Java 将从程序接收的输入从int更改为string初学者
我写了一个模拟评分测验的程序,但是我想把我收到的输入从int改为string,这样我就可以输入a,b,c,d作为测验的答案。我该怎么做Java 将从程序接收的输入从int更改为string初学者,java,string,Java,String,我写了一个模拟评分测验的程序,但是我想把我收到的输入从int改为string,这样我就可以输入a,b,c,d作为测验的答案。我该怎么做 import java.util.Scanner; public class Quizzes1 { public static void main(String[] args) { int Questions; int answers; int Quizzes; int numOf
import java.util.Scanner;
public class Quizzes1
{
public static void main(String[] args)
{
int Questions;
int answers;
int Quizzes;
int numOfQs = 0;
String phrase= "";
Scanner scan = new Scanner(System.in);
System.out.println("How many questions are in the quizz?");
Questions = scan.nextInt();
char[] key = new char[numOfQs];
int[] canswers = new int[Questions];
for (int i=0; i<canswers.length; i++)
{
System.out.println("Please give the correct answers " + (i+1) + ": ");
canswers[i] = scan.nextInt();
}
while (!phrase.equals("n"))
{
double Correct = 0;
double Incorrect = 0;
for (int i=0; i<canswers.length; i++)
{
System.out.println("What are the answers that the students put");
answers = scan.nextInt();
if (answers == canswers[i])
Correct++;
else
Incorrect++;
}
System.out.println("There are " +Correct + " correct answers and " +Incorrect
+" incorrect answers");
double Percent = ((Correct / (Correct + Incorrect)) * 100);
System.out.println("The percentage correct is " +Percent +"%");
phrase = scan.nextLine();
System.out.println("Would you like to grade another quiz y/n");
phrase = scan.nextLine();
}
}
}
import java.util.Scanner;
公开课测验1
{
公共静态void main(字符串[]args)
{
智力问题;
int答案;
智力测验;
int numOfQs=0;
字符串短语=”;
扫描仪扫描=新扫描仪(System.in);
System.out.println(“测验中有多少问题?”);
问题=scan.nextInt();
char[]key=新字符[numofq];
int[]canswers=新int[问题];
对于(inti=0;i因为a、b、c和d是单字母,为什么不读字符而不是int或甚至字符串呢
试试看
scanner.nextLine().charAt(0);
使用字符,您仍然可以使用代码的这一部分:
if (answers == canswers[i])
Correct++;
else
Incorrect++;
}
这与dasblinkenligh的答案非常相似