Javascript 不带数据库的php json jQuery自动完成
我想用Javascript 不带数据库的php json jQuery自动完成,javascript,php,jquery,json,autocomplete,Javascript,Php,Jquery,Json,Autocomplete,我想用jQuery在我的表单上自动完成。源代码取自php的json数据,但我不使用数据库。 这是我的密码: facebookfriends.php <?php include('facebookdata.php'); $user_friend = $user_friends['data']; $json_friends = json_encode($user_friend); echo $json_friends; ?> JSON数据 [{"name":"Indiarto Pr
jQuery
在我的表单上自动完成。源代码取自php的json
数据,但我不使用数据库。
这是我的密码:
facebookfriends.php
<?php
include('facebookdata.php');
$user_friend = $user_friends['data'];
$json_friends = json_encode($user_friend);
echo $json_friends;
?>
JSON数据
[{"name":"Indiarto Priadi","id":"502163984"},
{"name":"Agustin Kertawijaya","id":"511990261"},
{"name":"Jecklyne Christin L","id":"528197912"},
{"name":"Jazi Eko Istiyanto","id":"531149275"},
{"name":"Esritha Situmorang","id":"535864892"},
{"name":"Christy Margaretha Siregar","id":"543468540"},
{"name":"Daniel Oscar Baskoro","id":"549332828"},
........]
我只想在autocomplete中显示名称
,以确保autocomplete工作正常。但事实并非如此。请帮忙。谢谢大家! 您需要将标签和值传递到php文件中
比如说
$data[] = array(
'label' => $row['city_name'].','.$state['state_name'].','.$c_name['country_name'],
'value' => $row['city_name'].','.$state['state_name'].','.$c_name['country_name']
);
echo json_encode($data);
flush();
1.您必须在php中解析json
2.为下拉列表创建一个数组
应遵循以下步骤:
$data ='[{"name":"Indiarto Priadi","id":"502163984"},
{"name":"Agustin Kertawijaya","id":"511990261"},
{"name":"Jecklyne Christin L","id":"528197912"},
{"name":"Jazi Eko Istiyanto","id":"531149275"},
{"name":"Esritha Situmorang","id":"535864892"},
{"name":"Christy Margaretha Siregar","id":"543468540"},
{"name":"Daniel Oscar Baskoro","id":"549332828"}]';
$user_friend = json_decode($data, true );
$data=array();
foreach($user_friend as $key=>$val)
$data[]=$val['name'];
$json_friends =json_encode($data);
echo $json_friends;
告诉我你有什么问题。请清楚地解释一下自动完成没有出现(当我在输入字段中键入一些字母时不会发生任何情况)。自动完成需要一个字符串数组(没有键),或者一个带有标签和/或值的键的数组。您能否更新facebookdata.php
以添加标签
键,该键可能只是您的名称
值的副本。
$data ='[{"name":"Indiarto Priadi","id":"502163984"},
{"name":"Agustin Kertawijaya","id":"511990261"},
{"name":"Jecklyne Christin L","id":"528197912"},
{"name":"Jazi Eko Istiyanto","id":"531149275"},
{"name":"Esritha Situmorang","id":"535864892"},
{"name":"Christy Margaretha Siregar","id":"543468540"},
{"name":"Daniel Oscar Baskoro","id":"549332828"}]';
$user_friend = json_decode($data, true );
$data=array();
foreach($user_friend as $key=>$val)
$data[]=$val['name'];
$json_friends =json_encode($data);
echo $json_friends;