Javascript 通过ajax发布到PHP的音频blob返回NULL
我正在使用recorder.js。我的目标是把录音上传到服务器上,好像音频块被上传到了服务器上。但是我不断地得到$_文件[“file”][“tmp_name”]的null返回值 Javascript:Javascript 通过ajax发布到PHP的音频blob返回NULL,javascript,php,ajax,recorder.js,Javascript,Php,Ajax,Recorder.js,我正在使用recorder.js。我的目标是把录音上传到服务器上,好像音频块被上传到了服务器上。但是我不断地得到$_文件[“file”][“tmp_name”]的null返回值 Javascript: function uploadAudio(){ audioRecorder.stop(); audioRecorder.exportWAV(function(audio) { var fd = new FormData(); fd.append('filename', 'test.wav'); f
function uploadAudio(){
audioRecorder.stop();
audioRecorder.exportWAV(function(audio) {
var fd = new FormData();
fd.append('filename', 'test.wav');
fd.append('data', blob);
$.ajax({
type: 'POST',
url: 'testthing.php',
data: fd,
processData: false,
contentType: false
}).done(function(data) {
console.log(data);
});
});
}
PHP:
以下是我在firefox中使用firebug发布的标题数据:
-----------------------------2600221228510
Content-Disposition: form-data; name="filename"
test.wav
-----------------------------2600221228510
Content-Disposition: form-data; name="data"; filename="blob"
Content-Type: audio/wav
多亏了你,我才使它运转起来
javascript:
audioRecorder.exportWAV(function(blob) {
var url = (window.URL || window.webkitURL).createObjectURL(blob);
console.log(url);
var filename = "test.wav";
var data = new FormData();
data.append('file', blob);
$.ajax({
url : "testthing.php",
type: 'POST',
data: data,
contentType: false,
processData: false,
success: function(data) {
alert("boa!");
},
error: function() {
alert("not so boa!");
}
});
});
if(isset($_FILES['file']) and !$_FILES['file']['error']){
$fname = "11" . ".wav";
move_uploaded_file($_FILES['file']['tmp_name'], "recordings/" . $fname);
}
?>
php:
if(isset($_FILES['file']) and !$_FILES['file']['error']){
$fname = "11" . ".wav";
move_uploaded_file($_FILES['file']['tmp_name'], "recordings/" . $fname);
}
?>