Java 如何在Android中合并两个JSON数组?
我有一个JSON响应,如下所示:Java 如何在Android中合并两个JSON数组?,java,android,json,gson,Java,Android,Json,Gson,我有一个JSON响应,如下所示: [{"ProjectID":1,"ProjectName":"Test","UserID":[1,3,5,7],"RSID":[2,4,6,8]}] [{"ProjectID":1,"ProjectName":"Test","RS":[{"UserID":1,"RSID":2},{"UserID":3,"RSID":4},{"UserID":5,"RSID":6},{"UserID":7,"RSID":8} ]}] 但我需要像这样合并它: [{"Projec
[{"ProjectID":1,"ProjectName":"Test","UserID":[1,3,5,7],"RSID":[2,4,6,8]}]
[{"ProjectID":1,"ProjectName":"Test","RS":[{"UserID":1,"RSID":2},{"UserID":3,"RSID":4},{"UserID":5,"RSID":6},{"UserID":7,"RSID":8}
]}]
但我需要像这样合并它:
[{"ProjectID":1,"ProjectName":"Test","UserID":[1,3,5,7],"RSID":[2,4,6,8]}]
[{"ProjectID":1,"ProjectName":"Test","RS":[{"UserID":1,"RSID":2},{"UserID":3,"RSID":4},{"UserID":5,"RSID":6},{"UserID":7,"RSID":8}
]}]
这有可能做到吗?没有直接的方法可以做到这一点,您只需要阅读json并自己完成逻辑 您可以使用:来检查JSON结构,因此:
jsonArray = getJSONArray(response.toString()) // the full response;
jsonObject = jsonArray.getJSONObject(0);
String myProjectID = jsonObject.getString("ProjectID");
String myProjectName=jsonObject.getString("ProjectName");
/* userIdArray = jsonObject .getJSONArray("UserID");
for (int i = 0; i < userIdArray .length(); i++)
{
//javaArray pushing values JSONObject jsonO = userIdArray .getJSONObject(i);
}
rsIdArray = jsonObject.getJSONArray("RSID");
for (int i = 0; i < rsIdArray .length(); i++)
{
}*/
我还没有测试过它,但是像这样的东西应该可以做到。没有直接的方法可以做到这一点,你只需要阅读json并自己完成逻辑
i tried to solve your query in plain javascript. hope it helps you.
您可以使用:来检查JSON结构,因此:
jsonArray = getJSONArray(response.toString()) // the full response;
jsonObject = jsonArray.getJSONObject(0);
String myProjectID = jsonObject.getString("ProjectID");
String myProjectName=jsonObject.getString("ProjectName");
/* userIdArray = jsonObject .getJSONArray("UserID");
for (int i = 0; i < userIdArray .length(); i++)
{
//javaArray pushing values JSONObject jsonO = userIdArray .getJSONObject(i);
}
rsIdArray = jsonObject.getJSONArray("RSID");
for (int i = 0; i < rsIdArray .length(); i++)
{
}*/
我还没有测试过它,但是像这样的东西应该可以奏效
i tried to solve your query in plain javascript. hope it helps you.
下面的代码将使用Java执行相同的任务:
JSONParser parser = new JSONParser();
String oldJSON = "[{\"ProjectID\":1,\"ProjectName\":\"Test\",\"UserID\":[1,3,5,7],\"RSID\":[2,4,6,8]}]";
JSONObject newJSON = new JSONObject();
Object obj = parser.parse(oldJSON);
JSONArray mainArray = (JSONArray) obj;
JSONObject objects = (JSONObject) mainArray.get(0);
newJSON.put("ProjectID", objects.get("ProjectID"));
newJSON.put("ProjectName", objects.get("ProjectName"));
JSONArray userId = (JSONArray) objects.get("UserID");
JSONArray rsid = (JSONArray) objects.get("RSID");
JSONArray newArr = new JSONArray();
for (int i = 0; i < userId.size(); i++) {
JSONObject combine = new JSONObject();
System.out.println("inside array" + userId.get(i));
combine.put("UserID", userId.get(i));
combine.put("RSID", rsid.get(i));
newArr.add(combine);
}
newJSON.put("RS", newArr);
System.out.println("json" + newJSON.toJSONString());
JSONParser=newjsonparser();
字符串oldJSON=“[{\“ProjectID\”:1,“ProjectName\”:“Test\”,“UserID\”:[1,3,5,7],“RSID\”:[2,4,6,8]}];
JSONObject newJSON=新JSONObject();
objectobj=parser.parse(oldJSON);
JSONArray mainArray=(JSONArray)obj;
JSONObject对象=(JSONObject)mainArray.get(0);
newJSON.put(“ProjectID”),objects.get(“ProjectID”);
newJSON.put(“ProjectName”,objects.get(“ProjectName”);
JSONArray userId=(JSONArray)objects.get(“userId”);
JSONArray rsid=(JSONArray)objects.get(“rsid”);
JSONArray newArr=新的JSONArray();
对于(int i=0;i
下面的代码将使用Java执行相同的任务:
JSONParser parser = new JSONParser();
String oldJSON = "[{\"ProjectID\":1,\"ProjectName\":\"Test\",\"UserID\":[1,3,5,7],\"RSID\":[2,4,6,8]}]";
JSONObject newJSON = new JSONObject();
Object obj = parser.parse(oldJSON);
JSONArray mainArray = (JSONArray) obj;
JSONObject objects = (JSONObject) mainArray.get(0);
newJSON.put("ProjectID", objects.get("ProjectID"));
newJSON.put("ProjectName", objects.get("ProjectName"));
JSONArray userId = (JSONArray) objects.get("UserID");
JSONArray rsid = (JSONArray) objects.get("RSID");
JSONArray newArr = new JSONArray();
for (int i = 0; i < userId.size(); i++) {
JSONObject combine = new JSONObject();
System.out.println("inside array" + userId.get(i));
combine.put("UserID", userId.get(i));
combine.put("RSID", rsid.get(i));
newArr.add(combine);
}
newJSON.put("RS", newArr);
System.out.println("json" + newJSON.toJSONString());
JSONParser=newjsonparser();
字符串oldJSON=“[{\“ProjectID\”:1,“ProjectName\”:“Test\”,“UserID\”:[1,3,5,7],“RSID\”:[2,4,6,8]}];
JSONObject newJSON=新JSONObject();
objectobj=parser.parse(oldJSON);
JSONArray mainArray=(JSONArray)obj;
JSONObject对象=(JSONObject)mainArray.get(0);
newJSON.put(“ProjectID”),objects.get(“ProjectID”);
newJSON.put(“ProjectName”,objects.get(“ProjectName”);
JSONArray userId=(JSONArray)objects.get(“userId”);
JSONArray rsid=(JSONArray)objects.get(“rsid”);
JSONArray newArr=新的JSONArray();
对于(int i=0;i
在重构现有json对象时,没有直接的方法合并json。处理json并设置如下值
var myObj = {"ProjectID":1,"ProjectName":"Test","UserID":[1,3,5,7],"RSID":[2,4,6,8]}
var myArray = [];
var RS = {};
var rsuserObj ={};
for(var key in myObj.UserID){
rsuserObj["userID"] = myObj.UserID[key];
rsuserObj["RSID"] = myObj.RSID[key];
myArray.push(rsuserObj);
}
var updatedObj = {"ProjectID":1,"ProjectName":"Test", "RS": myArray};
console.log(JSON.stringify(updatedObj));
在重构现有json对象时,没有直接的方法合并json。处理json并设置如下值
var myObj = {"ProjectID":1,"ProjectName":"Test","UserID":[1,3,5,7],"RSID":[2,4,6,8]}
var myArray = [];
var RS = {};
var rsuserObj ={};
for(var key in myObj.UserID){
rsuserObj["userID"] = myObj.UserID[key];
rsuserObj["RSID"] = myObj.RSID[key];
myArray.push(rsuserObj);
}
var updatedObj = {"ProjectID":1,"ProjectName":"Test", "RS": myArray};
console.log(JSON.stringify(updatedObj));
试试下面的代码
try {
String json1 = "[{\"ProjectID\":1,\"ProjectName\":\"Test\",\"UserID\":[1,3,5,7],\"RSID\":[2,4,6,8]}]";
JSONArray jsonArray1 = new JSONArray(json1);
JSONObject jsonObject = jsonArray1.optJSONObject(0);
String key1 = "UserID";
String key2 = "RSID";
String keyFinal = "RS";
JSONArray userIDArray = jsonObject.optJSONArray("UserID");
JSONArray rsIDArray = jsonObject.optJSONArray(key2);
jsonObject.remove(key1);
jsonObject.remove(key2);
int index = 0;
JSONArray rsFinalArray = new JSONArray();
if (userIDArray.length() > rsIDArray.length()) {
index = userIDArray.length();
} else {
index = rsIDArray.length();
}
for (int i = 0; i < index; i++) {
JSONObject rsObject = new JSONObject();
rsObject.accumulate(key1, userIDArray.opt(i));
rsObject.accumulate(key2, rsIDArray.opt(i));
rsFinalArray.put(rsObject);
}
jsonObject.accumulate(keyFinal, rsFinalArray);
JSONArray jsonArrayFinal = new JSONArray();
jsonArrayFinal.put(jsonObject);
Log.v("TAG", "result :" + jsonArrayFinal.toString());
} catch (Exception e) {
e.printStackTrace();
}
试试看{
字符串json1=“[{\“ProjectID\”:1,“ProjectName\”:“Test\”,“UserID\”:[1,3,5,7],“RSID\”:[2,4,6,8]}];
JSONArray jsonArray1=新JSONArray(json1);
JSONObject JSONObject=jsonArray1.optJSONObject(0);
字符串key1=“UserID”;
字符串key2=“RSID”;
字符串keyFinal=“RS”;
JSONArray userIDArray=jsonObject.optJSONArray(“UserID”);
JSONArray rsIDArray=jsonObject.optJSONArray(键2);
jsonObject.remove(键1);
jsonObject.remove(键2);
int指数=0;
JSONArray rsFinalArray=新的JSONArray();
if(userIDArray.length()>rsIDArray.length()){
index=userIDArray.length();
}否则{
索引=rsIDArray.length();
}
对于(int i=0;i
尝试下面的代码
try {
String json1 = "[{\"ProjectID\":1,\"ProjectName\":\"Test\",\"UserID\":[1,3,5,7],\"RSID\":[2,4,6,8]}]";
JSONArray jsonArray1 = new JSONArray(json1);
JSONObject jsonObject = jsonArray1.optJSONObject(0);
String key1 = "UserID";
String key2 = "RSID";
String keyFinal = "RS";
JSONArray userIDArray = jsonObject.optJSONArray("UserID");
JSONArray rsIDArray = jsonObject.optJSONArray(key2);
jsonObject.remove(key1);
jsonObject.remove(key2);
int index = 0;
JSONArray rsFinalArray = new JSONArray();
if (userIDArray.length() > rsIDArray.length()) {
index = userIDArray.length();
} else {
index = rsIDArray.length();
}
for (int i = 0; i < index; i++) {
JSONObject rsObject = new JSONObject();
rsObject.accumulate(key1, userIDArray.opt(i));
rsObject.accumulate(key2, rsIDArray.opt(i));
rsFinalArray.put(rsObject);
}
jsonObject.accumulate(keyFinal, rsFinalArray);
JSONArray jsonArrayFinal = new JSONArray();
jsonArrayFinal.put(jsonObject);
Log.v("TAG", "result :" + jsonArrayFinal.toString());
} catch (Exception e) {
e.printStackTrace();
}
试试看{
字符串json1=“[{\“ProjectID\”:1,“ProjectName\”:“Test\”,“UserID\”:[1,3,5,7],“RSID\”:[2,4,6,8]}];
JSONArray jsonArray1=新JSONArray(json1);
JSONObject JSONObject=jsonArray1.optJSONObject(0);
字符串key1=“UserID”;
字符串key2=“RSID”;
字符串keyFinal=“RS”;
JSONArray userIDArray=jsonObject.optJSONArray(“UserID”);
JSONArray rsIDArray=jsonObject.optJSONArray(键2);
jsonObject.remove(键1);
jsonObject.remove(键2);
int指数=0;
JSONArray rsFinalArray=新的JSONArray();
if(userIDArray.length()>rsIDArray.length()){
index=userIDArray.length();
}否则{
索引=rsIDArray.length();
}
对于(int i=0;i
解析收到的响应JSON并创建您选择的新JSON。如何执行@monishkamble解析收到的响应JSON并创建您选择的新JSON。如何执行@MonishKambleam已使用for循环进行解析我是否需要在循环中使用两个for循环?是这样吗?有时我会得到无穷的循环