Javascript NodeJS-如何中断函数?
最近有一个类似的问题,但仍然无法理解。在添加新用户之前,我必须验证注册页面Javascript NodeJS-如何中断函数?,javascript,node.js,callback,return,break,Javascript,Node.js,Callback,Return,Break,最近有一个类似的问题,但仍然无法理解。在添加新用户之前,我必须验证注册页面 app.post('/signup', function(req, res) { //checking if first name is filled if (req.body.first_name = "" || req.body.first_name = null || req.body.first_name = undefined) { res.render('signup', { "t
app.post('/signup', function(req, res) {
//checking if first name is filled
if (req.body.first_name = "" || req.body.first_name = null || req.body.first_name = undefined) {
res.render('signup', { "title": "Ttitle", "menu": "signup", user: req.user, "error" : "empty_first_name" });
break;
}
//checking if last name is filled
if (req.body.last_name = "" || req.body.last_name = null || req.body.last_name = undefined) {
res.render('signup', { "title": "Ttitle", "menu": "signup", user: req.user, "error" : "empty_last_name" });
break;
}
//checking if email is filled
if (req.body.email = "" || req.body.email = null || req.body.email = undefined) {
res.render('signup', { "title": "Ttitle", "menu": "signup", user: req.user, "error" : "empty_email" });
break;
}
//checking if passwords match
if (req.body.password != req.body.repassword) {
res.render('signup', { "title": "Ttitle", "menu": "signup", user: req.user, "error" : "pass_missmatch" });
break;
}
...
...
...
//and finally if everything seems to be OK...
addUser(req.body.email, req.body.password, req.body.first_name, req.body.last_name, req.body.country, function(status) {
res.render('signup', { "title": "Ttitle", "menu": "signup", user: req.user, "success" : 1 });
});
});
Node.JS告诉我所有的中断都是非法的。但是我应该如何以适当的方式破坏我的函数呢?它不会返回任何东西。谢谢 一个
return
语句用于停止函数
您可以提供一个可选的返回值,但在这种情况下,我相信它会被忽略,所以您应该能够替换break代码>带返回代码>
旁注,但您有大量重复代码,并且在if
条件中有赋值。你通常可以排除重复。此外,如果使用if/else if/else
语句,则可以完全去掉return
这里有一个例子
function isEmpty(val) {
return val === "" || val == null;
}
function renderWithError(req, res, msg) {
res.render('signup', { "title": "Ttitle", "menu": "signup", user: req.user, "error" : msg });
}
app.post('/signup', function(req, res) {
if (isEmpty(req.body.first_name)) {
renderWithError(req, res, "empty_first_name");
}
else if (isEmpty(req.body.last_name)) {
renderWithError(req, res, "empty_last_name");
}
else if (isEmpty(req.body.email)) {
renderWithError(req, res, "empty_email");
}
else if (req.body.password != req.body.repassword) {
renderWithError(req, res, "pass_missmatch");
}
...
...
...
else {
addUser(req.body.email, req.body.password, req.body.first_name, req.body.last_name, req.body.country, function(status) {
res.render('signup', { "title": "Ttitle", "menu": "signup", user: req.user, "success" : 1 });
});
}
});
你是说类似smth的返回空值吗?@IlyaRusanen:Justreturn代码>应该可以做到这一点。不需要提供显式返回值。