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Java 未调用Spring MVC控制器_Java_Spring_Servlets_Model View Controller_Controller - Fatal编程技术网

Java 未调用Spring MVC控制器

Java 未调用Spring MVC控制器,java,spring,servlets,model-view-controller,controller,Java,Spring,Servlets,Model View Controller,Controller,项目结构如下图所示: web.xml如下所示: <?xml version="1.0" encoding="UTF-8"?> <web-app xmlns="http://xmlns.jcp.org/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javae

项目结构如下图所示:

web.xml如下所示:

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns="http://xmlns.jcp.org/xml/ns/javaee"
         xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
         xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd"
         version="3.1">
  <display-name>Archetype Created Web Application</display-name>

  <servlet>
    <servlet-name>mvc</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <load-on-startup>1</load-on-startup>
  </servlet>
  <servlet-mapping>
    <servlet-name>mvc</servlet-name>
    <url-pattern>/mvc</url-pattern>
  </servlet-mapping>

  <context-param>
    <param-name>contextClass</param-name>
    <param-value>
      org.springframework.web.context.support.AnnotationConfigWebApplicationContext
    </param-value>
  </context-param>
  <context-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>/webapp.WEB-INF/mvc-servlet.xml</param-value>
  </context-param>
  <listener>
    <listener-class>
      org.springframework.web.context.ContextLoaderListener
    </listener-class>
  </listener>
</web-app>
名为“home”的jsp只是一些随机html

但是,当我尝试访问url时

我得到以下错误:


我使用了调试器,甚至没有调用控制器中的方法。因此,spring配置存在问题。我在互联网上搜索了很多次,我的想法都没有了。如果有任何帮助,我将不胜感激。

将web.xml文件中org.springframework.web.servlet.DispatcherServlet的url模式中的/mvc改为/mvc/*
这将使所有带有/mvc/*模式的uri路由到spring dispatcher,然后再路由到您的servlet

尝试使用此url访问hello servlet。我相信这会有帮助的war文件名为“CatalogFacultate”。在Tomcat内的webapps文件夹中,我还有根webapp。所以我使用的URL是正确的。尝试了一下,没有结果。
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xmlns:mvc="http://www.springframework.org/schema/mvc"
       xmlns:context="http://www.springframework.org/schema/context"
       xsi:schemaLocation="http://www.springframework.org/schema/beans
        http://www.springframework.org/schema/beans/spring-beans-3.2.xsd
        http://www.springframework.org/schema/mvc
        http://www.springframework.org/schema/mvc/spring-mvc-3.2.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd">

    <context:component-scan base-package="main.java.controller"/>
    <mvc:annotation-driven />

    <bean id="viewResolver"
          class="org.springframework.web.servlet.view.InternalResourceViewResolver">
        <property name="prefix" value="/webapp.WEB-INF/view/" />
        <property name="suffix" value=".jsp" />
    </bean>

</beans>
package main.java.controller;

import org.springframework.stereotype.Controller;
import org.springframework.ui.Model;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;

@Controller
public class HomePageController {

    @RequestMapping(value="/home", method= RequestMethod.GET)
    public String hello(){
        return "homepage";
    }

}