Javascript 在d3中通过角度绘制日期与频率的折线图
我试图在d3中制作一个简单的图表,在图中我绘制日期(作为字符串)与频率。但是,我犯了一个错误。有人能帮我吗 片段:Javascript 在d3中通过角度绘制日期与频率的折线图,javascript,angularjs,d3.js,svg,linechart,Javascript,Angularjs,D3.js,Svg,Linechart,我试图在d3中制作一个简单的图表,在图中我绘制日期(作为字符串)与频率。但是,我犯了一个错误。有人能帮我吗 片段: <html> <head> <script src="https://cdnjs.cloudflare.com/ajax/libs/angular.js/1.4.12/angular.min.js"></script> <script src="https://cdnjs.cloudflare.com/aj
<html>
<head>
<script src="https://cdnjs.cloudflare.com/ajax/libs/angular.js/1.4.12/angular.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/1.12.4/jquery.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/d3/4.3.0/d3.min.js"></script>
</head>
<body ng-app="myApp" ng-controller="myCtrl">
<svg width="1000" height="500"></svg>
<script>
//module declaration
var app = angular.module('myApp',[]);
//Controller declaration
app.controller('myCtrl', function($scope){
//custom data
var data = [
{x: "2016-01-10", y: "10.02"},
{x: "2016-02-10", y: "15.05"},
{x: "2016-03-10", y: "50.02"},
{x: "2016-04-10", y: "40.01"},
{x: "2016-05-10", y: "10.08"},
{x: "2016-06-10", y: "29.07"},
{x: "2016-07-10", y: "45.02"}
];
var mySVG = d3.select("svg");
var svgWidth = mySVG.attr("width");
var svgHeight = mySVG.attr("height");
var margins = {top: 20,right: 20,bottom: 20,left: 50};
var xRange = d3.scale.linear()
.range([margins.left, svgWidth - margins.right])
.domain([d3.min(data, function (d) {return d.x;}), d3.max(data, function (d) {return d.x;}) ]);
var yRange = d3.scale.linear()
.range([svgHeight - margins.top, margins.bottom])
.domain([d3.min(data, function (d) { return d.y; }), d3.max(data, function (d) { return d.y;}) ]);
var xAxis = d3.svg.axis()
.scale(xRange)
.tickSize(5)
.tickSubdivide(true);
var yAxis = d3.svg.axis()
.scale(yRange)
.tickSize(5)
.orient("left")
.tickSubdivide(true);
mySVG.append("svg:g")
.attr("class", "x axis")
.attr("transform", "translate(0," + (svgHeight - margins.bottom) + ")")
.call(xAxis);
mySVG.append("svg:g")
.attr("class", "y axis")
.attr("transform", "translate(" + (margins.left) + ",0)")
.call(yAxis);
var lineFunc = d3.svg.line()
.x(function (d) {
return xRange(d.x);
})
.y(function (d) {
return yRange(d.y);
})
.interpolate('linear');
mySVG.append("svg:path")
.attr("d", lineFunc(data))
.attr("stroke", "blue")
.attr("stroke-width", 2)
.attr("fill", "none");
});
</script>
</body>
</html>
<html>
<head>
<script src="https://cdnjs.cloudflare.com/ajax/libs/angular.js/1.4.12/angular.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/1.12.4/jquery.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/d3/4.3.0/d3.min.js"></script>
</head>
<body ng-app="myApp" ng-controller="myCtrl">
<svg width="1000" height="500"></svg>
<script>
//module declaration
var app = angular.module('myApp',[]);
//Controller declaration
app.controller('myCtrl', function($scope){
//custom data
var data = [
{x: "2016-01-10", y: "10.02"},
{x: "2016-02-10", y: "15.05"},
{x: "2016-03-10", y: "50.02"},
{x: "2016-04-10", y: "40.01"},
{x: "2016-05-10", y: "10.08"},
{x: "2016-05-10", y: "29.07"},
{x: "2016-05-10", y: "45.02"}
];
var mySVG = d3.select("svg");
var svgWidth = mySVG.attr("width");
var svgHeight = mySVG.attr("height");
var margins = {top: 20,right: 20,bottom: 20,left: 50};
var xRange = d3.scaleLinear()
.range([margins.left, svgWidth - margins.right])
.domain([d3.min(data, function (d) {return d.x;}), d3.max(data, function (d) {return d.x;}) ]);
var yRange = d3.scaleLinear()
.range([svgHeight - margins.top, margins.bottom])
.domain([d3.min(data, function (d) { return d.y; }), d3.max(data, function (d) { return d.y;}) ]);
var xAxis = d3.axisBottom(xRange)
.scale(xRange)
.tickSize(5);
var yAxis = d3.axisLeft(yRange)
.scale(yRange)
.tickSize(5)
.orient("left");
mySVG.append("svg:g")
.attr("class", "x axis")
.attr("transform", "translate(0," + (svgHeight - margins.bottom) + ")")
.call(xAxis);
mySVG.append("svg:g")
.attr("class", "y axis")
.attr("transform", "translate(" + (margins.left) + ",0)")
.call(yAxis);
var lineFunc = d3.line()
.x(function (d) {
return xRange(d.x);
})
.y(function (d) {
return yRange(d.y);
})
.curve(d3.curveLinear);
mySVG.append("svg:path")
.attr("d", lineFunc(data))
.attr("stroke", "blue")
.attr("stroke-width", 2)
.attr("fill", "none");
});
</script>
</body>
</html>
//模块声明
var-app=angular.module('myApp',[]);
//控制器声明
应用程序控制器('myCtrl',函数($scope){
//自定义数据
风险值数据=[
{x:“2016-01-10”,y:“10.02”},
{x:“2016-02-10”,y:“15.05”},
{x:“2016-03-10”,y:“50.02”},
{x:“2016-04-10”,y:“40.01”},
{x:“2016-05-10”,y:“10.08”},
{x:“2016-06-10”,y:“29.07”},
{x:“2016-07-10”,y:“45.02”}
];
var mySVG=d3.select(“svg”);
var svgWidth=mySVG.attr(“宽度”);
var svgHeight=mySVG.attr(“高度”);
var边距={顶部:20,右侧:20,底部:20,左侧:50};
var xRange=d3.scale.linear()
.range([margins.left,svgWidth-margins.right])
.domain([d3.min(数据,函数(d){return d.x;}),d3.max(数据,函数(d){return d.x;}]);
var yRange=d3.scale.linear()
.range([svghight-margins.top,margins.bottom])
.domain([d3.min(数据,函数(d){return d.y;}),d3.max(数据,函数(d){return d.y;}]);
var xAxis=d3.svg.axis()
.刻度(X范围)
.尺寸(5)
.tickde(真);
var yAxis=d3.svg.axis()
.刻度(Y量程)
.尺寸(5)
.东方(“左”)
.tickde(真);
追加(“svg:g”)
.attr(“类”、“x轴”)
.attr(“转换”、“转换(0)”+(svghight-margins.bottom)+”)
.呼叫(xAxis);
追加(“svg:g”)
.attr(“类”、“y轴”)
.attr(“转换”、“转换”(+(margins.left)+“,0)”)
.呼叫(yAxis);
var lineFunc=d3.svg.line()
.x(功能(d){
返回x范围(d.x);
})
.y(功能(d){
返回y范围(d.y);
})
.插入(“线性”);
追加(“svg:path”)
.attr(“d”,lineFunc(数据))
.attr(“笔划”、“蓝色”)
.attr(“笔划宽度”,2)
.attr(“填充”、“无”);
});
**错误:**
var xRange=d3.scale.linear()您使用的是d3 v4.x,而不是旧的v3。因此,您必须修改代码
这些是必要的改变:
var xRange = d3.scaleLinear()//keep the domain and range
var yRange = d3.scaleLinear()//keep the domain and range
var xAxis = d3.axisBottom(xRange)
.tickSize(5);
var yAxis = d3.axisLeft(yRange)
.tickSize(5);
var lineFunc = d3.line()//etc...
对于直线生成器,更改曲线的插值
另外,去掉tickSubdivide
编辑:您的小提琴还有其他问题:值是字符串,但它们应该是数字。除此之外,如果使用日期,则必须解析它们
这是你的小提琴,不使用日期:d3.axisLeft(…).scale(…).tickSize(…).orient不是函数你要我写小提琴吗?是的,复制它。。。所以它运行。正如你所说的,我仍然面临上述错误。我已经更新了我的代码和我面临的错误。我明白了。你为什么不做一把小提琴,这样我们就可以改变它了?毕竟,这是你的兴趣所在。我在这里得到的唯一东西是(很少)一张赞成票。
var xRange = d3.scaleLinear()//keep the domain and range
var yRange = d3.scaleLinear()//keep the domain and range
var xAxis = d3.axisBottom(xRange)
.tickSize(5);
var yAxis = d3.axisLeft(yRange)
.tickSize(5);
var lineFunc = d3.line()//etc...