Java 如何将yyy/MM/ss hh:MM:ss转换为秒？
导言 我正试图得到两个时代的秒差 i、 e 2019-05-22 18:28:56->1558542536秒 2019-07-22 19:00:00->1563814800秒 差值为：5272264 秒 此日期格式以字符串形式来自二进制文件 我的代码Java 如何将yyy/MM/ss hh:MM:ss转换为秒？,java,date,format,epoch,seconds,Java,Date,Format,Epoch,Seconds,导言 我正试图得到两个时代的秒差 i、 e 2019-05-22 18:28:56->1558542536秒 2019-07-22 19:00:00->1563814800秒 差值为：5272264 秒 此日期格式以字符串形式来自二进制文件 我的代码 public static void main(String[] args) throws ParseException { String regEpoch = ""; long result = 0; //System
public static void main(String[] args) throws ParseException
{
String regEpoch = "";
long result = 0;
//System.out.println((fecha = dateFormat.format(date)));
try(RandomAccessFile raf = new RandomAccessFile("binario2.txt", "rw")){
//user inputs a code (for now, doesn't matter if exists or not)
System.out.print("Input a code to look for: ");
String code = scan.next();
while(!code.matches("\\d+"))
{
System.out.println("[ERROR] Only digits accepted");
System.out.print("Input a code to look for: ");
code = scan.next();
}
//Gets the current date in seconds
long getSecs = (new Date().getTime())/1000;
System.out.println("Current tiem in secs: " + getSecs);
//We are "randomly accessing" a binary file. The is no problem here at all. It just works.
//Sets the pointer where I want it, again... this works fine.
raf.seek(27+(80*Integer.parseInt(code)));
//Read the String date correctly, which is 2019-05-22 18:28:56
System.out.println(raf.readUTF());
/*
//Attempt 2
System.out.println(java.time.Instant.ofEpochSecond(Long.parseLong(raf.readUTF())));
Long millis = new SimpleDateFormat("yyyy/MM/ss hh:mm:ss").parse(raf.readUTF()).getTime();
System.out.println(millis);
*/
//Let's try to convert it into seconds... No we can't due to -> Unparseable date: "2019-05-22 18:28:56"
Date dt = dateFormat.parse(raf.readUTF());
long epoch = dt.getTime();
System.out.println("Result is: " + (int)(epoch*1000));
}catch(IOException e){System.out.println("[ERROR] " + e);}
}
- 我必须手动操作吗
- 有没有我没听说过的图书馆
hh:mm:ssChronoUnitpackage test;
import java.text.ParseException;
import java.time.LocalDateTime;
import java.time.temporal.ChronoUnit;
public class Test2 {
public static void main(String[] args) throws ParseException {
LocalDateTime date1 = LocalDateTime.parse("2019-05-22T18:58:56");
LocalDateTime date2 = LocalDateTime.parse("2019-05-23T19:00:00"); //LocalDateTime.now();
long seconds = ChronoUnit.SECONDS.between(date1, date2);
System.out.println(seconds);
}
}
new SimpleDateFormat("yyyy-MM-dd HH:mm:ss").parse("2019-05-22 18:28:56").getTime();
持续时间持续时间LocalDateTime ldtStart = LocalDateTime.parse( "2019-05-22 18:28:56".replace( " " , "T" ) ) ;
ZoneId z = ZoneId.of( "America/Montreal" ) ;
ZonedDateTime zdtStart = ldtStart.atZone( z ) ;
Duration d = Duration.between( zdtStart , zdtStop ) ;
long seconds = d.toSeconds() ; // Or `getSeconds` before Java 9.
long hours = d.toHours() ;
提示：您的格式是
HHHHSimpleDataFormatLocalDateTimeZonedDateTimeDateTimeFormatterZonedDateTime“2019-05-22 18:28:56”1556728136“2019年5月1日星期三18:28:56（pm）”