Javascript 当来自两个diff对象的两个值匹配时，向对象添加新的键/对
我已经映射并过滤了两个对象。我的思想遇到了障碍。当值匹配时，我看不到如何将键/值从一个对象添加到另一个对象 这种类型对我来说是相当新鲜的，并且会让我的逻辑思维陷入困境，所以任何帮助都将不胜感激 我想将'lat'和'lon'值以及'TodaySdapAtPostCode'对象中的键添加到'data'对象中 这应该在邮政编码匹配时进行 我用的是我以前用过的方法，但最后的阶段是不同的，很难弄清楚 代码如下：Javascript 当来自两个diff对象的两个值匹配时，向对象添加新的键/对,javascript,arrays,reactjs,object,ecmascript-6,Javascript,Arrays,Reactjs,Object,Ecmascript 6,我已经映射并过滤了两个对象。我的思想遇到了障碍。当值匹配时，我看不到如何将键/值从一个对象添加到另一个对象 这种类型对我来说是相当新鲜的，并且会让我的逻辑思维陷入困境，所以任何帮助都将不胜感激 我想将'lat'和'lon'值以及'TodaySdapAtPostCode'对象中的键添加到'data'对象中 这应该在邮政编码匹配时进行 我用的是我以前用过的方法，但最后的阶段是不同的，很难弄清楚 代码如下： addLatLon = (location, latLon) => {
addLatLon = (location, latLon) => {
return location.map(compiledDataObj => {
const objectsWithSameLocation = latLon.filter(dataObj => {
return dataObj.postcode === compiledDataObj.postcode;
});
objectsWithSameLocation.map(obj => {
//here we want to match the postcode of the object we're running through
// so its like
compiledDataObj.postcode[obj.postcode]
// return console.log('location.postcode', location.map(i => i.postcode), 'obj.postcode', obj.postcode)
});
});
};
[
{
"location": "City of London",
"postcode": "EC1A 7BE",
"year": {
"10": "464436",
"11": "442413",
"12": "525723",
"13": "465451",
"14": "625001",
"15": "783667",
"16": "736788",
"17": "820305",
"18": "802129",
"19": "864034",
"95": "91449",
"96": "108999",
"97": "116343",
"98": "124382",
"99": "149143",
"00": "173738",
"01": "284262",
"02": "344239",
"03": "261645",
"04": "326913",
"05": "330363",
"06": "316121",
"07": "360923",
"08": "471861",
"09": "400317"
}
},
{
"location": "Barking & Dagenham",
"postcode": "RM9 4TP",
"year": {
"10": "162905",
"11": "163821",
"12": "163899",
"13": "167919",
"14": "184884",
"15": "220070",
"16": "258758",
"17": "282441",
"18": "291548",
"19": "298333",
"95": "50460",
"96": "50828",
"97": "54459",
"98": "57559",
"99": "64532",
"00": "71079",
"01": "82343",
"02": "98713",
"03": "134750",
"04": "150115",
"05": "164484",
"06": "162340",
"07": "176577",
"08": "194235",
"09": "166798"
}
}]
[{
"postcode": "EC1A 7BE",
"longitude": -0.100404,
"latitude": 51.51775
},
{
"postcode": "RM9 4TP",
"longitude": 0.127884,
"latitude": 51.539774
},
{
"postcode": "EN5 5RP",
"longitude": -0.194074,
"latitude": 51.65044
},
{
"postcode": "DA16 3DN",
"longitude": 0.102535,
"latitude": 51.464737
},
{
"postcode": "HA9 9AA",
"longitude": -0.279243,
"latitude": 51.563322
},
{
"postcode": "BR1 3NN",
"longitude": 0.017131,
"latitude": 51.40827
},
{
"postcode": "NW1 8QL",
"longitude": -0.142696,
"latitude": 51.53929
},
{
"postcode": "CR2 7PA",
"longitude": -0.094105,
"latitude": 51.36292
}]
这应该在邮政编码匹配时进行。”这就是你一直在追求的吗
const arr1=[{“地点”：“伦敦市”，“邮政编码”：“EC1A 7BE”，“年份”：“10”：“464436”，“11”：“442413”，“12”：“525723”，“13”：“465451”，“14”：“625001”，“15”：“783667”，“16”：“736788”，“17”：“820305”，“18”：“802129”，“19”：“864034”，“95”：“91449”，“96”：“108999”，“97”：“116343”，“98”：“124382”，“99”：“14914343”，“00”：“173738”，“01”284262”，“16403”，“2603”：“326913”、“05”：“330363”、“06”：“316121”、“07”：“360923”、“08”：“471861”、“09”：“400317”}、{“地点”：“Barking&Dagenham”、“邮政编码”：“RM9 4TP”、“年份”：{“10”：“162905”、“11”：“163821”、“12”：“163899”、“13”：“167919”、“14”：“184884”、“15”：“220070”、“16”：“258758”、“17”：“282441”、“18”：“291548”、“19”：“298333”、“95”：“50460”、“50828”、“549”、“539”：“539”：”00":"71079","01":"82343","02":"98713","03":"134750","04":"150115","05":"164484","06":"162340","07":"176577","08":"194235","09":"166798"}}];
const arr2=[{“邮政编码”：“EC1A 7BE”，“经度”：-0.100404，“纬度”：51.51775}，{“邮政编码”：“RM9 4TP”，“经度”：0.127884，“纬度”：51.539774}，{“邮政编码”：“EN5 5RP”，“经度”：-0.194074，“纬度”：51.65044}，{“邮政编码”：“DA16 3DN”，“经度”：0.102535，“纬度”：51.464737}，{“邮政编码”：“HA9 9AA”，“经度”：0.279，“经度”：51.563322}邮政编码：“BR1 3NN”，“经度”：0.017131，“纬度”：51.40827}，{“邮政编码”：“NW1 8QL”，“经度”：-0.142696，“纬度”：51.53929}，{“邮政编码”：“CR2 7PA”，“经度”：-0.094105，“纬度”：51.36292}；
const merged=arr1.map（e=>（coords=arr2.find（ee=>ee.postcode==e.postcode），Object.assign（e，{经度：coords['longitude']，纬度：coords['latitude']}））；
console.log（合并）；.as console wrapper{min height:100%}