Javascript SyntaxError:带有JSON数组的未终止字符串文字

所以我

 var newfavz = 'Array (


[0] => [" 6 "," 1 "," 2 "," 5 "," 3 "," 4 "]
[1] => [" 6 "," 1 "," 2 "," 5 "," 3 "," 4 "]
[2] => [" 6 "," 1 "," 2 "," 5 "," 3 "," 4 "]

)
';

在我的console.log上，但不知何故出现了一个语法错误：unterminated string literal。我环顾四周，尝试了一些方法，比如str_replace“/”和“/”或类似正则表达式的.replace（/^/+//g，”）；因为JavaScript似乎不允许将字符串分成多行或类似的内容

这一切都是从这样的SQL查询开始的

$favurl = [];
$favquery = "SELECT * FROM userfavs WHERE users = '$username'";
$favresult = mysqli_query($conn, $favquery);

while($row = mysqli_fetch_assoc($favresult)) {

array_push($favurl, $row['fav_id']);

后来，我做到了

var newfavz = <?php print_r ($favurl); ?>

var newfavz=

这导致了上述情况

---

有什么方法可以解决语法错误吗？谢谢

原因js中不允许使用多行字符串：

"A
 B"

是一个语法错误。您可以删除所有换行符并将其替换为\n，或者使用模板文字：

`A
 B`

在代码中：

var newfavz =` <?php print_r ($favurl); ?>`;

var newfavz=`；

关于这个错误，我想说的太多了。但是字符串仍然不可用，需要对其进行分析。查看JSON或编写自己的小解析器。

或者使用ES6：

或者使用反斜杠：

var newfavz = 'Array (\n\
\n\
\n\
[0] => [" 6 "," 1 "," 2 "," 5 "," 3 "," 4 "]\n\
[1] => [" 6 "," 1 "," 2 "," 5 "," 3 "," 4 "]\n\
[2] => [" 6 "," 1 "," 2 "," 5 "," 3 "," 4 "]\n\
\n\
)\
';

或连接：

var newfavz = 'Array (\n' +
  '\n' +
  '\n' +
  '[0] => [" 6 "," 1 "," 2 "," 5 "," 3 "," 4 "]\n' +
  '[1] => [" 6 "," 1 "," 2 "," 5 "," 3 "," 4 "]\n' +
  '[2] => [" 6 "," 1 "," 2 "," 5 "," 3 "," 4 "]\n' +
  '\n' +
  ')\n';

---

\n

用于表示一个

换行符

您必须在每行末尾加一个反斜杠才能有一个多行字符串：

var newfavz = 'Array (\
[0] => [" 6 "," 1 "," 2 "," 5 "," 3 "," 4 "]\
[1] => [" 6 "," 1 "," 2 "," 5 "," 3 "," 4 "]\
[2] => [" 6 "," 1 "," 2 "," 5 "," 3 "," 4 "]\
)\
';

---

echo

json\u encode的结果而不是使用

print\r

。打印的字符串在JavaScript环境中是无用的，检查啊抱歉我在调试时使用了print_r:）要添加到这个，在服务器上，在传递给JS之前，应该使用json_encode（）方法将数组编码为json对象。嘿，我忘了将此添加到问题中，但在将数据插入SQL数据库之前，我确实使用了JSON_编码方法。到目前为止，我发现消除这个未终止字符串文字错误的唯一方法是执行另一个JSON_编码，这在我看来相当愚蠢。谢谢你！我使用了``字符，效果非常好！

var newfavz = 'Array (\
[0] => [" 6 "," 1 "," 2 "," 5 "," 3 "," 4 "]\
[1] => [" 6 "," 1 "," 2 "," 5 "," 3 "," 4 "]\
[2] => [" 6 "," 1 "," 2 "," 5 "," 3 "," 4 "]\
)\
';