如果Java卡住，则小于或等于Else

该程序输入一个温度，并根据该温度输出一条消息。我的程序卡住了（超过50） System.out.println（“享受天气”）；

---

否则，如果（tempOutside所有

int

都是

>50

或

的话，如果您可以直接提到您的确切问题，然后是您的实现，那么会更清楚，因为这里的问题看起来可能有误解。
但我想也许这就是这里被问到的问题

if (tempOutside > 50)
    {
        System.out.println("Enjoy the weather");
    }
    else if (tempOutside <= 50)
    {
        if(tempOutside <= 30)
        {
            if(tempOutside <= -10)
            {
                System.out.println("BUNDLE UP it's \"COLD\" outside ");

            }
            else {
            System.out.println("Check the gas in you car before leaving");
            }

        }
        else
        {
            //when the temp is between 30 and 50
            System.out.println("Time to turn on the heat");

        }
    }

if（tempOutside>50）
{
System.out.println（“享受天气”）；
}
如果（临时）在外面
> 30

> -10

if (tempOutside > 50)
    {
        System.out.println("Enjoy the weather");
    }
    else if (tempOutside <= 50)
    {
        if(tempOutside <= 30)
        {
            if(tempOutside <= -10)
            {
                System.out.println("BUNDLE UP it's \"COLD\" outside ");

            }
            else {
            System.out.println("Check the gas in you car before leaving");
            }

        }
        else
        {
            //when the temp is between 30 and 50
            System.out.println("Time to turn on the heat");

        }
    }