Javascript 如何在保留两个值的同时将两个对象合并到不同的数组中？_Javascript_Arrays_Json

Javascript 如何在保留两个值的同时将两个对象合并到不同的数组中？

javascript arrays json

Javascript 如何在保留两个值的同时将两个对象合并到不同的数组中？,javascript,arrays,json,Javascript,Arrays,Json,这段代码适用于一条记录，但我正试图使它适用于约500条记录的数组 var aaa = { aaa_id: 123, abbr_name: "j_doe", name: "john doe" } var bbb = { bbb_id: 789, } for (var attrname in bbb) { aaa[attrname] = bbb[attrname]; } console.log(aaa.aaa_id) 这将产生： Object {a

这段代码适用于一条记录，但我正试图使它适用于约500条记录的数组

var aaa = {
    aaa_id: 123,
    abbr_name: "j_doe",
    name: "john doe"
}
var bbb = {
    bbb_id: 789,
}


for (var attrname in bbb) {

    aaa[attrname] = bbb[attrname];

}

console.log(aaa.aaa_id)

这将产生：

Object {aaa_id: 123, abbr_name: "j_doe", name: "john doe", bbb_id: 789}

以下是我的JSON对于其他记录的外观：

var aaaRecords [   {
        "first_name": "Hasheem",
        "last_name": "Thabeet",
        "aaa_player_id": "4562"
    },
    ...
]

var bbbRecords [{
        "first_name": "Hasheem",
        "last_name": "Thabeet",
        "aaa_player_id": "4562"
    },
    ....
]

关于如何使这个函数与这些数组一起工作，有什么想法吗？非常感谢你的帮助

这已经过测试：

<html>
<head>
    <script src="//ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
    <script language="javascript">

        var aaaRecords = [{
            "first_name": "Hasheem",
            "last_name": "Thabeet",
            "aaa_player_id": "456"
        },{
            "first_name": "Mariah",
            "last_name": "Carey",
            "aaa_player_id": "721"
        }];

        var bbbRecords = [{
            "first_name": "Hasheem",
            "last_name": "Thabeet",
            "bbb_player_id": "489"
        },{
            "first_name": "Mariah",
            "last_name": "Carey",
            "bbb_player_id": "198"
        }];

        $(document).ready(function() {
            mergeRecords(function() {
                displayRecords();
            });
        });

        function mergeRecords(callback) {
            for (var i = 0; i < aaaRecords.length; i++) {
                aFName = aaaRecords[i].first_name;
                aLName = aaaRecords[i].last_name;
                for (var j = 0; j < bbbRecords.length; j++) {
                    bFName = bbbRecords[j].first_name;
                    bLName = bbbRecords[j].last_name;
                    bPlayerID = bbbRecords[j].bbb_player_id;
                    if (aFName == bFName && aLName == bLName) {
                        aaaRecords[i].bbb_player_id = bPlayerID;
                    }
                }
            } callback();
        }

        function displayRecords() {
            for (var i = 0; i < aaaRecords.length; i++) {
                $('#results').append('<tr><td>' + 
                    aaaRecords[i].first_name + '</td><td>' +
                    aaaRecords[i].last_name + '</td><td>' +
                    aaaRecords[i].aaa_player_id + '</td><td>' +
                    aaaRecords[i].bbb_player_id + '</td></tr>');
            }
        }

    </script>
</head>

<body>
    <table id="results" border="1" cellpadding="2" cellspacing="2" width="400">
        <tr>
            <th>First Name:</th>
            <th>Last Name:</th>
            <th>Player ID (a):</th>
            <th>Player ID (b):</th>
        </tr>
        <!-- Display results here -->
    </table>
</body>
</html>


var aaaRecords=[{
“名字”：“哈希姆”，
“姓氏”：“Thabeet”，
“aaa玩家id”：“456”
},{
“名字”：“玛丽亚”，
“姓”：“凯莉”，
“aaa玩家id”：“721”
}];
变量bbbRecords=[{
“名字”：“哈希姆”，
“姓氏”：“Thabeet”，
“BBU玩家id”：“489”
},{
“名字”：“玛丽亚”，
“姓”：“凯莉”，
“BBU玩家id”：“198”
}];
$（文档）.ready（函数（）{
合并记录（函数（）{
显示记录（）；
});
});
函数合并记录（回调）{
对于（变量i=0；i


结果输出：
阵列的长度是否相同？是否只有两个数组？不，数组的长度不同，但将只有两个数组如果数组不平行，则不清楚应该如何执行合并。我会使用下划线示例，看看是否找不到可以修改的相近内容。