Javascript 使用JSON创建数组

我正在用谷歌地图api创建地图

基本上，调用任何标记的数组结构如下所示：

var station = [
['SEDRANO DI SAN QUIRINO (PN)',46.048887,12.657924,'Via Maniago, 28','Tel. 0434 918900','sedrano-di-san-quirino.jpg',true,true,false,false,false,false,false],
['CORTINA D\'AMPEZZO (BL)',46.541307,12.132348,'Via dello Stadio, 7','Tel.  0436 869133','cortina-dampezzo.jpg',true,true,false,false,false,true,false],
['POINCICCO DI ZOPPOLA (PN)',45.948725,12.745332,'Via Cusano, 14','Tel. 0434 574831','poinciccio-di-zoppola.jpg',true,true,false,false,false,true,false]
];

现在，我将使用json调用创建一个数组，所以第一步我使用php调用标记，并将它们放入json_encode中

$sth = mysql_query("SELECT * FROM markers");
$rows = array();
 while($r = mysql_fetch_assoc($sth)) {
  $rows[] = $r;
 }
print json_encode($rows);

结果

[{"city":"SEDRANO DI SAN QUIRINO (PN)","lat":"46.0489","lng":"12.6579","address":"Via Maniago, 28","phone":"Tel. 0434 918900","thumb":"http:\/\/www.costantin.com\/images\/thumb\/maps\/sedrano-di-san-quirino.jpg","top-verde":"false","top-diesel":"false","gpl":"false","lavaggio":"false","cafe":"false","verde":"true","diesel":"true","id":"1"},{"city":"CORTINA D'AMPEZZO (BL)","lat":"46.5413","lng":"12.1323","address":"Via dello Stadio, 7","phone":"Tel. 0436 869133","thumb":"http:\/\/www.costantin.com\/images\/thumb\/maps\/cortina-dampezzo.jpg","top-verde":"false","top-diesel":"false","gpl":"false","lavaggio":"true","cafe":"false","verde":"true","diesel":"true","id":"2"},{"city":"POINCICCO DI ZOPPOLA (PN)","lat":"45.9487","lng":"12.7453","address":"Via Cusano, 14","phone":"Tel. 0434 574831","thumb":"http:\/\/www.costantin.com\/images\/thumb\/maps\/poinciccio-di-zoppola.jpg","top-verde":"false","top-diesel":"false","gpl":"false","lavaggio":"true","cafe":"false","verde":"true","diesel":"true","id":"3"}]

第二步我使用jquery getJSON数据调用，如下所示

$.getJSON( "markers.php", function( data ) {
    var station = [];
  $.each( data, function( key, val ) {
    station.push( data );
  });
});

但这完全没用了，所以。。。我用哪种方法能做到？ 所以有没有办法完成这个结构

  var station = [
    ['SEDRANO DI SAN QUIRINO (PN)',46.048887,12.657924,'Via Maniago, 28','Tel. 0434 918900','sedrano-di-san-quirino.jpg',true,true,false,false,false,false,false],
    ['CORTINA D\'AMPEZZO (BL)',46.541307,12.132348,'Via dello Stadio, 7','Tel.  0436 869133','cortina-dampezzo.jpg',true,true,false,false,false,true,false],
    ['POINCICCO DI ZOPPOLA (PN)',45.948725,12.745332,'Via Cusano, 14','Tel. 0434 574831','poinciccio-di-zoppola.jpg',true,true,false,false,false,true,false]
    ];

var站=[]//您需要一个外部变量来保存所有桩号
$.getJSON（“markers.php”，函数（数据）{
//var station=[]；//这里不需要这个
//“数据”是一个数组，不是键/值对象
/*$。每个（数据、函数（键、值）{
//这里添加的是JSON“数据”数组，而不是值
站推（数据）；
});*/
//请记住，“数据”是一个JSON数组，而不是对象
对于（var i=0；i

不要获取关联数组如果只关心数组值，请尝试以下操作：

$rows = array();
 while($r = mysql_fetch_array($sth)) {
  $rows[] = array_values($r);
 }
print json_encode($rows);

根据您的目标，它不是有效的json对象。

$rows = array();
 while($r = mysql_fetch_array($sth)) {
  $rows[] = array_values($r);
 }
print json_encode($rows);