Javascript jQuery检查属性。打开收音机并取消选中onClick
这是代码Javascript jQuery检查属性。打开收音机并取消选中onClick,javascript,jquery,html,list,Javascript,Jquery,Html,List,这是代码 <html> <head> <link href="../../fuctions/style.css" rel="stylesheet" media="screen" type="text/css" /> <script type="text/javascript" charset="utf-8" src="../../fuctions/cordova-2.3.0.js"></script&g
<html>
<head>
<link href="../../fuctions/style.css" rel="stylesheet" media="screen" type="text/css" />
<script type="text/javascript" charset="utf-8" src="../../fuctions/cordova-2.3.0.js"></script>
<script type="text/javascript" charset="utf-8" src="../../fuctions/functions.js"></script>
<script type="text/javascript" charset="utf-8" src="../../fuctions/jq.js"></script>
</head>
<body>
<div id="topbar">
<div id="title"><!--Title-->
After Landing
</div>
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<a href="../../index_aerosoft.html">Home</a>
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<a href="katan_checklist_engineshut-downl.html"id="a_next">Next</a></div><!--NextPage-->
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<div id="content">
<ul class="pageitem">
<li class="radiobutton" onClick="checkChanges()">
<span class="name">Wing Flaps -<font color="red"> UP
</font></span>
<input name="1" type="radio" value="other" />
</li><!--CheckpunktEnd-->
<li class="radiobutton" onClick="checkChanges()">
<span class="name">Carburetor Heat -<font color="red"> OFF
</font></span>
<input name="2" type="radio" value="other" />
</li><!--CheckpunktEnd-->
<li class="radiobutton" onClick="checkChanges()">
<span class="name">Exterior Lights -<font color="red"> as required
</font></span>
<input name="3" type="radio" value="other" />
</li><!--CheckpunktEnd-->
<li class="radiobutton" onClick="checkChanges()">
<span class="name">Electric Fuel Pump -<font color="red"> OFF
</font></span>
<input name="4" type="radio" value="other" />
</li><!--CheckpunktEnd-->
</ul>
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<a class="noeffect" href="#" onClick="resetChecklist();">Reset Checklist</a><!--ResetChecklist-->
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<a class="noeffect" href="#" onClick="openxyzDE();">xyz</a>
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我想在该代码中添加一个功能,如果选中并再次单击(onClick),则取消选中收音机。这也会将颜色改回红色。很少更正
:选中的前的空格。更改:
$('.radiobutton :checked').closest('.radiobutton').find('font').attr('color', 'green');
致:
input[type=“radio”]
。更改:
$('.radiobutton :radio').on('click', checkChanges);
致:
不适合我,也许我做错了什么你有完整的代码给我吗?你能帮我做一个修改,这样我会编辑并把你发回…:)
$('.radiobutton:checked').closest('.radiobutton').find('font').attr('color', 'green');
$('.radiobutton :radio').on('click', checkChanges);
$('input.radiobutton[type="radio"]').on('click', checkChanges);