Java 一对一外键
我的项目中的一对一外键关系映射有问题 User.javaJava 一对一外键,java,spring,spring-boot,Java,Spring,Spring Boot,我的项目中的一对一外键关系映射有问题 User.java @Access(AccessType.FIELD) @Entity @Table(name = "users") public class User { public Role ro; @Id @GeneratedValue(strategy = GenerationType.AUTO) public int user_id; @Column(name = "username") public String username; @Col
@Access(AccessType.FIELD)
@Entity
@Table(name = "users")
public class User {
public Role ro;
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
public int user_id;
@Column(name = "username")
public String username;
@Column(name = "password")
public String password;
@OneToOne(cascade = CascadeType.ALL)
@JoinColumn(name = "username")
public Role getRo() {
return ro;
}
public void setRo(Role ro) {
this.ro = ro;
}
@Column(name = "enabled")
public int enabled;
public User() {
}
public int getUser_id() {
return user_id;
}
public User(String username, String password, int enabled) {
this.username = username;
this.password = password;
this.enabled = enabled;
}
public String getUsername() {
return username;
}
public void setUsername(String username) {
this.username = username;
}
public String getPassword() {
return password;
}
public void setPassword(String password) {
this.password = password;
}
public int getEnabled() {
return enabled;
}
public void setEnabled(int enabled) {
this.enabled = enabled;
}
@Override
public String toString() {
return String.format(
"student[id=%d, name='%s', age='%d']",
ro.getUsername(), username, ro.getUsername());
}
}
Role.java
import javax.persistence.*;
@Access(AccessType.FIELD)
@Entity
@Table(name = "user_roles")
public class Role {
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
public int user_role_id;
@Column(name = "username")
public String username;
@Column(name = "role")
public String role;
public User user;
@OneToOne(mappedBy = "ro")
public User getUser() {
return user;
}
public void setUser(User user) {
this.user = user;
}
public Role(String username, String role) {
this.username = username;
this.role = role;
}
public Role() {
}
public int getUser_role_id() {
return user_role_id;
}
public String getUsername() {
return username;
}
public void setUsername(String username) {
this.username = username;
}
public String getRole() {
return role;
}
public void setRole(String role) {
this.role = role;
}
}
这就是错误:
原因:org.hibernate.MappingException:无法确定以下列的类型:com.company.project.models.Role,在表:users中:[org.hibernate.mapping.Column(ro)]
在org.hibernate.mapping.SimpleValue.getType(SimpleValue.java:431)~[hibernate-core-5.0.12.Final.jar:5.0.12.Final]
在org.hibernate.mapping.SimpleValue.isValid(SimpleValue.java:398)~[hibernate-core-5.0.12.Final.jar:5.0.12.Final]
在org.hibernate.mapping.Property.isValid(Property.java:225)~[hibernate-core-5.0.12.Final.jar:5.0.12.Final]
在org.hibernate.mapping.PersistentClass.validate(PersistentClass.java:595)~[hibernate-core-5.0.12.Final.jar:5.0.12.Final]
在org.hibernate.mapping.RootClass.validate(RootClass.java:265)~[hibernate-core-5.0.12.Final.jar:5.0.12.Final]
在org.hibernate.boot.internal.MetadataImpl.validate(MetadataImpl.java:329)~[hibernate-core-5.0.12.Final.jar:5.0.12.Final]
在org.hibernate.boot.internal.SessionFactoryBuilderImpl.build(SessionFactoryBuilderImpl.java:443)~[hibernate-core-5.0.12.Final.jar:5.0.12.Final]
在org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl.build(EntityManagerFactoryBuilderImpl.java:879)~[hibernate-entitymanager-5.0.12.Final.jar:5.0.12.Final]
... 22省略的公共帧您应该在变量声明或getter()上注释所有
@Column
/@OneToOne
。这就是为什么hibernate在类用户中找不到角色
请尝试在变量或用户类
中的getter上注释所有@列
和@MappedBy
。谢谢,我现在没有为实体指定标识符:com.company.project.models.User。这是我的代码@Id@GeneratedValue(strategy=GenerationType.AUTO)public int getUser_Id(){return user_Id;}您确定不能混合使用字段注释和方法注释吗?我同意这样做是不好的做法。我确信你不能为@Column
注释这样做,也不能完全确定映射。的确是坏习惯。谢谢