Javascript &引用;未捕获的SyntaxError:意外标记:“0”;当没有“时”:&引用;?
给定的JSON数据没有索引:Javascript &引用;未捕获的SyntaxError:意外标记:“0”;当没有“时”:&引用;?,javascript,jquery,google-chrome-devtools,Javascript,Jquery,Google Chrome Devtools,给定的JSON数据没有索引: var knol = [ {"hant":"火","status":1,"rank":30,"score": 1}, {"hant":"人","status":1,"rank":33,"score": 2}, {"hant":"山","status":1,"rank":60,"score": 5}, {"hant":"是","status":1,"rank":50,"score": 3} ]; var addIndex = fu
var knol = [
{"hant":"火","status":1,"rank":30,"score": 1},
{"hant":"人","status":1,"rank":33,"score": 2},
{"hant":"山","status":1,"rank":60,"score": 5},
{"hant":"是","status":1,"rank":50,"score": 3}
];
var addIndex = function(object, key1, key2){
var data = object;
var newData = "[";
for (var i in data) {
if (!key2) {
var newIndex = data[i][key1]
} else {
var newIndex = data[i][key1] + data[i][key2]
}
newData = newData + "\"" + newIndex + "\":" + JSON.stringify(data[i]) +",";
}
newData = newData.concat("]").replace(",]", "]");
console.log(newData);
newData = JSON.parse(newData);
return newData;
};
knol = addIndex(knol, "hant");
给定了一个JS函数来重新创建带有索引的数据:
var knol = [
{"hant":"火","status":1,"rank":30,"score": 1},
{"hant":"人","status":1,"rank":33,"score": 2},
{"hant":"山","status":1,"rank":60,"score": 5},
{"hant":"是","status":1,"rank":50,"score": 3}
];
var addIndex = function(object, key1, key2){
var data = object;
var newData = "[";
for (var i in data) {
if (!key2) {
var newIndex = data[i][key1]
} else {
var newIndex = data[i][key1] + data[i][key2]
}
newData = newData + "\"" + newIndex + "\":" + JSON.stringify(data[i]) +",";
}
newData = newData.concat("]").replace(",]", "]");
console.log(newData);
newData = JSON.parse(newData);
return newData;
};
knol = addIndex(knol, "hant");
我在代码中指定的位置得到错误“uncaughtsyntaxerror:意外标记:”
,而没有“:”。这似乎使我的大脚本崩溃了。知道发生了什么吗
Fiddle:中间JSON不正确,因此最终的
JSON.parse失败。中间文本是[”火":{“汉特”:火“,…
,正如控制台上报告的那样,这确实是不正确的,因为数组没有键
只需将整个对象图构建/重建为JS对象,然后在其上使用JSON.stringify
——或者,在这种情况下,永远不要,因为最终结果将是一个JS对象
var addIndex = function(data, key1, key2){
var newData = {}; // new JS object - there is /no/ JSON here.
var newIndex;
for(var i in data){
if(!key2){
newIndex = data[i][key1];
}else{
newIndex = data[i][key1] + data[i][key2];
}
// add data to new object with appropriate property/key
// and do NOT manually build JSON text.
newData[newIndex] = data[i];
}
// return object directly; it's not JSON text, no need to parse it!
return newData;
};
中间JSON不正确,因此最终的JSON.parse
失败。中间文本为[”火“:{“汉特”:”火“,…
,正如控制台上报告的那样,这确实是不正确的,因为数组没有键
只需将整个对象图构建/重建为JS对象,然后在其上使用JSON.stringify
——或者,在这种情况下,永远不要,因为最终结果将是一个JS对象
var addIndex = function(data, key1, key2){
var newData = {}; // new JS object - there is /no/ JSON here.
var newIndex;
for(var i in data){
if(!key2){
newIndex = data[i][key1];
}else{
newIndex = data[i][key1] + data[i][key2];
}
// add data to new object with appropriate property/key
// and do NOT manually build JSON text.
newData[newIndex] = data[i];
}
// return object directly; it's not JSON text, no need to parse it!
return newData;
};
中间JSON不正确,因此最终的JSON.parse
失败。中间文本为[”火“:{“汉特”:”火“,…
,正如控制台上报告的那样,这确实是不正确的,因为数组没有键
只需将整个对象图构建/重建为JS对象,然后在其上使用JSON.stringify
——或者,在这种情况下,永远不要,因为最终结果将是一个JS对象
var addIndex = function(data, key1, key2){
var newData = {}; // new JS object - there is /no/ JSON here.
var newIndex;
for(var i in data){
if(!key2){
newIndex = data[i][key1];
}else{
newIndex = data[i][key1] + data[i][key2];
}
// add data to new object with appropriate property/key
// and do NOT manually build JSON text.
newData[newIndex] = data[i];
}
// return object directly; it's not JSON text, no need to parse it!
return newData;
};
中间JSON不正确,因此最终的JSON.parse
失败。中间文本为[”火“:{“汉特”:”火“,…
,正如控制台上报告的那样,这确实是不正确的,因为数组没有键
只需将整个对象图构建/重建为JS对象,然后在其上使用JSON.stringify
——或者,在这种情况下,永远不要,因为最终结果将是一个JS对象
var addIndex = function(data, key1, key2){
var newData = {}; // new JS object - there is /no/ JSON here.
var newIndex;
for(var i in data){
if(!key2){
newIndex = data[i][key1];
}else{
newIndex = data[i][key1] + data[i][key2];
}
// add data to new object with appropriate property/key
// and do NOT manually build JSON text.
newData[newIndex] = data[i];
}
// return object directly; it's not JSON text, no need to parse it!
return newData;
};
您需要创建一个对象({…}
),而不是一个数组([…]
)。这将起作用:
var newData = "{";
for(var i in data){
if(!key2){ var newIndex = data[i][key1] }else{ var newIndex = data[i][key1]+ data[i][key2]}
newData = newData + "\""+newIndex+"\":"+JSON.stringify(data[i])+",";
}
newData = newData.concat("}").replace(",]", "]").replace(",}", "}");
但是,我强烈建议直接操作数据,而不是尝试从数据的各个部分手动构造JSON字符串
下面是一个简单的实现:
var addIndex = function(object, key1, key2){
var data = object, newData = {}, newIndex;
for(var i in data){
if(!key2){
newIndex = data[i][key1];
}else{
newIndex = data[i][key1]+ data[i][key2];
}
newData[newIndex] = data[i];
}
console.log(newData);
return newData;
};
您需要创建一个对象({…}
),而不是一个数组([…]
)。这可以:
var newData = "{";
for(var i in data){
if(!key2){ var newIndex = data[i][key1] }else{ var newIndex = data[i][key1]+ data[i][key2]}
newData = newData + "\""+newIndex+"\":"+JSON.stringify(data[i])+",";
}
newData = newData.concat("}").replace(",]", "]").replace(",}", "}");
但是,我强烈建议直接操作数据,而不是尝试从数据的各个部分手动构造JSON字符串
下面是一个简单的实现:
var addIndex = function(object, key1, key2){
var data = object, newData = {}, newIndex;
for(var i in data){
if(!key2){
newIndex = data[i][key1];
}else{
newIndex = data[i][key1]+ data[i][key2];
}
newData[newIndex] = data[i];
}
console.log(newData);
return newData;
};
您需要创建一个对象({…}
),而不是一个数组([…]
)。这可以:
var newData = "{";
for(var i in data){
if(!key2){ var newIndex = data[i][key1] }else{ var newIndex = data[i][key1]+ data[i][key2]}
newData = newData + "\""+newIndex+"\":"+JSON.stringify(data[i])+",";
}
newData = newData.concat("}").replace(",]", "]").replace(",}", "}");
但是,我强烈建议直接操作数据,而不是尝试从数据的各个部分手动构造JSON字符串
下面是一个简单的实现:
var addIndex = function(object, key1, key2){
var data = object, newData = {}, newIndex;
for(var i in data){
if(!key2){
newIndex = data[i][key1];
}else{
newIndex = data[i][key1]+ data[i][key2];
}
newData[newIndex] = data[i];
}
console.log(newData);
return newData;
};
您需要创建一个对象({…}
),而不是一个数组([…]
)。这可以:
var newData = "{";
for(var i in data){
if(!key2){ var newIndex = data[i][key1] }else{ var newIndex = data[i][key1]+ data[i][key2]}
newData = newData + "\""+newIndex+"\":"+JSON.stringify(data[i])+",";
}
newData = newData.concat("}").replace(",]", "]").replace(",}", "}");
但是,我强烈建议直接操作数据,而不是尝试从数据的各个部分手动构造JSON字符串
下面是一个简单的实现:
var addIndex = function(object, key1, key2){
var data = object, newData = {}, newIndex;
for(var i in data){
if(!key2){
newIndex = data[i][key1];
}else{
newIndex = data[i][key1]+ data[i][key2];
}
newData[newIndex] = data[i];
}
console.log(newData);
return newData;
};
谢谢,这个答案太棒了。我想知道怎么做。谢谢,这个答案太棒了。我想知道怎么做。谢谢,这个答案太棒了。我想知道怎么做。谢谢,这个答案太棒了。我想知道怎么做。+1看起来我们两个都独立开发了几乎相同的解决方案。+1看起来我们两个E独立开发了几乎相同的解决方案。+1看起来我们都独立开发了几乎相同的解决方案。+1看起来我们都独立开发了几乎相同的解决方案。