如何过滤多维JavaScript数组

我有以下数据：

var object = [{
    "nid": "31",
    "0": {
        "tid": "20",
        "name": "Bench Press",
        "objectDate": "2012-02-08",
        "goal": "rep",
        "result": "55.00",
        "comments": "sick!",
        "maxload": "250"
    },
    "1": {
        "tid": "22",
        "name": "Back Squat",
        "objectDate": "2012-02-08",
        "goal": "time",
        "result": "8.00",
        "comments": "i was tired.",
        "maxload": "310"
    }},
{
    "nid": "30",
    "0": {
        "tid": "19",
        "name": "Fran",
        "objectDate": "2012-02-07",
        "goal": "time",
        "result": "5.00",
        "comments": null
    }}];

我想按名字过滤它。例如，如果我对名称“Fran”应用过滤器，我希望有如下内容：

[0] => Array
     (
        [tid] => 19
        [name] => Fran
        [objectDate] => 2012-02-07
        [goal] => time
        [result] => 5.00
        [comments] => 
     )
[1] => Array
     (
        [tid] => 19
        [name] => Fran
        [objectDate] => 2012-02-08
        [goal] => rep
        [result] => 55.00
        [comments] => woohoo!
     )

有可能实现吗

问题是关于多维数组的。如果你喜欢我错过了，这里是普通阵列的解决方案

2020年

filteredArray = array.filter(item => item.name.indexOf('Fran') > -1);

或

2012版

var result = [];
for (var i = 0; i < array.length; i++)
{
    if (array[i].name === 'Fran')
    {
        result.push(array[i]);
    }
}

var结果=[]；
对于（var i=0；i

我将创建一个过滤功能：

function filter(array, key, value){
    var i, j, hash = [], item;

    for(i =  0, j = array.length; i<j; i++){
        item = array[i];
        if(typeof item[key] !== "undefined" && item[key] === value){
            hash.push(item);
        }
    }

    return hash;
}

---

Javascript中没有用于此的函数。您必须像这样编写自己的函数

var arr = [{"nid":"31","0":{"tid":"20","name":"Bench Press","objectDate":"2012-02-08","goal":"rep","result":"55.00","comments":"sick!","maxload":"250"},"1":{"tid":"22","name":"Back Squat","objectDate":"2012-02-08","goal":"time","result":"8.00","comments":"i was tired.","maxload":"310"}},{"nid":"30","0":{"tid":"19","name":"Fran","objectDate":"2012-02-07","goal":"time","result":"5.00","comments":null}}];


function filterByProperty(array, prop, value){
    var filtered = [];
    for(var i = 0; i < array.length; i++){

        var obj = array[i];

        for(var key in obj){
            if(typeof(obj[key] == "object")){
                var item = obj[key];
                if(item[prop] == value){
                    filtered.push(item);
                }
            }
        }

    }    

    return filtered;

}

var byName = filterByProperty(arr, "name", "Fran");
var byGoal = filterByProperty(arr, "goal", "time");

var arr=[{“nid”：“31”，“0”：“{“tid”：“20”，“姓名”：“台式机”，“目标日期”：“2012-02-08”，“目标”：“rep”，“结果”：“55.00”，“评论”：“sick！”，“maxload”：“250”}，“1”：“{“tid”：“22”，“姓名”：“后蹲”，“objectDate”：“2012-02-08”，“目标”：“时间”，“结果”：“8.00”，“评论”：“我很累”，“maxload”：“310”}，{“nid”：“30”，“0”：“19”，“objectDate“2012-02-07”，“目标”：“时间”，“结果”：“5.00”，“注释”：null}}]；
函数filterByProperty（数组、属性、值）{
var筛选=[]；
对于（var i=0；i

最大的技巧是制作一个平面阵列，其中包含您想要的项目

假设您有一个二维数组，如下所示：

e = [[1,2],[1,2],[2,3],[4,5],[6,7]]

创建一个新数组：

var f = []

只需填写一项：

for(var x=0;x<e.length;x++) f[x] = e[x][1]

然后

var g = e.filter( function(elem, pos){ return (f.indexOf(elem[1]) == pos) })

---

cowabunga！

我尝试了二极管的解决方案。我适合我的情况。包括3个阵列

var arr = 
[

  {
    taskTypeGroupId: "EXP.CONT", taskTypeGroupName: "Contradictoire", 
    taskType: 
    {
      taskTypeId: "DGE-EXPCONT", taskTypeName: "Dégats des eaux contradictoire", defaultDuration: 60, isInProject: false, 
      dataItems:
      {
        id: "EXTRAFILLER5", label: "Divers 5"
      }
    }
  },

  {
  takTypeGroupId: "EXPQUAL", taskTypeGroupName: "Contrôle qualité", 
    taskType: 
    {
      taskTypeId: "DGE-EXPQUAL", taskTypeName: "Contrôle qualité dégats des eaux", defaultDuration: 60, isInProject: false, 
      dataItems: 
      {
        id: "EXTRAFILLER5", label: "Divers 5"
      }
    }
  }

];
function filterByProperty(array, prop, value){
var filtered = [];

for(var i = 0; i < array.length; i++){
var array1 = array[i];
  for(var key in array1){
    if(typeof(array1[key] == "object")){
    var array2 = array1[key];
      for (var key2 in array2){
        if(typeof(array2[key2] == "object")){
        var array3 = array2[key2];
          if(array3[prop] == value){
            filtered.push(array3);
          }
        }
      }
    }
  }
}    
return filtered;

var-arr=
[
{
taskTypeGroupId:“EXP.CONT”，taskTypeGroupName:“conclareoire”，
任务类型：
{
taskTypeId:“DGE-EXPCONT”，taskTypeName:“Dégats des eaux conclaure”，默认持续时间：60，isInProject:false，
数据项：
{
id：“额外填充物5”，标签：“潜水员5”
}
}
},
{
takTypeGroupId:“EXPQUAL”，taskTypeGroupName:“Contrôle qualité”，
任务类型：
{
taskTypeId:“DGE-EXPQAL”，taskTypeName:“水资源质量控制”，默认持续时间：60，isInProject:false，
数据项：
{
id：“额外填充物5”，标签：“潜水员5”
}
}
}
];
函数filterByProperty（数组、属性、值）{
var筛选=[]；
对于（var i=0；i

}

---

如果您的对象包含3个字段，例如email、firstName、lastName，则使用此字段

ArrayObject
.filter(em => em.email.indexOf(searchEmail) > -1)
.filter(fn => fn.firstName.indexOf(searchFirstName) > -1)
.filter(ln => ln.lastName.indexOf(searchLastName) > -1) 

---

您可能会对我的JSON.search API感兴趣，它比$.grep快5倍，允许您使用正则表达式进行搜索gold@CyrilleConMorales嗯，我今天不会这样做。首先，我会使用

==

，但它与

f = [2,2,3,5,7]

var g = e.filter( function(elem, pos){ return (f.indexOf(elem[1]) == pos) })

var arr = 
[

  {
    taskTypeGroupId: "EXP.CONT", taskTypeGroupName: "Contradictoire", 
    taskType: 
    {
      taskTypeId: "DGE-EXPCONT", taskTypeName: "Dégats des eaux contradictoire", defaultDuration: 60, isInProject: false, 
      dataItems:
      {
        id: "EXTRAFILLER5", label: "Divers 5"
      }
    }
  },

  {
  takTypeGroupId: "EXPQUAL", taskTypeGroupName: "Contrôle qualité", 
    taskType: 
    {
      taskTypeId: "DGE-EXPQUAL", taskTypeName: "Contrôle qualité dégats des eaux", defaultDuration: 60, isInProject: false, 
      dataItems: 
      {
        id: "EXTRAFILLER5", label: "Divers 5"
      }
    }
  }

];
function filterByProperty(array, prop, value){
var filtered = [];

for(var i = 0; i < array.length; i++){
var array1 = array[i];
  for(var key in array1){
    if(typeof(array1[key] == "object")){
    var array2 = array1[key];
      for (var key2 in array2){
        if(typeof(array2[key2] == "object")){
        var array3 = array2[key2];
          if(array3[prop] == value){
            filtered.push(array3);
          }
        }
      }
    }
  }
}    
return filtered;

ArrayObject
.filter(em => em.email.indexOf(searchEmail) > -1)
.filter(fn => fn.firstName.indexOf(searchFirstName) > -1)
.filter(ln => ln.lastName.indexOf(searchLastName) > -1)