Javascript Sinon存根不适用于导出的函数

Sinon似乎没有从导入的文件中删除方法。这与导出常量有关吗

我在console.log中看到“已接收原始消息”

Main.js

import * as otherActions from 'filters/actions/Other.actions';

describe('filter actions', () => {

    it('should log STUBBED MESSAGE', () => {   
      sinon.stub(otherActions, 'logMessage').callsFake(m => console.log('STUBBED Message'));
      const compiled = otherActions.doSomethingAndLogMessage(5, 5);
      compiled(message => console.log(`RECEIVED ${message}`), () => {});
    });

});

export const logMessage = () => console.log("ORIGINAL MESSAGE");

export const doSomethingAndLogMessage = (categoryId, size) => (dispatch, getState) => {
  dispatch(logMessage());
};

Other.actions.js

import * as otherActions from 'filters/actions/Other.actions';

describe('filter actions', () => {

    it('should log STUBBED MESSAGE', () => {   
      sinon.stub(otherActions, 'logMessage').callsFake(m => console.log('STUBBED Message'));
      const compiled = otherActions.doSomethingAndLogMessage(5, 5);
      compiled(message => console.log(`RECEIVED ${message}`), () => {});
    });

});

export const logMessage = () => console.log("ORIGINAL MESSAGE");

export const doSomethingAndLogMessage = (categoryId, size) => (dispatch, getState) => {
  dispatch(logMessage());
};

---

出现此问题的原因是，当在模块上下文中引用时，您正在导出模块中存根函数。当从模块内部引用它时，您不是存根。有很多方法可以解决这个问题，但我认为所有这些都需要您稍微更改一下生产代码

一项建议是：

Other.actions.js

export const logger = { message: () => console.log("ORIGINAL MESSAGE") };

Main.js

import * as otherActions from 'filters/actions/Other.actions';

...
sinon.stub(otherActions.logger, 'message')
  .callsFake(m => console.log('STUBBED Message'));

重要的是，您要在测试模块可用的上下文中创建存根

---

另一个一般性意见是，通常情况下，您不希望在正在测试的模块中模拟或存根函数或方法。通常，单元测试单元指的是一个模块。因此，如果您发现需要在正在测试的同一模块中删除某些内容，那么我建议您的模块边界不正确。

您使用的是哪一版本的sinon？我使用的是5.0.10版