Java评分法

Java评分法,java,string,loops,Java,String,Loops,目前仍停留在确定某个国家的最高分数的程序上。我面临的问题是如何通过用户的输入确定得分最高的国家。主要关注的是输出得分最高的国家和它获得的奖牌(前美国获得2金1银1铜)。我只关心美国的自动取款机方法。我对我关心的领域发表了一些评论 import java.util.Scanner; class OlympicMedalsEM { public static void main (String[] args) { Scanner kb = new Scanner(System.in);

目前仍停留在确定某个国家的最高分数的程序上。我面临的问题是如何通过用户的输入确定得分最高的国家。主要关注的是输出得分最高的国家和它获得的奖牌(前美国获得2金1银1铜)。我只关心美国的自动取款机方法。我对我关心的领域发表了一些评论

import java.util.Scanner;
class OlympicMedalsEM
{
public static void main (String[] args)
{
    Scanner kb = new Scanner(System.in);
    int winner=0;
    String countrywin;
    int gold=0, silver=0, bronze=0, count=0, num=0, sum=0;      //num as in the number of countries
    int goldscore=0, silverscore=0, bronzescore=0;
    String country;
    {
    System.out.println("Please choose a scoring method. a for American or c for Canadian. ");
    char again = kb.next().charAt(0);
        if(again == 'a')//american method
        {
            // American method counts the medals with the most score. ex: gold is worth 3, silver 2, and bronze 1.
            // USA win 3 gold 1 silver 0 bronze = 11 points so to speak.
            {
            System.out.println("Enter the number of countries competing: ");
            num = kb.nextInt();
            {
            for (int x=0; x < num; x++)
                {
                System.out.println("Enter country and medal count(from gold to bronze): ");
                country = kb.next();
                gold = kb.nextInt();
                silver = kb.nextInt();
                bronze = kb.nextInt();
                country += country; // not sure if for loops works better than while. Not even sure is country should be counted
                }
            }
                    {
                    goldscore = gold * 3;
                    silverscore = silver * 2;
                    bronzescore = bronze * 1;
                    sum = goldscore + silverscore + bronzescore;
                        winner = sum;
                        // determine the highest score for the winner(?)
                        if (sum < winner) 
                    winner = sum;
                    }
                {
                // country is String need to change to a int(?). 
                // need it to also figure out how to pick the country with the high quality of medals
                // Possibly substitute countrywin instead of country?
                    System.out.println("The winner is: " + country + " with " + gold + " gold medals," + silver + " silver medals, and " + bronze + " bronze medals.");
                }
            }
        }
        else if(again == 'c')//canadian method
        {
            // Canadian method which counts the total number of medals
            {
            System.out.println("Enter the number of countries competing: ");
            num = kb.nextInt();
            {
            while (count<=num)
                {
                System.out.println("Enter country and medal count(from gold to bronze): ");
                country = kb.next();
                gold = kb.nextInt();
                silver = kb.nextInt();
                bronze = kb.nextInt();
                // need to understand the american version first before proceding
                +=;
                }
            }
                    {
                    sum = gold + silver + bronze;
                        }
                {
                    System.out.println("The winner is: " + country + " with " + gold + " gold medals," + silver + " silver medals, and " + bronze + " bronze medals.");
                }
            }
        }
        else
        {
            System.err.println("invalid answer");
        }
    }
}
}
import java.util.Scanner;
奥林匹克梅达尔塞姆级
{
公共静态void main(字符串[]args)
{
扫描仪kb=新扫描仪(System.in);
int=0;
字符串countrywin;
int gold=0,silver=0,brown=0,count=0,num=0,sum=0;//num表示国家数量
int goldscore=0,silverscore=0,bronzescore=0;
弦国;
{
System.out.println(“请选择一种评分方法。a代表美国人,c代表加拿大人。”);
char再次=kb.next().charAt(0);
if(再次=='a')//美国方法
{
//美国方法计算得分最高的奖牌。例如:金牌价值3枚,银牌价值2枚,铜牌价值1枚。
//美国队赢得3金1银0铜=11分。
{
System.out.println(“输入竞争国家的数量:”);
num=kb.nextInt();
{
对于(int x=0;x

您可以通过使用自己的

获得所需的最小/最大值。请这样想。如果一个国家的奖牌数量输入少于上一个国家,为什么要继续存储它?请为当前最高值设置一个变量,并仅在需要时覆盖它们

int currentHigh = 0;
int noOfCountries = 10;
int input;

for(int i=0; i<noOfCountries; i++) {
    input = in.nextInt();
    if(input>currentHigh) {
        currentHigh=input;
    }
}
int currentHigh=0;
int noOfCountries=10;
int输入;
对于(int i=0;icurrentHigh){
电流高=输入;
}
}

如果这是家庭作业,那么你已经学习过课程了吗?现在似乎是使用它们的好时机

我将创建一个countries类,其中包含每个奖牌数量和国家名称的字段。然后,您可以在该类中编写一个sum方法,返回该国家拥有的所有奖牌的值。然后使用类似于@Patters answer的内容检查当前国家与得分最高的国家的总和

另外,我会将您的
if/else
语句替换为
开关
(非常适合菜单选择)


如果这不是家庭作业,我可以给你一些示例代码

您可以尝试使用数组来存储和值和国家名称。根据您的情况,您可以使用代码。它不一定完美,但可以工作。您还可以添加try和catch块,以确保当用户输入错误类型的数据(例如int而不是char)时,程序不会崩溃

 import java.util.Scanner;
 class OlympicMedalsEM
  {
    public static void main (String[] args)
      {
        Scanner kb = new Scanner(System.in);
        int goldscore=0, silverscore=0, bronzescore=0;
        String[] country;
       {
         System.out.println("Please choose a scoring method. a for American or c for Canadian.");                              
char again = kb.next().charAt(0);
    if(again == 'a')//american method
    {
        // American method counts the medals with the most score. ex: gold is worth 3,    silver 2, and bronze 1.
        // USA win 3 gold 1 silver 0 bronze = 11 points so to speak.
        {
        System.out.println("Enter the number of countries competing: ");
        int num = kb.nextInt();
        int []sum = new int[num];            // Create sum array with "num"         number of elements, each representing sum for one country
        country = new String[num];           
        {
        /** each country is saved in a string array "country" element with corresponding sum in the "sum" array */
        for (int x=0; x < num; x++)
            {
            System.out.println("Enter country and medal count(from gold to bronze): ");
            country[x] = kb.next();
            goldscore = kb.nextInt()*3;
            silverscore = kb.nextInt()*2;
            bronzescore = kb.nextInt()*1;
            sum[x]= goldscore+silverscore+bronzescore;

            }
        }       /** gets index of array "sum" with highest value element */
                int MaxIndex=0;
                for (int c=0; c<sum.length-1; c++){
                   if (sum[c+1]>sum[c]){
                   MaxIndex=c+1;
                   }
                }
                /** country with most medals is saved in the same index number as the maximum sum index */
                System.out.println(" the country with most medals is :" + country[MaxIndex]);
                }
                }

                }
                }
                }
import java.util.Scanner;
奥林匹克梅达尔塞姆级
{
公共静态void main(字符串[]args)
{
扫描仪kb=新扫描仪(System.in);
int goldscore=0,silverscore=0,bronzescore=0;
字符串[]国家;
{
System.out.println(“请选择一种评分方法。a代表美国人,c代表加拿大人。”);
char再次=kb.next().charAt(0);
if(再次=='a')//美国方法
{
//美国方法计算得分最高的奖牌。例如:金牌价值3枚,银牌价值2枚,铜牌价值1枚。
//美国队赢得3金1银0铜=11分。
{
System.out.println(“输入竞争国家的数量:”);
int num=kb.nextInt();
int[]sum=new int[num];//创建元素数为“num”的sum数组,每个元素表示一个国家的总和
country=新字符串[num];
{
/**每个国家/地区都保存在字符串数组“country”元素中,“sum”数组中有相应的sum*/
对于(int x=0;x