Java 如何进行POST请求并从服务器获得响应？

我需要通过以下示例向服务器发送POST请求：

请求格式：

POST /oauth/authorize HTTP/1.1
Host: m.sp-money.yandex.ru (для мобильных устройств) или sp-money.yandex.ru (для остальных  устройств)
Content-Type: application/x-www-form-urlencoded
Content-Length: <content-length>

client_id=<client_id>&response_type=code
&redirect_uri=<redirect_uri>&scope=<scope>

REQUEST PARAMETERS EXAMPLE:

client_id=092763469236489593523464667
response_type=code
redirect_uri=https://client.example.com/cb
scope=account-info operation-history

---

在你的后台，你可以试试这样的东西

HttpClient client = new DefaultHttpClient();
            HttpPost post = new HttpPost(HTTP_REQUEST_URL);

            //create and assign post request server data
            String latitude = loc.getLatitude() + "";
            String longitude = loc.getLongitude() + "";
            String time = DateFormat.getDateTimeInstance().format(Calendar.getInstance().getTime()) + "";
            String whr = WhereAmI(loc.getLatitude(), loc.getLongitude());

            //data back from server
            String responseBackFromServer = "";

            try {
                List<NameValuePair> pairs = new ArrayList<NameValuePair>();

                pairs.add(new BasicNameValuePair("latitude", latitude));
                pairs.add(new BasicNameValuePair("longitude", longitude));
                pairs.add(new BasicNameValuePair("whereAmI", whr));
                pairs.add(new BasicNameValuePair("time", time));

                post.setEntity(new UrlEncodedFormEntity(pairs));
                HttpResponse server_response = client.execute(post);

                responseBackFromServer = EntityUtils.toString(server_response.getEntity());

            } catch (UnsupportedEncodingException e) {
                e.printStackTrace();
            } catch (IOException e) {
                e.printStackTrace();
            } catch (Exception e) {
                e.printStackTrace();
            }

            return "Response Back: " + responseBackFromServer;

---

在onPostExecute中，您可以对响应执行任何操作。

OK。我是否可以传输头等参数？post.addHeader一些名称，一些名称值；这应该行得通。

HTTP/1.1 302 Found
Location: https://client.example.com/cb?code=i1WsRn1uB1ehfbb37

HttpClient client = new DefaultHttpClient();
            HttpPost post = new HttpPost(HTTP_REQUEST_URL);

            //create and assign post request server data
            String latitude = loc.getLatitude() + "";
            String longitude = loc.getLongitude() + "";
            String time = DateFormat.getDateTimeInstance().format(Calendar.getInstance().getTime()) + "";
            String whr = WhereAmI(loc.getLatitude(), loc.getLongitude());

            //data back from server
            String responseBackFromServer = "";

            try {
                List<NameValuePair> pairs = new ArrayList<NameValuePair>();

                pairs.add(new BasicNameValuePair("latitude", latitude));
                pairs.add(new BasicNameValuePair("longitude", longitude));
                pairs.add(new BasicNameValuePair("whereAmI", whr));
                pairs.add(new BasicNameValuePair("time", time));

                post.setEntity(new UrlEncodedFormEntity(pairs));
                HttpResponse server_response = client.execute(post);

                responseBackFromServer = EntityUtils.toString(server_response.getEntity());

            } catch (UnsupportedEncodingException e) {
                e.printStackTrace();
            } catch (IOException e) {
                e.printStackTrace();
            } catch (Exception e) {
                e.printStackTrace();
            }

            return "Response Back: " + responseBackFromServer;