Javascript 如何按多个字段对对象数组进行排序?
由此,我将如何对多个字段应用排序 使用这个稍加调整的结构,我将如何对城市(升序)和价格(降序)进行排序 我喜欢这个事实,而不是给出一个提供了一般方法的答案。在我计划使用这段代码的地方,我必须对日期和其他事情进行排序。“初始化”对象的功能似乎很方便,如果不是有点麻烦的话Javascript 如何按多个字段对对象数组进行排序?,javascript,arrays,sorting,Javascript,Arrays,Sorting,由此,我将如何对多个字段应用排序 使用这个稍加调整的结构,我将如何对城市(升序)和价格(降序)进行排序 我喜欢这个事实,而不是给出一个提供了一般方法的答案。在我计划使用这段代码的地方,我必须对日期和其他事情进行排序。“初始化”对象的功能似乎很方便,如果不是有点麻烦的话 我试图将其构建成一个很好的通用示例,但运气不太好。多维排序方法: 更新:这是一个“优化”版本。它会进行更多的预处理,并预先为每个排序选项创建一个比较函数。它可能需要更多的内存(因为它为每个排序选项存储了一个函数,但它的性能应该更好
我试图将其构建成一个很好的通用示例,但运气不太好。多维排序方法: 更新:这是一个“优化”版本。它会进行更多的预处理,并预先为每个排序选项创建一个比较函数。它可能需要更多的内存(因为它为每个排序选项存储了一个函数,但它的性能应该更好一些,因为它不必在比较过程中确定正确的设置。不过,我没有做任何分析
var sort_by;
(function() {
// utility functions
var default_cmp = function(a, b) {
if (a == b) return 0;
return a < b ? -1 : 1;
},
getCmpFunc = function(primer, reverse) {
var dfc = default_cmp, // closer in scope
cmp = default_cmp;
if (primer) {
cmp = function(a, b) {
return dfc(primer(a), primer(b));
};
}
if (reverse) {
return function(a, b) {
return -1 * cmp(a, b);
};
}
return cmp;
};
// actual implementation
sort_by = function() {
var fields = [],
n_fields = arguments.length,
field, name, reverse, cmp;
// preprocess sorting options
for (var i = 0; i < n_fields; i++) {
field = arguments[i];
if (typeof field === 'string') {
name = field;
cmp = default_cmp;
}
else {
name = field.name;
cmp = getCmpFunc(field.primer, field.reverse);
}
fields.push({
name: name,
cmp: cmp
});
}
// final comparison function
return function(A, B) {
var a, b, name, result;
for (var i = 0; i < n_fields; i++) {
result = 0;
field = fields[i];
name = field.name;
result = field.cmp(A[name], B[name]);
if (result !== 0) break;
}
return result;
}
}
}());
原始功能:
homes.sort(sort_by('city', {name:'price', primer: parseInt, reverse: true}));
var sort_by = function() {
var fields = [].slice.call(arguments),
n_fields = fields.length;
return function(A,B) {
var a, b, field, key, primer, reverse, result, i;
for(i = 0; i < n_fields; i++) {
result = 0;
field = fields[i];
key = typeof field === 'string' ? field : field.name;
a = A[key];
b = B[key];
if (typeof field.primer !== 'undefined'){
a = field.primer(a);
b = field.primer(b);
}
reverse = (field.reverse) ? -1 : 1;
if (a<b) result = reverse * -1;
if (a>b) result = reverse * 1;
if(result !== 0) break;
}
return result;
}
};
const createSorter = (...sorters) => (a, b) =>
sorters.reduce(
(d, fn) => (d === 0 ? fn(a, b) : d),
0
);
var sort_by=function(){
变量字段=[].slice.call(参数),
n_fields=fields.length;
返回函数(A,B){
变量a、b、字段、键、引物、反转、结果、i;
对于(i=0;i
这里还有一个可能更接近您对语法的理解
function sortObjects(objArray, properties /*, primers*/) {
var primers = arguments[2] || {}; // primers are optional
properties = properties.map(function(prop) {
if( !(prop instanceof Array) ) {
prop = [prop, 'asc']
}
if( prop[1].toLowerCase() == 'desc' ) {
prop[1] = -1;
} else {
prop[1] = 1;
}
return prop;
});
function valueCmp(x, y) {
return x > y ? 1 : x < y ? -1 : 0;
}
function arrayCmp(a, b) {
var arr1 = [], arr2 = [];
properties.forEach(function(prop) {
var aValue = a[prop[0]],
bValue = b[prop[0]];
if( typeof primers[prop[0]] != 'undefined' ) {
aValue = primers[prop[0]](aValue);
bValue = primers[prop[0]](bValue);
}
arr1.push( prop[1] * valueCmp(aValue, bValue) );
arr2.push( prop[1] * valueCmp(bValue, aValue) );
});
return arr1 < arr2 ? -1 : 1;
}
objArray.sort(function(a, b) {
return arrayCmp(a, b);
});
}
// just for fun use this to reverse the city name when sorting
function demoPrimer(str) {
return str.split('').reverse().join('');
}
// Example
sortObjects(homes, ['city', ['price', 'desc']], {city: demoPrimer});
以下函数将允许您对一个或多个属性上的对象数组进行升序(默认)或降序排序,并允许您选择是否执行区分大小写的比较。默认情况下,此函数执行不区分大小写的排序 第一个参数必须是包含对象的数组。 后续参数必须是引用不同对象属性进行排序的字符串的逗号分隔列表。最后一个参数(可选)是一个布尔值,用于选择是否执行区分大小写的排序-使用
true
进行区分大小写的排序
默认情况下,该函数将按升序对每个属性/键进行排序。如果希望某个特定键按降序排序,请改为按以下格式传入数组:['property\u name',true]
下面是函数的一些示例用法,并附有说明(其中homes
是包含对象的数组):
objSort(homes,'city')
-->按城市排序(升序,区分大小写)
objSort(homes,['city',true])
-->按城市排序(降序,区分大小写)
objSort(homes,'city',true)
-->按城市排序,然后按价格排序(升序,区分大小写)
objSort(房屋,'city','price')
-->先按城市排序,然后按价格排序(两者都是升序,区分大小写)
objSort(homes,'city',['price',true])
-->按城市(升序)排序,然后按价格(降序)排序,区分大小写)
不用多说,下面是函数:
function objSort() {
var args = arguments,
array = args[0],
case_sensitive, keys_length, key, desc, a, b, i;
if (typeof arguments[arguments.length - 1] === 'boolean') {
case_sensitive = arguments[arguments.length - 1];
keys_length = arguments.length - 1;
} else {
case_sensitive = false;
keys_length = arguments.length;
}
return array.sort(function (obj1, obj2) {
for (i = 1; i < keys_length; i++) {
key = args[i];
if (typeof key !== 'string') {
desc = key[1];
key = key[0];
a = obj1[args[i][0]];
b = obj2[args[i][0]];
} else {
desc = false;
a = obj1[args[i]];
b = obj2[args[i]];
}
if (case_sensitive === false && typeof a === 'string') {
a = a.toLowerCase();
b = b.toLowerCase();
}
if (! desc) {
if (a < b) return -1;
if (a > b) return 1;
} else {
if (a > b) return -1;
if (a < b) return 1;
}
}
return 0;
});
} //end of objSort() function
var data = [
{
"id": 1,
"ship": null,
"product": "Orange",
"quantity": 7,
"price": 92.08,
"discount": 0
},
{
"id": 2,
"ship": "2017-06-14T23:00:00.000Z".toDate(),
"product": "Apple",
"quantity": 22,
"price": 184.16,
"discount": 0
},
...
]
var sorts = ["product", "quantity", "ship"]
// comp_val formats values and protects against comparing nulls/undefines
// type() just returns the variable constructor
// String.lower just converts the string to lowercase.
// String.toDate custom fn to convert strings to Date
function comp_val(value){
if (value==null || value==undefined) return null
var cls = type(value)
switch (cls){
case String:
return value.lower()
}
return value
}
function compare(a, b, i){
i = i || 0
var prop = sorts[i]
var va = comp_val(a[prop])
var vb = comp_val(b[prop])
// handle what to do when both or any values are null
if (va == null || vb == null) return true
if ((i < sorts.length-1) && (va == vb)) {
return compare(a, b, i+1)
}
return va > vb
}
var d = data.sort(compare);
console.log(d);
今天我做了一个非常通用的多功能分类器。您可以在此处查看thenBy.js:
它允许您使用标准的Array.sort,但使用firstBy().thenBy().thenBy()样式。与上面发布的解决方案相比,它的代码和复杂性要少得多。对于您的确切问题的非通用、简单的解决方案:
homes.sort(
function(a, b) {
if (a.city === b.city) {
// Price is only important when cities are the same
return b.price - a.price;
}
return a.city > b.city ? 1 : -1;
});
以下是@Snowburn解决方案的通用版本:
var sortarray = [{field:'city', direction:'asc'}, {field:'price', direction:'desc'}];
array.sort(function(a,b){
for(var i=0; i<sortarray.length; i++){
retval = a[sortarray[i].field] < b[sortarray[i].field] ? -1 : a[sortarray[i].field] > b[sortarray[i].field] ? 1 : 0;
if (sortarray[i].direction == "desc") {
retval = retval * -1;
}
if (retval !== 0) {
return retval;
}
}
}
})
var-sortarray=[{字段:'city',方向:'asc'},{字段:'price',方向:'desc'}];
array.sort(函数(a,b){
对于(VARI=0;IB[Sortaray[i].字段]?1:0;
if(sortarray[i].方向==“desc”){
retval=retval*-1;
}
如果(返回值!==0){
返回返回;
}
}
}
})
这是基于我正在使用的一个排序例程。我没有测试这个特定的代码,所以它可能会有错误,但你得到了这个想法。这个想法是根据指示差异的第一个字段进行排序,然后停止并转到下一条记录。因此,如果你按三个字段进行排序,比较中的第一个字段就足以确定排序顺序然后返回排序结果并转到下一条记录
我在5000条记录上测试了它(实际上使用了更复杂的排序逻辑),它在一眨眼的功夫就完成了。如果你真的要将1000多条记录加载到客户端,你可能应该使用服务器端排序和筛选
这段代码不区分大小写,但我把它留给读者来处理这个琐碎的修改。这里是一个简单的函数方法。使用array.Prepend减号指定排序顺序以指定降序
var homes = [
{"h_id":"3", "city":"Dallas", "state":"TX","zip":"75201","price":"162500"},
{"h_id":"4","city":"Bevery Hills", "state":"CA", "zip":"90210", "price":"319250"},
{"h_id":"6", "city":"Dallas", "state":"TX", "zip":"75000", "price":"556699"},
{"h_id":"5", "city":"New York", "state":"NY", "zip":"00010", "price":"962500"}
];
homes.sort(fieldSorter(['city', '-price']));
// homes.sort(fieldSorter(['zip', '-state', 'price'])); // alternative
function fieldSorter(fields) {
return function (a, b) {
return fields
.map(function (o) {
var dir = 1;
if (o[0] === '-') {
dir = -1;
o=o.substring(1);
}
if (a[o] > b[o]) return dir;
if (a[o] < b[o]) return -(dir);
return 0;
})
.reduce(function firstNonZeroValue (p,n) {
return p ? p : n;
}, 0);
};
}
var homes=[
{“h_id”:“3”,“城市”:“达拉斯”,“州”:“德克萨斯州”,“邮编”:“75201”,“价格”:“162500”},
{“h_id”:“4”,“城市”:“贝弗里山”,“州”:“CA”,“邮编”:“90210”,“价格”:“319250”},
{“h_id”:“6”,“城市”:“达拉斯”,“州”:“德克萨斯州”,“邮编”:“75000”,“价格”:“556699”},
{“h_id”:“5”,“城市”:“纽约”,“州”:“纽约”,“邮编”:“00010”,“价格”:“962500”}
];
排序(fieldSorter(['city','-price']);
//排序(fieldSorter(['zip','-state',price']);//可选
功能字段分类器(字段){
返回函数(a,b){
返回字段
.map(功能(o){
var-dir=1;
如果(o[0]=='-'){
dir=-1;
o=o.子串(1);
}
如果(a[o]>b[o])返回dir;
如果(a[o]var sortarray = [{field:'city', direction:'asc'}, {field:'price', direction:'desc'}];
array.sort(function(a,b){
for(var i=0; i<sortarray.length; i++){
retval = a[sortarray[i].field] < b[sortarray[i].field] ? -1 : a[sortarray[i].field] > b[sortarray[i].field] ? 1 : 0;
if (sortarray[i].direction == "desc") {
retval = retval * -1;
}
if (retval !== 0) {
return retval;
}
}
}
})
var homes = [
{"h_id":"3", "city":"Dallas", "state":"TX","zip":"75201","price":"162500"},
{"h_id":"4","city":"Bevery Hills", "state":"CA", "zip":"90210", "price":"319250"},
{"h_id":"6", "city":"Dallas", "state":"TX", "zip":"75000", "price":"556699"},
{"h_id":"5", "city":"New York", "state":"NY", "zip":"00010", "price":"962500"}
];
homes.sort(fieldSorter(['city', '-price']));
// homes.sort(fieldSorter(['zip', '-state', 'price'])); // alternative
function fieldSorter(fields) {
return function (a, b) {
return fields
.map(function (o) {
var dir = 1;
if (o[0] === '-') {
dir = -1;
o=o.substring(1);
}
if (a[o] > b[o]) return dir;
if (a[o] < b[o]) return -(dir);
return 0;
})
.reduce(function firstNonZeroValue (p,n) {
return p ? p : n;
}, 0);
};
}
array.sort(function(a, b) {
if (a.AffiliateDueDate > b.AffiliateDueDate ) return 1;
else if (a.AffiliateDueDate < b.AffiliateDueDate ) return -1;
else if (a.Title > b.Title ) return 1;
else if (a.Title < b.Title ) return -1;
else return 0;
})
function sortByAttribute(array, ...attrs) {
// generate an array of predicate-objects contains
// property getter, and descending indicator
let predicates = attrs.map(pred => {
let descending = pred.charAt(0) === '-' ? -1 : 1;
pred = pred.replace(/^-/, '');
return {
getter: o => o[pred],
descend: descending
};
});
// schwartzian transform idiom implementation. aka: "decorate-sort-undecorate"
return array.map(item => {
return {
src: item,
compareValues: predicates.map(predicate => predicate.getter(item))
};
})
.sort((o1, o2) => {
let i = -1, result = 0;
while (++i < predicates.length) {
if (o1.compareValues[i] < o2.compareValues[i]) result = -1;
if (o1.compareValues[i] > o2.compareValues[i]) result = 1;
if (result *= predicates[i].descend) break;
}
return result;
})
.map(item => item.src);
}
let games = [
{ name: 'Pako', rating: 4.21 },
{ name: 'Hill Climb Racing', rating: 3.88 },
{ name: 'Angry Birds Space', rating: 3.88 },
{ name: 'Badland', rating: 4.33 }
];
// sort by one attribute
console.log(sortByAttribute(games, 'name'));
// sort by mupltiple attributes
console.log(sortByAttribute(games, '-rating', 'name'));
var generic_date = new Date(2070, 1, 1);
checkDate = function(date) {
return Date.parse(date) ? new Date(date): generic_date;
}
function sortData() {
data.sort(function(a,b){
var deltaEnd = checkDate(b.end) - checkDate(a.end);
if(deltaEnd) return deltaEnd;
var deltaRank = a.rank - b.rank;
if (deltaRank) return deltaRank;
var deltaStart = checkDate(b.start) - checkDate(a.start);
if(deltaStart) return deltaStart;
return 0;
});
}
var someArray = [...];
function generateSortFn(props) {
return function (a, b) {
for (var i = 0; i < props.length; i++) {
var prop = props[i];
var name = prop.name;
var reverse = prop.reverse;
if (a[name] < b[name])
return reverse ? 1 : -1;
if (a[name] > b[name])
return reverse ? -1 : 1;
}
return 0;
};
};
someArray.sort(generateSortFn([{name: 'prop1', reverse: true}, {name: 'prop2'}]));
function sortMultiFields(prop){
return function(a,b){
for(i=0;i<prop.length;i++)
{
var reg = /^\d+$/;
var x=1;
var field1=prop[i];
if(prop[i].indexOf("-")==0)
{
field1=prop[i].substr(1,prop[i].length);
x=-x;
}
if(reg.test(a[field1]))
{
a[field1]=parseFloat(a[field1]);
b[field1]=parseFloat(b[field1]);
}
if( a[field1] > b[field1])
return x;
else if(a[field1] < b[field1])
return -x;
}
}
}
homes.sort(sortMultiFields(["city","-price"]));
homes.sort(
function(a,b){
if (a.city==b.city){
return (b.price-a.price);
} else {
return (a.city-b.city);
}
});
var users = [
{ 'user': 'fred', 'age': 48 },
{ 'user': 'barney', 'age': 36 },
{ 'user': 'fred', 'age': 40 },
{ 'user': 'barney', 'age': 34 }
];
_.sortBy(users, [function(o) { return o.user; }]);
// => objects for [['barney', 36], ['barney', 34], ['fred', 48], ['fred', 40]]
_.sortBy(users, ['user', 'age']);
// => objects for [['barney', 34], ['barney', 36], ['fred', 40], ['fred', 48]]
function sort(data, orderBy) {
orderBy = Array.isArray(orderBy) ? orderBy : [orderBy];
return data.sort((a, b) => {
for (let i = 0, size = orderBy.length; i < size; i++) {
const key = Object.keys(orderBy[i])[0],
o = orderBy[i][key],
valueA = a[key],
valueB = b[key];
if (!(valueA || valueB)) {
console.error("the objects from the data passed does not have the key '" + key + "' passed on sort!");
return [];
}
if (+valueA === +valueA) {
return o.toLowerCase() === 'desc' ? valueB - valueA : valueA - valueB;
} else {
if (valueA.localeCompare(valueB) > 0) {
return o.toLowerCase() === 'desc' ? -1 : 1;
} else if (valueA.localeCompare(valueB) < 0) {
return o.toLowerCase() === 'desc' ? 1 : -1;
}
}
}
});
}
sort(homes, [{city : 'asc'}, {price: 'desc'}])
function sortByPriority(data, priorities) {
if (priorities.length == 0) {
return data;
}
const nextPriority = priorities[0];
const remainingPriorities = priorities.slice(1);
const matched = data.filter(item => item.hasOwnProperty(nextPriority));
const remainingData = data.filter(item => !item.hasOwnProperty(nextPriority));
return sortByPriority(matched, remainingPriorities)
.sort((a, b) => (a[nextPriority] > b[nextPriority]) ? 1 : -1)
.concat(sortByPriority(remainingData, remainingPriorities));
}
const data = [
{ id: 1, mediumPriority: 'bbb', lowestPriority: 'ggg' },
{ id: 2, highestPriority: 'bbb', mediumPriority: 'ccc', lowestPriority: 'ggg' },
{ id: 3, mediumPriority: 'aaa', lowestPriority: 'ggg' },
];
const priorities = [
'highestPriority',
'mediumPriority',
'lowestPriority'
];
const sorted = sortByPriority(data, priorities);
const sortCompareByCityPrice = (a, b) => {
let comparison = 0
// sort by first criteria
if (a.city > b.city) {
comparison = 1
}
else if (a.city < b.city) {
comparison = -1
}
// If still 0 then sort by second criteria descending
if (comparison === 0) {
if (parseInt(a.price) > parseInt(b.price)) {
comparison = -1
}
else if (parseInt(a.price) < parseInt(b.price)) {
comparison = 1
}
}
return comparison
}
homes.sort(function(left, right) {
var city_order = left.city.localeCompare(right.city);
var price_order = parseInt(left.price) - parseInt(right.price);
return city_order || -price_order;
});
testSort(data) {
return data.sort(
a['nameOne'] > b['nameOne'] ? 1
: b['nameOne'] > a['nameOne'] ? -1 : 0 ||
a['date'] > b['date'] ||
a['number'] - b['number']
);
}
function msort(arr, ...compFns) {
let fn = compFns[0];
arr = [].concat(arr);
let arr1 = [];
while (arr.length > 0) {
let arr2 = arr.splice(0, 1);
for (let i = arr.length; i > 0;) {
if (fn(arr2[0], arr[--i]) === 0) {
arr2 = arr2.concat(arr.splice(i, 1));
}
}
arr1.push(arr2);
}
arr1.sort(function (a, b) {
return fn(a[0], b[0]);
});
compFns = compFns.slice(1);
let res = [];
arr1.map(a1 => {
if (compFns.length > 0) a1 = msort(a1, ...compFns);
a1.map(a2 => res.push(a2));
});
return res;
}
let tstArr = [{ id: 1, sex: 'o' }, { id: 2, sex: 'm' }, { id: 3, sex: 'm' }, { id: 4, sex: 'f' }, { id: 5, sex: 'm' }, { id: 6, sex: 'o' }, { id: 7, sex: 'f' }];
function tstFn1(a, b) {
if (a.sex > b.sex) return 1;
else if (a.sex < b.sex) return -1;
return 0;
}
function tstFn2(a, b) {
if (a.id > b.id) return -1;
else if (a.id < b.id) return 1;
return 0;
}
console.log(JSON.stringify(msort(tstArr, tstFn1, tstFn2)));
//output:
//[{"id":7,"sex":"f"},{"id":4,"sex":"f"},{"id":5,"sex":"m"},{"id":3,"sex":"m"},{"id":2,"sex":"m"},{"id":6,"sex":"o"},{"id":1,"sex":"o"}]
Object.defineProperty(Array.prototype, 'orderBy', {
value: function(sorts) {
sorts.map(sort => {
sort.uniques = Array.from(
new Set(this.map(obj => obj[sort.key]))
);
sort.uniques = sort.uniques.sort((a, b) => {
if (typeof a == 'string') {
return sort.inverse ? b.localeCompare(a) : a.localeCompare(b);
}
else if (typeof a == 'number') {
return sort.inverse ? b - a : a - b;
}
else if (typeof a == 'boolean') {
let x = sort.inverse ? (a === b) ? 0 : a? -1 : 1 : (a === b) ? 0 : a? 1 : -1;
return x;
}
return 0;
});
});
const weightOfObject = (obj) => {
let weight = "";
sorts.map(sort => {
let zeropad = `${sort.uniques.length}`.length;
weight += sort.uniques.indexOf(obj[sort.key]).toString().padStart(zeropad, '0');
});
//obj.weight = weight; // if you need to see weights
return weight;
}
this.sort((a, b) => {
return weightOfObject(a).localeCompare( weightOfObject(b) );
});
return this;
}
});
// works with string, number and boolean
let sortered = your_array.orderBy([
{key: "type", inverse: false},
{key: "title", inverse: false},
{key: "spot", inverse: false},
{key: "internal", inverse: true}
]);
const sortByTitle = (a, b): number =>
a.title === b.title ? 0 : a.title > b.title ? 1 : -1;
const createSorter = (...sorters) => (a, b) =>
sorters.reduce(
(d, fn) => (d === 0 ? fn(a, b) : d),
0
);
const sorter = createSorter(sortByTitle, sortByYear)
items.sort(sorter)
interface Person {
firstName: string;
lastName: string;
}
people.sort(byObjectValues<Person>(['lastName','firstName']));
interface Language {
code: string;
version: number;
}
// languageCodeToName(code) is defined elsewhere in code
languageCodes.sort(byObjectValues<Language>([
{
key: 'code',
map(code:string) => languageCodeToName(code),
},
{
key: 'version',
reverse: true,
}
]));
/** Performs comparing of two items by specified properties
* @param {Array} props for sorting ['name'], ['value', 'city'], ['-date']
* to set descending order on object property just add '-' at the begining of property
*/
export const compareBy = (...props) => (a, b) => {
for (let i = 0; i < props.length; i++) {
const ascValue = props[i].startsWith('-') ? -1 : 1;
const prop = props[i].startsWith('-') ? props[i].substr(1) : props[i];
if (a[prop] !== b[prop]) {
return a[prop] > b[prop] ? ascValue : -ascValue;
}
}
return 0;
};
homes.sort(compareBy('city', '-price'));
var data = [
{
"id": 1,
"ship": null,
"product": "Orange",
"quantity": 7,
"price": 92.08,
"discount": 0
},
{
"id": 2,
"ship": "2017-06-14T23:00:00.000Z".toDate(),
"product": "Apple",
"quantity": 22,
"price": 184.16,
"discount": 0
},
...
]
var sorts = ["product", "quantity", "ship"]
// comp_val formats values and protects against comparing nulls/undefines
// type() just returns the variable constructor
// String.lower just converts the string to lowercase.
// String.toDate custom fn to convert strings to Date
function comp_val(value){
if (value==null || value==undefined) return null
var cls = type(value)
switch (cls){
case String:
return value.lower()
}
return value
}
function compare(a, b, i){
i = i || 0
var prop = sorts[i]
var va = comp_val(a[prop])
var vb = comp_val(b[prop])
// handle what to do when both or any values are null
if (va == null || vb == null) return true
if ((i < sorts.length-1) && (va == vb)) {
return compare(a, b, i+1)
}
return va > vb
}
var d = data.sort(compare);
console.log(d);
let homes = [ {"h_id":"3",
"city":"Dallas",
"state":"TX",
"zip":"75201",
"price":"162500"},
{"h_id":"4",
"city":"Bevery Hills",
"state":"CA",
"zip":"90210",
"price":"319250"},
{"h_id":"6",
"city":"Dallas",
"state":"TX",
"zip":"75000",
"price":"556699"},
{"h_id":"5",
"city":"New York",
"state":"NY",
"zip":"00010",
"price":"962500"}
];
homes.sort((a, b) => (a.city > b.city) ? 1 : -1);