Javascript $scope不';t外部回调函数
我开发了与数据库集成的AngularJS应用程序。当尝试从数据库获取信息时,$scope变量仅存在于方法内部Javascript $scope不';t外部回调函数,javascript,angularjs,pouchdb,Javascript,Angularjs,Pouchdb,我开发了与数据库集成的AngularJS应用程序。当尝试从数据库获取信息时,$scope变量仅存在于方法内部 db.allDocs({include_docs: true, descending: true}, function(err, doc) { $scope.$apply(function(){ $scope.info = doc.rows; }); }); $scope.select = function(id){ for(var
db.allDocs({include_docs: true, descending: true}, function(err, doc) {
$scope.$apply(function(){
$scope.info = doc.rows;
});
});
$scope.select = function(id){
for(var i = 0; i < $scope.info.length; i++){
if(id == $scope.info[i].doc._id){
$scope.$apply(function (){
$scope.sName = $scope.info[i].doc.name;
$scope.sSurname = $scope.info[i].doc.surname;
$scope.sPhone = $scope.info[i].doc.phone;
$scope.sAddress = $scope.info[i].doc.address;
console.log($scope.info[i].doc);
});
}
}
};
db.allDocs({include_docs:true,descending:true},函数(err,doc){
$scope.$apply(函数(){
$scope.info=doc.rows;
});
});
$scope.select=函数(id){
对于(变量i=0;i<$scope.info.length;i++){
如果(id=$scope.info[i].doc.\u id){
$scope.$apply(函数(){
$scope.sName=$scope.info[i].doc.name;
$scope.sSurname=$scope.info[i].doc.name;
$scope.sPhone=$scope.info[i].doc.phone;
$scope.sAddress=$scope.info[i].doc.address;
console.log($scope.info[i].doc);
});
}
}
};
在这里,我调用Select函数来选择一个用户,然后我想在输入中显示该用户,以便更新信息
<div class="col-xs-6 col-sm-3 sidebar-offcanvas" id="sidebar" role="navigation">
<h3>All users</h3>
<div class="list-group">
<a href="#" ng-repeat="i in info" class="list-group-item" ng-click="select(i.doc._id)">{{i.doc.name + ' ' + i.doc.surname}}</a>
</div>
</div>
所有用户
这里我使用$scope变量
<div class="col-xs-6 col-sm-3 sidebar-offcanvas" style="margin-left: 20%;">
<h3>Selected user</h3>
<input type="text" ng-model="sName" class="form-control" placeholder="Name" />
<input type="text" ng-model="sSurname" class="form-control" placeholder="Surname" />
<input type="text" ng-model="sPhone" class="form-control" placeholder="Phone" />
<input type="text" ng-model="sAddress" class="form-control" placeholder="Address" />
<br/>
<table>
<tr>
<td><button ng-click="" class="btn btn-lg btn-primary">Update</button></td>
<td><label style="visibility: hidden;">a;dl</label></td>
<td><button ng-click="" class="btn btn-lg btn-danger">Remove</button></td>
</tr>
</table>
</div>
选定用户
使现代化
A.dl
去除
$scope.sName,$scope.sName。。。在select函数之外未定义
有什么帮助吗?您的问题是循环中有一个函数,因此执行函数时,
i
始终等于$scope.info.length+1
如果您使用,它将警告您此类错误,以便您在运行时不会发现它们。唯一的问题似乎是您正在使用
$scope.$apply()
回调到ngClick
(这也会触发$digest循环)
删除$scope.$apply()
,它应该可以正常工作:
$scope.select = function (id) {
for (var i = 0; i < $scope.info.length; i++) {
if (id === $scope.info[i].doc._id) {
// $scope.$apply(function (){
$scope.sName = $scope.info[i].doc.name;
$scope.sSurname = $scope.info[i].doc.surname;
$scope.sPhone = $scope.info[i].doc.phone;
$scope.sAddress = $scope.info[i].doc.address;
console.log($scope.info[i].doc);
// });
}
}
};
你确定没有收到任何错误吗?没有,没有错误…我们需要查看更多代码。
$scope
的上下文是什么,以及$scope是如何调用的。选择调用的?我编辑了这篇文章,你可以看到我是如何使用$scope变量的。如果你告诉我你正在调用$scope.$apply()
在回调中单击不会出现任何错误?很难相信:)这不是问题:/如果我删除$scope.$apply函数,此方法将设置$scope.sName、$scope.sSurname。。。变量,但我不能在方法之外使用它们。#问题是什么:/非常感谢:)@АаСаааааааааааааааааааааааа-答案左上角的箭头)。这样,其他面临类似问题的用户就会知道这个答案解决了它!
<a href="" ... ng-click="select(i.doc)" ng-repeat="i in info">...</a>
$scope.select = function (doc) {
$scope.sName = doc.name;
$scope.sSurname = doc.surname;
$scope.sPhone = doc.phone;
$scope.sAddress = doc.address;
};