Javascript 在php中从ajax获取数据

我是ajax新手，遇到了一个问题。我想将结果列表中单击的元素的id发布到另一个页面（在localhost中）。当我想从ajax数据中获取发布的id时，我会得到未定义的索引id（即$id=$\u POST['id']）。我怎样才能解决这个问题

我感谢任何帮助或建议

index.php

<section id= "searchbar">
        <form method="get" action="index.php" name="myForm" id="myForm">
            <h3>Search</h3>
        <table>
            <tr>
                <td><input id="wilaya" type="text" name="wilaya" class="resizedTextbox" placeholder="Choose your Wilaya"></td>
                <td><input id="surface" type="text" name="surface" class="resizedTextbox" placeholder="Choose the surface"></td>
                <td><input id="search" type="submit" class="resizedTextbox" value="Search"></td>
            </tr>

        </table>
    </form>
    </section>




     <section id="resultlist">
            <table width="100%" height="90%" id="table1">
                <thead>
                    <tr>
                    </tr>
                </thead>

                <?php
                $array[] = null;
                $i = 1;
                while ($results = mysql_fetch_assoc($result)) {
                    ?>
                    <tr>

                    <div class="round-button">
                        <!--echo '<img name= "house" class= "imagehouse" src="images/' . $results['photo'] . '" id=' . $results['id'] . ''-->   
                        <?php echo "<img src= images/" . $results['photo'] . " width='50' id=" . $results['id'] . " />"; ?>
                        <td id="nametable" width="10%"> <?php echo $results['name']; ?></td>
                        <td id="wilayatable"width="10%"><?php echo $results['wilaya']; ?></td>
                        <td width="10%"><?php echo $results['surface'] . " m²"; ?></td> 
                        </tr>
                        <?php
                        $i++;
                    }
                }
                ?>
        </table>
    </section>

    <?php
//extract data from the post
//set POST variables
        $url = 'http://localhost/testcurl.php';

        $fields = array(
            'wilaya' => urlencode($_POST['wilaya']),
            'id' => urlencode($_POST['id']),
        );

//url-ify the data for the POST
        foreach ($fields as $key => $value) {
            $fields_string .= $key . '=' . $value . '&';
        }
        rtrim($fields_string, '&');

//open connection
        $ch = curl_init();

//set the url, number of POST vars, POST data
        curl_setopt($ch, CURLOPT_URL, $url);
        curl_setopt($ch, CURLOPT_POST, count($fields));
        curl_setopt($ch, CURLOPT_POSTFIELDS, $fields_string);

//execute post
        $result = curl_exec($ch);

//close connection
        curl_close($ch);
        ?>
    <?php
    var_dump($_POST['id']);
    ?>

testcurl.php

在这里，我向服务器发送了一个post-the-id

<?php

$url = "http://localhost/testcurlserver.php";// where you want to post data

$wilaya = isset($_POST['wilaya']);
$id = isset($_POST['id']);
$fields = array(
    'wilaya' => urlencode($_POST['wilaya']),
    'id' => urlencode($_POST['id']),

);

//url-ify the data for the POST
foreach($fields as $key=>$value) { $fields_string .= $key.'='.$value.'&'; }
rtrim($fields_string, '&');

//open connection
$ch = curl_init();

//set the url, number of POST vars, POST data
curl_setopt($ch,CURLOPT_URL, $url);
curl_setopt($ch,CURLOPT_POST, count($fields));
curl_setopt($ch,CURLOPT_POSTFIELDS, $fields_string);

//execute post
$result = curl_exec($ch);

//close connection
curl_close($ch);

var_dump($output); // show output

?>

---

请在代码顶部键入

if (! is_array($_POST)) {
   $_POST = json_decode(file_get_contents('php://input'), true);
}

---

在尝试之后，我现在找到了一个解决方案，这就是为什么我想在这里分享它。我使用类似（$.post）的ajax帖子发布id，并在id为'content'的div中获取响应

<div id="content" style ="border: 1px solid red;">

</div>

<script type="text/javascript">

    $('img').click(function () {
        alert(this.id);
        var id = this.id;

        $.post('testcurlserver.php', {'id': id}, function (data) {
                $('#content').html(data);
            });
        });

$（'img'）。单击（函数（）{
警报（this.id）；
var id=this.id；
$.post（'testcurlserver.php'，{'id'：id}，函数（数据）{
$（'#content'）.html（数据）；
});
});

@Xatenev在那之后不是3行！我在index.php中得到了未定义的索引，在这里我制作了curl post，我将添加通知。@Jeff你说的在那之后三行是什么意思？“不是在那之后三行！”是对删除的评论的回答。这里

'id'=>urlencode（$\u POST['id']）

您不检查

$\u POST['id']

isset@Jeff是的，你说得对！与此同时，我找到了一个解决方案，并将其发布在这里。谢谢：）在我的curl请求中，我没有将数据类型定义为json，或者是默认值？

Notice: Undefined index: id in C:\xampp\htdocs\index.php on line 122 
Notice: Undefined variable: fields_string in C:\xampp\htdocs\index.php on line 127 
  Notice: Undefined variable: fields_string in
  C:\xampp\htdocs\testcurl.php on line 14 string(0) "" it worked Notice:
  Undefined variable: output in C:\xampp\htdocs\testcurl.php on line 31
  NULL  
Notice: Undefined index: id in C:\xampp\htdocs\index.php on line
  147 NULL

if (! is_array($_POST)) {
   $_POST = json_decode(file_get_contents('php://input'), true);
}

<div id="content" style ="border: 1px solid red;">

</div>

<script type="text/javascript">

    $('img').click(function () {
        alert(this.id);
        var id = this.id;

        $.post('testcurlserver.php', {'id': id}, function (data) {
                $('#content').html(data);
            });
        });