在Java中尝试获取以空格分隔的整数

我试图输入由空格分隔的整数，然后试图检索它们。就这么简单，但我做不到

所以我要做的是，首先问一个用户想要输入多少个数字，他/她会输入这个数字，然后输入中间有空格的数字。

在用户输入了用空格分隔的数字后，我只想把它们打印回来

拟议产出 这就是我所做的：-

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问题是您试图使用以下方法捕获所有五个逗号分隔的整数：

actualnumbers=myinput2.nextInt（）

实际上只读取一个

int

，在您的例子中，它是

1

您需要读取循环或字符串中的整数，可以在空格上拆分，然后打印数字。你们不需要两台扫描仪，就像我所说的那个样。似乎您希望在循环中执行此操作，然后使用以下方法：

public static void main(String[] args) {
        int amountofnumbers;
        int[] actualnumbers;

        Scanner myinput = new Scanner (System.in);
        System.out.println ("How many numbers do you want to enter?");
        amountofnumbers = myinput.nextInt();

        actualnumbers = new int[amountofnumbers];
        for(int index=0; index<amountofnumbers; index++)
        {
            System.out.println ("Please enter");
            actualnumbers[index] = myinput.nextInt();

        }
         myinput.close();
         System.out.println("You entered:");
        for(int enteredNumber : actualnumbers){
            System.out.println (enteredNumber) ;
        }
    }

publicstaticvoidmain（字符串[]args）{
整数；
int[]实际数字；
扫描仪myinput=新扫描仪（System.in）；
System.out.println（“要输入多少个数字？”）；
amountofnumbers=myinput.nextInt（）；
实际数=新整数[数量]；
对于（int index=0；index，您可以将数字数组的输入作为字符串，并使用split（）函数将其除以。然后，将其打印或插入int数组

public static void main( String[] argv ) throws Exception{

int amountofnumbers;

Scanner myinput = new Scanner(System.in);
Scanner myinput2 = new Scanner(System.in);

System.out.println("How many numbers do you want to enter?");
amountofnumbers = myinput.nextInt();

try {
    int[] numbers = new int[amountofnumbers];

    System.out.println("Please enter " + amountofnumbers + " integer(s) seperated by a space");
    String actualnumbers = myinput2.nextLine();

    String[] amounts = actualnumbers.split(" ", amountofnumbers);
    if (amounts.length != amountofnumbers) {
        System.err.println("No of input should be: " + amountofnumbers);
        return;
    }
    for (int i=0; i<amounts.length; i++) {
        numbers[i] = Integer.parseInt(amounts[i]);
    }
    System.out.println("You entered:- ");
    for (int i = 0; i < numbers.length ; i++)  { 
        System.out.println(numbers[i]);
    }
}
catch(NumberFormatException e) {
    System.err.println("Only integer can be input");
}
catch(ArrayIndexOutOfBoundsException e) {
    System.err.println("No of input should be: " + amountofnumbers);
}

myinput.close();
myinput2.close();
}

你能展示一下当你运行它时会发生什么吗？
String#split
？甚至可能是一个新的
扫描仪
环绕原始输入，并使用
扫描仪#hasNextInt
和
扫描仪#nextInt
…？你应该把
实际数字=myinput2.nextInt（）
进入循环，因为您正在读取多个数字。存储到数组中，稍后再打印出来。@Vinetramachandran是的，但是OP需要一次读取一行文本…您只读取一次输入，然后打印5次值。您可能需要一个数组和一个更好的for循环正如前面提到的，最好是r移除第二台扫描仪。最后也关闭第一台。谢谢，关闭扫描仪只是我一时想不起来。我想可能是OP需要两台扫描仪，原因不明。我已经更新了代码。
1
1
1
1
1

public static void main(String[] args) {
        int amountofnumbers;
        int[] actualnumbers;

        Scanner myinput = new Scanner (System.in);
        System.out.println ("How many numbers do you want to enter?");
        amountofnumbers = myinput.nextInt();

        actualnumbers = new int[amountofnumbers];
        for(int index=0; index<amountofnumbers; index++)
        {
            System.out.println ("Please enter");
            actualnumbers[index] = myinput.nextInt();

        }
         myinput.close();
         System.out.println("You entered:");
        for(int enteredNumber : actualnumbers){
            System.out.println (enteredNumber) ;
        }
    }

public static void main( String[] argv ) throws Exception{

int amountofnumbers;

Scanner myinput = new Scanner(System.in);
Scanner myinput2 = new Scanner(System.in);

System.out.println("How many numbers do you want to enter?");
amountofnumbers = myinput.nextInt();

try {
    int[] numbers = new int[amountofnumbers];

    System.out.println("Please enter " + amountofnumbers + " integer(s) seperated by a space");
    String actualnumbers = myinput2.nextLine();

    String[] amounts = actualnumbers.split(" ", amountofnumbers);
    if (amounts.length != amountofnumbers) {
        System.err.println("No of input should be: " + amountofnumbers);
        return;
    }
    for (int i=0; i<amounts.length; i++) {
        numbers[i] = Integer.parseInt(amounts[i]);
    }
    System.out.println("You entered:- ");
    for (int i = 0; i < numbers.length ; i++)  { 
        System.out.println(numbers[i]);
    }
}
catch(NumberFormatException e) {
    System.err.println("Only integer can be input");
}
catch(ArrayIndexOutOfBoundsException e) {
    System.err.println("No of input should be: " + amountofnumbers);
}

myinput.close();
myinput2.close();
}

How many numbers do you want to enter?
5
Please enter 5 integer(s) seperated by a space
1 2 3 4 5
You entered:- 
1
2
3
4
5