Javascript 如何在此日历UI中禁用周末

我从DavidWalsh实现中修改了这个示例代码，我的目标是禁用周末Sat和Sun的按钮。我在实施它时遇到了一些困难。我希望有人能帮我解决我的问题`

<?php
/*
* Calendar from David Walsh's implementation: http://davidwalsh.name/php-calendar
*/

if(isset($_REQUEST["date"])){

    // Get the variable
    $chosenDate = explode("/",$_REQUEST["date"]);
    $month = $chosenDate[0];
    $year = $chosenDate[1];

    // Check browser
    if(isset($_SERVER['HTTP_USER_AGENT'])){
        $agent = $_SERVER['HTTP_USER_AGENT'];
    }

    /* 
    * Draws the calendar 
    */

    // Draw table 
    $calendar = '<table cellpadding="0" cellspacing="0" class="calendar">';

    // Table headings 
    $headings = array('S','M','T','W','Th','F','S');
    $calendar.= '<tr><td class="calendar-day-head">'.implode('</td><td class="calendar-day-head">',$headings).'</td></tr>';

    // Variables to be used
    $running_day = date('w',mktime(0,0,0,$month,1,$year));
    $days_in_month = date('t',mktime(0,0,0,$month,1,$year));
    $days_in_this_week = 1;
    $day_counter = 0;
    $current_date = explode("/",date('m/j/Y')); //Gets the current date 
    $dates_array = array();

    // Row for week one 
    $calendar.= '<tr class="calendar-row">';

    // Print "blank" days until the first of the current week 
    for($x = 0; $x < $running_day; $x++):
        $calendar.= '<td class="calendar-day-np"> </td>';
        $days_in_this_week++;
    endfor;

    // Keep going with days...
    for($list_day = 1; $list_day <= $days_in_month; $list_day++):

        // This checks current day so that past days will never be picked
        if($list_day < $current_date[1] && $month == $current_date[0] && $year == $current_date[2])
            $calendar.= '<td class="calendar-day2">';
        else{
            if(stristr($agent,"firefox")) $value = 'this.textContent';
            else $value = 'innerText';
            $calendar.= '<td class="calendar-day" onclick="redirect_to_sample('.$value.')">';
        }

        // Add in the day number
        if($list_day < $current_date[1] && $month == $current_date[0] && $year == $current_date[2])
            $calendar.= '<div class="day-number2">'.$list_day.'</div>';
        else if($list_day == $current_date[1] && $month == $current_date[0] && $year == $current_date[2])
            $calendar.= '<div class="day-number"><u>'.$list_day.'</u></div>';
        else 
            $calendar.= '<div class="day-number">'.$list_day.'</div>';      

        // For further SQLs put here
        $calendar.= str_repeat('<p></p>',2);

        $calendar.= '</td>';

        if($running_day == 6):
            $calendar.= '</tr>';
            if(($day_counter+1) != $days_in_month):
                $calendar.= '<tr class="calendar-row">';
            endif;
            $running_day = -1;
            $days_in_this_week = 0;
        endif;
        $days_in_this_week++; $running_day++; $day_counter++;
    endfor;

    // Finish the rest of the days in the week 
    if($days_in_this_week < 8 && $days_in_this_week != 1):
        for($x = 1; $x <= (8 - $days_in_this_week); $x++):
            $calendar.= '<td class="calendar-day-np"> </td>';
        endfor;
    endif;

    // Final row 
    $calendar.= '</tr>';

    // End the table 
    $calendar.= '</table>';

    // All done, return result 
    echo $calendar;
}


   ?>`

---

看起来
$running\u day
正在跟踪一周中的哪一天。0=周六&6=周日，因此您可以利用这一点

请尝试以下操作：

// This checks current day so that past days will never be picked
if($list_day < $current_date[1] && $month == $current_date[0] && $year == $current_date[2])
      $calendar.= '<td class="calendar-day2">';}
elseif($running_day == 0 || $running_day == 6) //Check for weekend
{
     $calendar.= '<td class="calendar-day weekend">';    } 
else{
        if(stristr($agent,"firefox")) $value = 'this.textContent';
        else $value = 'innerText';
        $calendar.= '<td class="calendar-day" onclick="redirect_to_sample('.$value.')">';
}

//这将检查当前日期，以便永远不会拾取过去的日期
如果（$list_day<$current_date[1]&&$month==$current_date[0]&&$year==$current_date[2]）
$calendar.=''；}
elseif（$running_day==0 | |$running_day==6）//检查周末
{
$calendar.=''；}
否则{
if（stristr（$agent，“firefox”）$value='this.textContent'；
else$value='innerText'；
$calendar.=''；
}

我已经检查了weekend，创建了一个不同的
td
标记，其中包含weekend的附加css类，这样您就可以为weekend添加一些附加样式

请注意，我还没有测试过这一点，只是做了一点猜测。
如何实现它？所有禁用的日期都在这个类中。问题不涉及
datepicker
jquery插件。这是一个php实现。在回答之前，你应该更仔细地阅读这个问题。我已经弄明白了：只需将（$running|u day==0 |$$running|u day==6）添加到if（$list|u day<$current_date[1]&&&$month=$current_date[0]&$year==current| date[2]）我已经弄明白了：只需将（$running|（$running| day==0 | running| day==0&$running| day==6））添加到if中即可(（$list_day<$current_date[1]&&&$month==$current_date[0]&&$year=$current_date[2]）这是一个可能的解决方案，但为了使事情更简单，只需将（$running_day==0 | running_day==6））添加到if（$list_day<$current_date[1]&$month=$current_date[0]&$year=$current_date[2]）@tomjerry，这是我最初的想法，但你可能希望与过去的日期不同地处理周末。例如，除了样式设置之外，你还可以添加标题属性以提供一些反馈
title='请选择一个工作日'
// This checks current day so that past days will never be picked
if($list_day < $current_date[1] && $month == $current_date[0] && $year == $current_date[2])
      $calendar.= '<td class="calendar-day2">';}
elseif($running_day == 0 || $running_day == 6) //Check for weekend
{
     $calendar.= '<td class="calendar-day weekend">';    } 
else{
        if(stristr($agent,"firefox")) $value = 'this.textContent';
        else $value = 'innerText';
        $calendar.= '<td class="calendar-day" onclick="redirect_to_sample('.$value.')">';
}