Javascript 角形意外标记{
我有一个工作正常的代码,突然出现了一个错误,说:Javascript 角形意外标记{,javascript,php,angularjs,Javascript,Php,Angularjs,我有一个工作正常的代码,突然出现了一个错误,说: SyntaxError: Unexpected token { at Object.parse (native) at fromJson (http://localhost/public_html/faculte/js/angular.js:1250:14) at defaultHttpResponseTransform (http://localhost/public_html/faculte/js/angular.js:9371:16) at
SyntaxError: Unexpected token {
at Object.parse (native)
at fromJson (http://localhost/public_html/faculte/js/angular.js:1250:14)
at defaultHttpResponseTransform (http://localhost/public_html/faculte/js/angular.js:9371:16)
at http://localhost/public_html/faculte/js/angular.js:9462:12
at forEach (http://localhost/public_html/faculte/js/angular.js:336:20)
at transformData (http://localhost/public_html/faculte/js/angular.js:9461:3)
at transformResponse (http://localhost/public_html/faculte/js/angular.js:10241:23)
at processQueue (http://localhost/public_html/faculte/js/angular.js:14634:28)
at http://localhost/public_html/faculte/js/angular.js:14650:27
at Scope.parent.$get.Scope.$eval (http://localhost/public_html/faculte/js/angular.js:15878:28)
在我的代码中,我向PHP发送了一个http请求,下面是JS代码:
main.submitNewChap = function(){
var data = main.newChap;
data.function = 'submitNewChap';
$http({
url: "ajax-functions.php",
method: "POST",
headers: {'Content-Type': 'application/x-www-form-urlencoded'},
data: $httpParamSerializerJQLike(data)
}).success(function(res) {
switch(res.msg){
case 1:
$translate(['success','newChapSuccess']).then(function(t){
toastr.success(t.newChapSuccess,t.success);
});
main.newChap = {};
main.data.chaps.push(res.item);
break;
case 2:
$translate(['error','missingData']).then(function (t) {
toastr.error(t.missingData,t.error);
});
break;
case 3:
$translate(['error','notAllowed']).then(function (t) {
toastr.error(t.notAllowed,t.error);
});
break;
}
}).error(function(res) {
$translate(['error','generalError']).then(function (t) {
toastr.error(t.generalError,t.error);
});
});
}
以及PHP函数:
function submitNewChap($data){
$res = 0;
$item = array();
if(userData('role') == 'admin'){
if($data['title'] != ''){
$item = R::dispense('chap');
$item->title = $data['title'];
$item->date = time();
$id = R::store($item);
$res = 1;
$item = array(
'id' => $id,
'title' => $item->title,
'date' => $item->date,
'courses' => array()
);
}else{
$res = 2;
}
}else{
$hack = R::dispense('hack');
$hack->text = "Trying to hack and adding Chap";
R::store($hack);
$res = 3;
}
return array(
'msg' => $res,
'item' => $item
);
/*
1: ok
2: missing data
3: not allowed
*/
}
这是我的ajax-functions.php代码:
include 'functions.php';
if(isset($_POST['function'])){
switch ($_POST['function']) {
case 'submitNewChap':
echo json_encode(submitNewChap($_POST));
default:
break;
}
}
我在代码中没有发现任何错误(至少我认为是这样),我到处搜索,但在web上没有找到任何解决方案,问题出在哪里?您应该能够在开发工具控制台中右键单击,然后单击“启用XMLHttpRequest日志记录” 一旦启用,您将在控制台中看到XHR(ajax)请求,并可以单击它们将您带到资源面板,在那里您将能够看到请求的内容/响应 如果您的请求中存在php错误,您可以在那里看到错误详细信息
这不是答案。这应该是一个评论。但是正如你所看到的,我是这里的新手。服务器响应的问题。您可以发布它吗?这似乎是一个问题,因为您没有返回JSON,您返回的是php代码,它不是JSON编码的,因此解析错误。此外,在php中也没有输入标题。如果你这么做了,请用代码告诉我们。我编辑了这条消息,即使这应该是一条评论,我也将其标记为最佳答案!这对我解决问题帮助很大!我错过了“休息”在我的php中。。。谢谢lot@Burawi很高兴这对你有帮助。