Javascript 使用groupby设置Json对象格式

Javascript 使用groupby设置Json对象格式,javascript,angularjs,json,grouping,Javascript,Angularjs,Json,Grouping,我正试图通过groupping city name格式化json对象。我正在尝试使用一个单独的数组,并根据find和not found移动项目,以构建一个字符串。我正在使用javascript/angularjs来实现这一点 我当前的字符串 CurrentDataFormat = [ {"Id":17,"code":"123","cityName":"Los Angeles","startDate":"1/20/2016","endDate":"1/20/2016"}, {"Id":18,"

我正试图通过groupping city name格式化json对象。我正在尝试使用一个单独的数组,并根据find和not found移动项目,以构建一个字符串。我正在使用javascript/angularjs来实现这一点

我当前的字符串

CurrentDataFormat = 
[
{"Id":17,"code":"123","cityName":"Los Angeles","startDate":"1/20/2016","endDate":"1/20/2016"},

{"Id":18,"code":"456","cityName":"Chicago    ","startDate":"1/22/2016","endDate":"1/25/2016"},

{"Id":19,"code":"789","cityName":"Los Angeles","startDate":"1/13/2016","endDate":"1/21/2016"}
]
我正在尝试实现这种格式

ExpectedDataFormat =

[{
"name":"Los Angeles",
"CityData":
[
{"Id":"17","code":"123","startDate":"1/20/2016","endDate":"1/20/2016"},
{"Id":"19","code":"789","startDate":"1/13/2016","endDate":"1/21/2016"}
]},{
"name":"Chicago",
"CityData":
[
{"Id":"18","code":"456","startDate":"1/22/2016","endDate":"1/25/2016"},
]}

}
逻辑我在尝试什么(尽管尝试使用不同的数据)

检查以下代码

CurrentDataFormat = [{
        "Id": 17,
        "code": "123",
        "cityName": "Los Angeles",
        "startDate": "1/20/2016",
        "endDate": "1/20/2016"
    },

    {
        "Id": 18,
        "code": "456",
        "cityName": "Chicago",
        "startDate": "1/22/2016",
        "endDate": "1/25/2016"
    },

    {
        "Id": 19,
        "code": "789",
        "cityName": "Los Angeles",
        "startDate": "1/13/2016",
        "endDate": "1/21/2016"
    }
]


var refinedArray = {};

for (i = 0; i < CurrentDataFormat.length; i++) {
    refinedArray[CurrentDataFormat[i].cityName] = refinedArray[CurrentDataFormat[i].cityName] ? refinedArray[CurrentDataFormat[i].cityName] : {};

    refinedArray[CurrentDataFormat[i].cityName].name = CurrentDataFormat[i].cityName;

    refinedArray[CurrentDataFormat[i].cityName].CityData = refinedArray[CurrentDataFormat[i].cityName].CityData ? refinedArray[CurrentDataFormat[i].cityName].CityData : [];
    refinedArray[CurrentDataFormat[i].cityName].CityData.push({
        "Id": CurrentDataFormat[i].Id,
        "code": CurrentDataFormat[i].code,
        "startDate": CurrentDataFormat[i].startDate,
        "endDate": CurrentDataFormat[i].endDate
    });
}

var ExpectedDataFormat = [];

for (singleCityName in refinedArray){
    ExpectedDataFormat.push({'name' : refinedArray[singleCityName].name, 'CityData' : refinedArray[singleCityName].CityData});
};
CurrentDataFormat=[{
“Id”:17,
“代码”:“123”,
“城市名称”:“洛杉矶”,
“起始日期”:“2016年1月20日”,
“截止日期”:“2016年1月20日”
},
{
“Id”:18,
“代码”:“456”,
“城市名称”:“芝加哥”,
“起始日期”:“2016年1月22日”,
“截止日期”:“2016年1月25日”
},
{
“Id”:19,
“代码”:“789”,
“城市名称”:“洛杉矶”,
“起始日期”:“1/13/2016”,
“截止日期”:“2016年1月21日”
}
]
var-darray={};
对于(i=0;i
ExpectedDataFormat
保存您所需的输出

处运行演示检查以下代码

CurrentDataFormat = [{
        "Id": 17,
        "code": "123",
        "cityName": "Los Angeles",
        "startDate": "1/20/2016",
        "endDate": "1/20/2016"
    },

    {
        "Id": 18,
        "code": "456",
        "cityName": "Chicago",
        "startDate": "1/22/2016",
        "endDate": "1/25/2016"
    },

    {
        "Id": 19,
        "code": "789",
        "cityName": "Los Angeles",
        "startDate": "1/13/2016",
        "endDate": "1/21/2016"
    }
]


var refinedArray = {};

for (i = 0; i < CurrentDataFormat.length; i++) {
    refinedArray[CurrentDataFormat[i].cityName] = refinedArray[CurrentDataFormat[i].cityName] ? refinedArray[CurrentDataFormat[i].cityName] : {};

    refinedArray[CurrentDataFormat[i].cityName].name = CurrentDataFormat[i].cityName;

    refinedArray[CurrentDataFormat[i].cityName].CityData = refinedArray[CurrentDataFormat[i].cityName].CityData ? refinedArray[CurrentDataFormat[i].cityName].CityData : [];
    refinedArray[CurrentDataFormat[i].cityName].CityData.push({
        "Id": CurrentDataFormat[i].Id,
        "code": CurrentDataFormat[i].code,
        "startDate": CurrentDataFormat[i].startDate,
        "endDate": CurrentDataFormat[i].endDate
    });
}

var ExpectedDataFormat = [];

for (singleCityName in refinedArray){
    ExpectedDataFormat.push({'name' : refinedArray[singleCityName].name, 'CityData' : refinedArray[singleCityName].CityData});
};
CurrentDataFormat=[{
“Id”:17,
“代码”:“123”,
“城市名称”:“洛杉矶”,
“起始日期”:“2016年1月20日”,
“截止日期”:“2016年1月20日”
},
{
“Id”:18,
“代码”:“456”,
“城市名称”:“芝加哥”,
“起始日期”:“2016年1月22日”,
“截止日期”:“2016年1月25日”
},
{
“Id”:19,
“代码”:“789”,
“城市名称”:“洛杉矶”,
“起始日期”:“1/13/2016”,
“截止日期”:“2016年1月21日”
}
]
var-darray={};
对于(i=0;i
ExpectedDataFormat
保存您所需的输出


上运行演示,这段代码能满足您的需要吗

var newarray = [];

CurrentDataFormat.forEach(function(item){
    if(newarray[item.cityName] != undefined){
      var key = item.cityName;
      delete item.cityName;
      newarray[key].CityData.push(item);
  }else{
    var o = {};
    o.name = item.cityName;
    o.CityData = [];
    o.CityData.push(item);
    newarray[o.name] = o;
  }
});

console.log(newarray);

这段代码能满足您的需要吗

var newarray = [];

CurrentDataFormat.forEach(function(item){
    if(newarray[item.cityName] != undefined){
      var key = item.cityName;
      delete item.cityName;
      newarray[key].CityData.push(item);
  }else{
    var o = {};
    o.name = item.cityName;
    o.CityData = [];
    o.CityData.push(item);
    newarray[o.name] = o;
  }
});

console.log(newarray);

在jsFiddle.net上创建一个jsFiddle。因此,我们可以更好地理解您的问题。在jsFiddle.net上创建一个jsFiddle。因此,我们可以更好地理解您的问题。您给出了几乎正确的答案,但在if(newarray[item.cityName]!=undefined){delete item.cityName;newarray[item.cityName].CityData.push(item);}正如用户所提到的,cityData将没有cityName。这似乎是非常通用的代码,非常有用,但是JSFIDLE抛出错误cityData未定义。因此无法将其标记为正确。抱歉,这是
delete
行。我不假思索地加了上去。修复了它,现在它可以工作了。您已经给出了几乎正确的答案,但在if(newarray[item.cityName]!=undefined){delete item.cityName;newarray[item.cityName].CityData.push(item);}正如用户所提到的,cityData将没有cityName。这似乎是非常通用的代码,非常有用,但是JSFIDLE抛出错误cityData未定义。因此无法将其标记为正确。抱歉,这是
delete
行。我不假思索地加了上去。修复了它,所以现在它可以工作了。