Java 迭代ExecutionResult返回关系

我使用上面的查询来获取两个节点之间的所有路径。如何迭代返回的关系

我是用下面的方法做的，上面的链接很有帮助

最终迭代器rels=eResult.columnAs（“p”）

while（rels.hasNext（））{
路径路径=rels.next（）；
Iterable relationships=path.relationships（）；
java.util.Iterator relIterator=relationships.Iterator（）；
while（relIterator.hasNext（））{
关系rel=relIterator.next（）；
字符串阳极=（字符串）rel.getStartNode（）.getProperty（“名称”）；
字符串zNode=（字符串）rel.getEndNode（）.getProperty（“名称”）；
长值=（长）相对getProperty（“值”）；
System.out.println（阳极+”连接到“+zNode+”，值为“+value”）；
}
}

---

您只需

将rels（p）返回为rels

即可返回关系。或

节点（p）

ftm

如果您只是对路径节点的名称感兴趣，请使用extract

while (rels.hasNext()){ Path path = rels.next(); Iterable<Relationship> relationships = path.relationships(); java.util.Iterator<Relationship> relIterator = relationships.iterator(); while (relIterator.hasNext()){ Relationship rel = relIterator.next(); String aNode = (String) rel.getStartNode().getProperty("name"); String zNode = (String) rel.getEndNode().getProperty("name"); Long value = (Long) rel.getProperty("value"); System.out.println(aNode +" is connected to "+zNode + " with value "+value); } } </code> while (rels.hasNext()){ Path path = rels.next(); Iterable<Relationship> relationships = path.relationships(); java.util.Iterator<Relationship> relIterator = relationships.iterator(); while (relIterator.hasNext()){ Relationship rel = relIterator.next(); String aNode = (String) rel.getStartNode().getProperty("name"); String zNode = (String) rel.getEndNode().getProperty("name"); Long value = (Long) rel.getProperty("value"); System.out.println(aNode +" is connected to "+zNode + " with value "+value); } } </code>

return extract(n in nodes(p) : n.name) as names