Java 如何创建编码器？解码器？

一般来说，我对编程相当陌生，我想知道如何对输入的文本进行编码/解码

对于ex A->D，所有字母必须减少3个字母 B->E 诸如此类

我将输入一些伪代码作为示例：

输入消息：“LORYHBRX”

编码信息：LORYHBRX

解码信息：我爱你

输出消息：“我爱你”

请帮忙

到目前为止我有

import java.util.*;

public class Encoder {

public static void main(String[] args) 
{   

    String a = "d";
    String b = "e";
    String c = "f";
    String d = "g";
    String e = "h";
    String f = "i";
    String g = "j";
    String h = "k";
    String i = "l";
    String j = "m";
    String k = "n";
    String l = "o";
    String m = "p";
    String n = "q";
    String o = "r";
    String p = "s";
    String q = "t";
    String r = "u";
    String s = "v";
    String t = "w";
    String u = "x";
    String v = "y";
    String w = "z";
    String x = "a";
    String y = "b";
    String z = "c";

    Scanner in = new Scanner(System.in);
    System.out.println("Please enter the text you wish to encode.");
    String place = in.nextLine();
    System.out.println(place);

}
}

我正在尝试将输入的内容转换为上面的变量

---

我想我将所有这些字符串都声明为变量，但我不知道如何通过输入使它们可变。

我将给您一些提示，如何进行解码和编码将是相反的过程

首先，你们应该知道计算机只能理解被称为

Ascii码的数字

Ascii码是字符的数字表示，如
b
、
&
、
A
，等等，因此，大写字母和小写字母都有
Ascii码
，它是int类型


你应该知道的另一个主题是
Casting

强制转换是将一种类型转换为另一种类型，如将int转换为char或将int转换为char，但您应该知道强制转换某些类型无法转换为另一种类型，如将boolean转换为int，这是不可能的


让我们谈谈编码，把解码留给你们去弄清楚，因为它和编码是相反的

关于如何编码的提示

不需要像
String a=“a”
这样定义字符串
由于您了解了作为数字的Ascci代码，您可以使用强制转换在97到122之间进行for循环，以获得小字符

例如：

System.out.println("Asci code of small a is " + (int)'a' + "\nsmall a is " + (char)97);

输出：

Asci小a代码为97
小a是a

注意：您可以将char转换为int，并将int转换为char

因为你在处理数字，所以你可以做加法

例如：

System.out.println("Three char after a is " +  (char)(97+3));

输出：

a后面有个字符是d

对于字符x、y和z，您可以从其asci代码中减去23，例如，
120-23
将给出a的asci代码。
整个编码和解码代码

import java.util.Scanner;

public class coder {

    public static void main(String[] args) {
        String[] qe = {"1 ","2 ","3 ","4 ","5 ","6 ","7 ","8 ","9 ","10 ","11 ","12 ","13 ",
            "14 ","15 ","16 ","17 ","18 ","19 ","20 ","21 ","22 ","23 ","24 ","25 ","26 "};
        String [] eq = {"a","b","c","d","e","f","g","h","i","j","k","l","m","n","o",
                "p","q","r","s","t","u","v","w","x","y","z"};
        Scanner in = new Scanner(System.in);
        System.out.println("Please enter the text you wish to encode.");
        String place = in.nextLine();
        place = place.toLowerCase();
        place = place.replace("a", qe[0]);
        place = place.replace("b", qe[1]);
        place = place.replace("c", qe[2]);
        place = place.replace("d", qe[3]);
        place = place.replace("e", qe[4]);
        place = place.replace("f", qe[5]);
        place = place.replace("g", qe[6]);
        place = place.replace("h", qe[7]);
        place = place.replace("i", qe[8]);
        place = place.replace("j", qe[9]);
        place = place.replace("k", qe[10]);
        place = place.replace("l", qe[11]);
        place = place.replace("m", qe[12]);
        place = place.replace("n", qe[13]);
        place = place.replace("o", qe[14]);
        place = place.replace("p", qe[15]);
        place = place.replace("q", qe[16]);
        place = place.replace("r", qe[17]);
        place = place.replace("s", qe[18]);
        place = place.replace("t", qe[19]);
        place = place.replace("u", qe[20]);
        place = place.replace("v", qe[21]);
        place = place.replace("w", qe[22]);
        place = place.replace("x", qe[23]);
        place = place.replace("y", qe[24]);
        place = place.replace("z", qe[25]);
        System.out.println(place);

        place = place.replace("26 ", eq[25]);
        place = place.replace("25 ", eq[24]);
        place = place.replace("24 ", eq[23]);
        place = place.replace("23 ", eq[22]);
        place = place.replace("22 ", eq[21]);
        place = place.replace("21 ", eq[20]);
        place = place.replace("20 ", eq[19]);
        place = place.replace("19 ", eq[18]);
        place = place.replace("18 ", eq[17]);
        place = place.replace("17 ", eq[16]);
        place = place.replace("16 ", eq[15]);
        place = place.replace("15 ", eq[14]);
        place = place.replace("14 ", eq[13]);
        place = place.replace("13 ", eq[12]);
        place = place.replace("12 ", eq[11]);
        place = place.replace("11 ", eq[10]);
        place = place.replace("10 ", eq[9]);
        place = place.replace("9 ", eq[8]);
        place = place.replace("8 ", eq[7]);
        place = place.replace("7 ", eq[6]);
        place = place.replace("6 ", eq[5]);
        place = place.replace("5 ", eq[4]);
        place = place.replace("4 ", eq[3]);
        place = place.replace("3 ", eq[2]);
        place = place.replace("2 ", eq[1]);
        place = place.replace("1 ", eq[0]);
        System.out.println(place);
    }

}

从编写代码开始。当您遇到特定的代码问题时，可以发布问题。这是唯一的解决办法，我道歉。我把密码放进去了。啊！将目标字母表存储为
String a=“d”
对您没有帮助，因为您无法将字符串中的字母转换为变量名。您需要了解数组和其他容器类。对于手头的任务，编写一个函数，将源字母转换为目标字母。您可以利用这一事实，即26个字母构成ASCII中的一个连续块。顺便说一句，您需要的代码称为凯撒密码。搜索它和SO上的Java标记应该会给你提示如何攻击它。@StevenJobs loryhbrx不可能给你iloveyou，但iloveyou给你loryhbrx。如果是这样，请让我知道，这样我就可以发布我的答案：）