Java adviceexecution（）在AspectJ中不起作用

我正在学习Java，不知怎的我进入了AspectJ。我试图执行教程中的以下代码：

    pointcut adviceExecutionPointcut( ) : adviceexecution( );

   // Advice declaration
   before( ) : adviceExecutionPointcut( )
      && !within(AdviceExecutionRecipe +)
   {
      System.out.println(
         "------------------- Aspect Advice Logic --------------------");
      System.out.println("In the advice picked by ExecutionRecipe");
      System.out.println(
         "Signature: "
            + thisJoinPoint.getStaticPart( ).getSignature( ));
      System.out.println(
         "Source Line: "
            + thisJoinPoint.getStaticPart( ).getSourceLocation( ));
      System.out.println(
         "------------------------------------------------------------");
   }
}

它不知怎么地给了我一个这样的错误

Exception in thread "main" java.lang.StackOverflowError
    at helloWorld.ajc$before$helloWorld$2$5e65e204(helloWorld.aj)
    at helloWorld.ajc$before$helloWorld$2$5e65e204(helloWorld.aj)
    at helloWorld.ajc$before$helloWorld$2$5e65e204(helloWorld.aj)
    at helloWorld.ajc$before$helloWorld$2$5e65e204(helloWorld.aj)
    at helloWorld.ajc$before$helloWorld$2$5e65e204(helloWorld.aj)

作为参考，这是示例代码和建议代码

public class myClass {

    public void foo(int number, String name){
        System.out.println("Inside foo(int, String)");
    }

    public static void main(String[] args) {
        // TODO Auto-generated method stub
    myClass myObject = new myClass();
    myObject.foo(1, "ican");

    }


public aspect helloWorld {
    public int a;
    long startTime;


    pointcut callPointcut(int value, String name) :
        call(* myClass.foo(int, String)) && args(value,name);

     before(int value, String name) : callPointcut(value,name)
       {
         startTime = System.nanoTime();
          System.out.println("Start Time in ns :" + startTime);
       }

---

任何帮助都将不胜感激。谢谢

我没有看到包含adviceexecution切入点的方面的类型声明？我怀疑你在你的

helloWorld

方面删除了那个建议块。您得到递归stackoverflow的原因是该建议正在应用于自身。警卫

！在（AdviceExecutionRecipe+

中，用于停止将通知应用于自身。但是，您不能将其从

AdviceExecutionRecipe

更改为

helloWorld

，因为这样它将不适用于您的任何建议。因此，我将把这个advice块放在一个单独的方面，并称之为

adviceecutionrecipe

。有了这一点，它对我很有用：

$ ajc -1.8 *.java -showWeaveInfo

Join point 'adviceexecution(void helloWorld.ajc$before$helloWorld$1$68d3c671(int, java.lang.String))' in Type 'helloWorld' (helloWorld.java:9) advised by before advice from 'AdviceExecutionRecipe' (AdviceExecutionRecipe.java:5)

Join point 'method-call(void myClass.foo(int, java.lang.String))' in Type 'myClass' (myClass.java:10) advised by before advice from 'helloWorld' (helloWorld.java:9)

$ java myClass

------------------- Aspect Advice Logic --------------------
In the advice picked by ExecutionRecipe
Signature: void helloWorld.before(int, String)
Source Line: helloWorld.java:9
------------------------------------------------------------
Start Time in ns :216368803494701
Inside foo(int, String)

---

我没有看到包含adviceexecution切入点的方面的类型声明？我怀疑你在你的

helloWorld

方面删除了那个建议块。您得到递归stackoverflow的原因是该建议正在应用于自身。警卫

！在（AdviceExecutionRecipe+

中，用于停止将通知应用于自身。但是，您不能将其从

AdviceExecutionRecipe

更改为

helloWorld

，因为这样它将不适用于您的任何建议。因此，我将把这个advice块放在一个单独的方面，并称之为

adviceecutionrecipe

。有了这一点，它对我很有用：

$ ajc -1.8 *.java -showWeaveInfo

Join point 'adviceexecution(void helloWorld.ajc$before$helloWorld$1$68d3c671(int, java.lang.String))' in Type 'helloWorld' (helloWorld.java:9) advised by before advice from 'AdviceExecutionRecipe' (AdviceExecutionRecipe.java:5)

Join point 'method-call(void myClass.foo(int, java.lang.String))' in Type 'myClass' (myClass.java:10) advised by before advice from 'helloWorld' (helloWorld.java:9)

$ java myClass

------------------- Aspect Advice Logic --------------------
In the advice picked by ExecutionRecipe
Signature: void helloWorld.before(int, String)
Source Line: helloWorld.java:9
------------------------------------------------------------
Start Time in ns :216368803494701
Inside foo(int, String)

---

怎么了？它甚至可以编译吗？在堆栈中粘贴跟踪可能无法编译。它被放在邮局了有什么错？它甚至可以编译吗？在堆栈中粘贴跟踪可能无法编译。已经放在邮局了