Javascript 向客户端呈现php数组时出现Jquery DataTable错误

我已经从PHP页面发送了json_编码的数据：

$arrayForDataTablePopulation = array();

        while (($row = oci_fetch_array($stid, OCI_BOTH)) != false) {

                $a = trim($row["IDCONF"]);
                $b = trim($row["NOME"]);
                $c = trim($row["TIPOLOGIA"]);
                $d = trim($row["STATO"]);
                $e = trim($row["AMBIENTE"]);
                $f = trim($row["AGGREGATORE"]);
                $f2 = trim($row["NOMECED"]);
                $g = trim($row["MODELLO"]);
                $h = trim($row["CONTRATTO"]);
                $i = trim($row["VALIDADAL"]);
                $l = trim($row["VALIDAAL"]);

            if ($count < $NUM){

                $arrayForDataTablePopulation[$count] = "[" .  $a . "," .  $b . "," . $c . "," . $d . "," . $e . "," . $f . "," . $f2 . "," . $g . "," . $h . "," . $i . "," . $l . " ]";
                $count++;

            } else {

                $arrayForDataTablePopulation[$count] = "[" .  $a . "," .  $b . "," . $c . "," . $d . "," . $e . "," . $f . "," . $f2 . "," . $g . "," . $h . "," . $i . "," . $l . " ]";

            }

        }

        echo  json_encode($arrayForDataTablePopulation);

} else {

    echo "No data Received. Dimensione array: " . $receivedArrayFormSize;

}

问题是我对所有这些Array/JSON的东西感到困惑，我想我现在脑子里有很多困惑xD 有人能帮我找到解决这个问题的方法吗？ 是PHP端错误还是AJAX中的代码错误

我想做的是修改服务器阵列，发送回客户端并正确呈现数据表。

PHP

应使用以下代码填充阵列：

$arrayForDataTablePopulation[$count] = array($a, $b, $c, $d, $e, $f, $f2, $g, $h, $i, $l);

要打印JSON，请使用以下代码：

header('Content-type: application/json');
echo json_encode($arrayForDataTablePopulation);

JS

在

success

处理程序中使用以下代码：

$('#OUTCOME_RESEARCH_TABLE').DataTable({
     "dom": 'ltipr',
     "data": data,
     "pageLength": 100,
     "scrollY": 150,
     "scrollX": true,
     "ordering": false
});

---

谢谢你，伙计！我会试试看，我会让你知道的！

$('#OUTCOME_RESEARCH_TABLE').DataTable({
     "dom": 'ltipr',
     "data": data,
     "pageLength": 100,
     "scrollY": 150,
     "scrollX": true,
     "ordering": false
});