Java 在不使用主键的情况下使用hibernate获取数据库记录

我想为我创建的表从数据库中获取不带主键的记录。这是它的模型类

@Entity
@Table(name = "DOCTORS_INFORMATION")
 public class DoctorInformation {

@Id
@GeneratedValue(strategy = GenerationType.AUTO)
@Column(name = "DOCTOR_ID")
private int ID;

@Column(name = "FIRST_NAME")
private String firstName;

@Column(name = "LAST_NAME")
private String lastName;

@Column(name = "ADDRESS_LINE1")
private String addressLine1;

@ManyToOne(cascade = CascadeType.ALL)
@JoinColumn(name = "CITY")
private Location location;
//along with setters and getters

很难记住每个医生的医生Id，从逻辑上讲，名字或任何东西都不能成为主键。我看过的所有教程和讲座视频都使用session.get获取记录，其中session是课堂会话的对象。在Session类的源代码中，

get

mandatory的所有重载方法都将id作为参数。。。

---

它们是解决上述问题的方法吗？

有多种选择。以下所有示例都搜索姓氏包含约翰逊的医生

标准

String lastNameToSearchFor = "Johnson";
List doctors = session.createCriteria(DoctorInformation.class)
     .add( Restrictions.like("lastName", "%"+lastNameToSearchFor+"%") ) // the leading wild card can become a problem since it cannot be indexed by the DB!
     .addOrder( Order.asc("lastName") )
     .list();

HQL

String lastNameToSearchFor = "Johnson";
String hql = "FROM " + DoctorInformation.class.getName() + " di WHERE di.lastName LIKE :lastName ORDER BY di.lastName ASC";
Query query = session.createQuery(hql);
query.setParameter("lastName", "%" + lastNameToSearchFor + "%"); // again, the leading wild card may be a problem
List doctors = query.list();

String lastNameToSearchFor = "Johnson";
String sql = "SELECT * FROM DOCTORS_INFORMATION WHERE lastName LIKE :lastName ORDER BY lastName ASC";
Query query = session.createSQLQuery(sql).addEntity(DoctorInformation.class);
query.setString("lastName", "%" + lastNameToSearchFor + "%"); // again, the leading wild card may be a problem
List doctors = query.list();

本机SQL

String lastNameToSearchFor = "Johnson";
String hql = "FROM " + DoctorInformation.class.getName() + " di WHERE di.lastName LIKE :lastName ORDER BY di.lastName ASC";
Query query = session.createQuery(hql);
query.setParameter("lastName", "%" + lastNameToSearchFor + "%"); // again, the leading wild card may be a problem
List doctors = query.list();

String lastNameToSearchFor = "Johnson";
String sql = "SELECT * FROM DOCTORS_INFORMATION WHERE lastName LIKE :lastName ORDER BY lastName ASC";
Query query = session.createSQLQuery(sql).addEntity(DoctorInformation.class);
query.setString("lastName", "%" + lastNameToSearchFor + "%"); // again, the leading wild card may be a problem
List doctors = query.list();

---

如果您想添加搜索功能，比如firstName，那么您可能需要研究Hibernate的析取：

有多个选项。以下所有示例都搜索姓氏包含约翰逊的医生

标准

String lastNameToSearchFor = "Johnson";
List doctors = session.createCriteria(DoctorInformation.class)
     .add( Restrictions.like("lastName", "%"+lastNameToSearchFor+"%") ) // the leading wild card can become a problem since it cannot be indexed by the DB!
     .addOrder( Order.asc("lastName") )
     .list();

HQL

String lastNameToSearchFor = "Johnson";
String hql = "FROM " + DoctorInformation.class.getName() + " di WHERE di.lastName LIKE :lastName ORDER BY di.lastName ASC";
Query query = session.createQuery(hql);
query.setParameter("lastName", "%" + lastNameToSearchFor + "%"); // again, the leading wild card may be a problem
List doctors = query.list();

String lastNameToSearchFor = "Johnson";
String sql = "SELECT * FROM DOCTORS_INFORMATION WHERE lastName LIKE :lastName ORDER BY lastName ASC";
Query query = session.createSQLQuery(sql).addEntity(DoctorInformation.class);
query.setString("lastName", "%" + lastNameToSearchFor + "%"); // again, the leading wild card may be a problem
List doctors = query.list();

本机SQL

String lastNameToSearchFor = "Johnson";
String hql = "FROM " + DoctorInformation.class.getName() + " di WHERE di.lastName LIKE :lastName ORDER BY di.lastName ASC";
Query query = session.createQuery(hql);
query.setParameter("lastName", "%" + lastNameToSearchFor + "%"); // again, the leading wild card may be a problem
List doctors = query.list();

String lastNameToSearchFor = "Johnson";
String sql = "SELECT * FROM DOCTORS_INFORMATION WHERE lastName LIKE :lastName ORDER BY lastName ASC";
Query query = session.createSQLQuery(sql).addEntity(DoctorInformation.class);
query.setString("lastName", "%" + lastNameToSearchFor + "%"); // again, the leading wild card may be a problem
List doctors = query.list();

---

如果您想添加搜索功能，比如firstName，那么您可能需要研究Hibernate的析取：

DAO的代码在哪里？为什么不使用HQL？DAO的代码在哪里？为什么不使用HQL？我不知道HQL，谢谢！我不知道HQL，谢谢！