Java 无法获取捕获的图像uri

我正在尝试获取捕获的图像Uri，但没有获取下面的代码来说明如何获取Uri。Toast消息给我空结果

 Button b=findViewById(R.id.button);
    b.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            Intent i=new Intent(MediaStore.ACTION_IMAGE_CAPTURE);
            startActivityForResult(i,2);
        }
    });
}

@Override
protected void onActivityResult(int requestCode, int resultCode, @Nullable Intent data) {
    super.onActivityResult(requestCode, resultCode, data);
    Toast.makeText(Authentication.this,""+data.getData(),Toast.LENGTH_LONG).show();
}

试试这个：

if (requestCode == CAPTURE_IMAGE && 
                              resultCode == RESULT_OK) {
        if (data != null) {
        Bitmap bitmap = (Bitmap) data.getExtras().get("data");

        Uri imageUri = getImageUri(getApplicationContext(), bitmap);
        }
    }

调用此方法以获取uri fom位图：

public Uri getImageUri(Context inContext, Bitmap myImage) {
    ByteArrayOutputStream bytes = new ByteArrayOutputStream();
    myImage.compress(Bitmap.CompressFormat.JPEG, 100, bytes);
    String path = Images.Media.insertImage(inContext.getContentResolver(), 
    myImage, "Title", null);
    return Uri.parse(path);
}

试试这个：

if (requestCode == CAPTURE_IMAGE && 
                              resultCode == RESULT_OK) {
        if (data != null) {
        Bitmap bitmap = (Bitmap) data.getExtras().get("data");

        Uri imageUri = getImageUri(getApplicationContext(), bitmap);
        }
    }

调用此方法以获取uri fom位图：

public Uri getImageUri(Context inContext, Bitmap myImage) {
    ByteArrayOutputStream bytes = new ByteArrayOutputStream();
    myImage.compress(Bitmap.CompressFormat.JPEG, 100, bytes);
    String path = Images.Media.insertImage(inContext.getContentResolver(), 
    myImage, "Title", null);
    return Uri.parse(path);
}

---

从Android版本的棒棒糖中，出于安全原因，无法直接获取URI-

    private static Uri getSharableImageUri(Context context) {
File outputDir = context.getCacheDir();
File imagePath = new File(outputDir, context.getString(R.string.app_name));
if (!imagePath.exists()) {
    imagePath.mkdir();
}
File tempFile = new File(imagePath, "image.jpg");
Uri uri = null;
try {
    if (!tempFile.exists()) {
        tempFile.createNewFile();
    }
    uri = FileProvider.getUriForFile(context, context.getPackageName() + ".fileprovider", tempFile);
} catch (Exception e) {
    e.printStackTrace();
}
return uri;
}

在按钮的“单击侦听器”中使用-

     Button b=findViewById(R.id.button);
b.setOnClickListener(new View.OnClickListener() {
    @Override
    public void onClick(View v) {
       Intent intent = new Intent(MediaStore.ACTION_IMAGE_CAPTURE);
try {
    String state = Environment.getExternalStorageState();
    if (Environment.MEDIA_MOUNTED.equals(state)) {

        mImageCaptureUri = getSharableImageUri(context);
    }
    if (Build.VERSION.SDK_INT <= Build.VERSION_CODES.LOLLIPOP) {
        intent.setClipData(ClipData.newRawUri("", mImageCaptureUri));

    }
    intent.addFlags(Intent.FLAG_GRANT_READ_URI_PERMISSION);
    intent.putExtra(MediaStore.EXTRA_OUTPUT, mImageCaptureUri);
    intent.putExtra("return-data", true);
    startActivityForResult(intent, 2);

} catch (Exception e) {
   e.printStackTrace();
}
    }
});

---

从Android版本的棒棒糖中，出于安全原因，无法直接获取URI-

    private static Uri getSharableImageUri(Context context) {
File outputDir = context.getCacheDir();
File imagePath = new File(outputDir, context.getString(R.string.app_name));
if (!imagePath.exists()) {
    imagePath.mkdir();
}
File tempFile = new File(imagePath, "image.jpg");
Uri uri = null;
try {
    if (!tempFile.exists()) {
        tempFile.createNewFile();
    }
    uri = FileProvider.getUriForFile(context, context.getPackageName() + ".fileprovider", tempFile);
} catch (Exception e) {
    e.printStackTrace();
}
return uri;
}

在按钮的“单击侦听器”中使用-

     Button b=findViewById(R.id.button);
b.setOnClickListener(new View.OnClickListener() {
    @Override
    public void onClick(View v) {
       Intent intent = new Intent(MediaStore.ACTION_IMAGE_CAPTURE);
try {
    String state = Environment.getExternalStorageState();
    if (Environment.MEDIA_MOUNTED.equals(state)) {

        mImageCaptureUri = getSharableImageUri(context);
    }
    if (Build.VERSION.SDK_INT <= Build.VERSION_CODES.LOLLIPOP) {
        intent.setClipData(ClipData.newRawUri("", mImageCaptureUri));

    }
    intent.addFlags(Intent.FLAG_GRANT_READ_URI_PERMISSION);
    intent.putExtra(MediaStore.EXTRA_OUTPUT, mImageCaptureUri);
    intent.putExtra("return-data", true);
    startActivityForResult(intent, 2);

} catch (Exception e) {
   e.printStackTrace();
}
    }
});

---

您将无法获得uri。通过这种方式，您将获得具有此目的的位图。@aj pawar。我想你需要检查一下这个答案。blackapps是对的，你在讨论中提到的代码会给你位图，你不会得到uri。通过这种方式，您将获得具有此目的的位图。@aj pawar。我想你需要检查一下这个答案。blackapps是对的，您刚才提到的代码将为您提供位图，但是先生，我想在我们需要的时候将图像存储到firebase_存储中Uri@AjPawar您需要文件提供程序。然后你可以获取文件uri并上传到firebase存储。但先生，我想在我们需要的时候将图像存储到firebase_存储Uri@AjPawar您需要文件提供程序。然后您可以获取文件uri并上传到firebase存储。