Java 根据包含的xsd验证xml

我试图根据一个内部引用另一个XSD的XSD（使用include语句）验证XML

作为

我得到一个错误，“cvc数据类型有效。1.2.1:‘True’不是‘boolean’的有效值。”

这是针对schema1.xsd引用的schema2.xsd中定义的元素

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如果我做错了什么，请告诉我。

您遇到了案例问题。”true是xsd:boolean的有效值，但true（显然是XML文档中的值）不是

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此处的响应（）提供了一些附加信息和基于枚举值的可能替代解决方案（如果您无法将True更改为True）。

Awesome！！。。谢谢你的解决方案。

<xs:include schemaLocation="Schema2.xsd"/>

DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();

    DocumentBuilder builder;
    try {
        builder = factory.newDocumentBuilder();

        Document document = builder.parse(new InputSource(new StringReader(
                inputXml)));
        TransformerFactory tranFactory = TransformerFactory.newInstance();
        Transformer aTransformer = tranFactory.newTransformer();
        Source src = new DOMSource(document);
        Result xmlFile = new StreamResult(new File("xmlFileName.xml"));
        aTransformer.transform(src, xmlFile);
    } catch (Exception e) {
        // TODO: handle exception
    }

    File xmlFile = new File("xmlFileName.xml");
    SchemaFactory factory1 = SchemaFactory
            .newInstance("http://www.w3.org/2001/XMLSchema");

    File schemaLocation = new File("F:\\Project\\Automation\\XSDs\\schema1.xsd");
    Schema schema = factory1.newSchema(schemaLocation);

    Validator validator = schema.newValidator();

    Source source = new StreamSource(xmlFile);

    try {
        validator.validate(source);
        System.out.println(xmlFile.getName() + " is valid.");
        isXmlValid = true;
    } catch (SAXException ex) {
        System.out.println(xmlFile.getName() + " is not valid because ");
        System.out.println(ex.getMessage());
        isXmlValid = false;
    }