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如何在javascript中将stringyfied数组值转换为float

javascript json

如何在javascript中将stringyfied数组值转换为float,javascript,json,Javascript,Json,我使用了data\u str=JSON.stringify（data）转换为字符串。json中的数据是 [{"temperSensorData":"28.489084691371996","temperSensorUnit":"celsius","timestamp":"1493270171424","timestamp2":"1493270171454","timestamp3":"1493270171454","val":"0"},{"temperSensorData":"28.489084

我使用了data\u str=JSON.stringify（data）转换为字符串。json中的数据是

[{"temperSensorData":"28.489084691371996","temperSensorUnit":"celsius","timestamp":"1493270171424","timestamp2":"1493270171454","timestamp3":"1493270171454","val":"0"},{"temperSensorData":"28.48908469137112","temperSensorUnit":"celsius","timestamp":"1493270171426","timestamp2":"1493270171522","timestamp3":"1493270171523","val":"1"},{"temperSensorData":"28.489084691371186","temperSensorUnit":"celsius","timestamp":"1493270171426","timestamp2":"1493270171523","timestamp3":"1493270171524","val":"2"},{"temperSensorData":"28.489084691371595","temperSensorUnit":"celsius","timestamp":"1493270171426","timestamp2":"1493270171524","timestamp3":"1493270171525","val":"3"},{"temperSensorData":"28.48908469137168","temperSensorUnit":"celsius","timestamp":"1493270171428","timestamp2":"1493270171529","timestamp3":"1493270171529","val":"4"},{"temperSensorData":"28.489084691371684","temperSensorUnit":"celsius","timestamp":"1493270171428","timestamp2":"1493270171529","timestamp3":"1493270171529","val":"5"},{"temperSensorData":"28.489084691371357","temperSensorUnit":"celsius","timestamp":"1493270171429","timestamp2":"1493270171530","timestamp3":"1493270171531","val":"6"},{"temperSensorData":"28.489084691371144","temperSensorUnit":"celsius","timestamp":"1493270171429","timestamp2":"1493270171531","timestamp3":"1493270171532","val":"7"},{"temperSensorData":"28.48908469137181","temperSensorUnit":"celsius","timestamp":"1493270171431","timestamp2":"1493270171546","timestamp3":"1493270171546","val":"25"}]
现在我想取timestamp值并执行一些数学运算。如何将其转换为浮点值？ 尽管我使用了parseInt（timestamp）和Number（timestamp），但它不起作用并向我显示结果：NaN

parseFloat（）-

结果

[ 1493270171424,
  1493270171426,
  1493270171426,
  1493270171426,
  1493270171428,
  1493270171428,
  1493270171429,
  1493270171429,
  1493270171431 ]
parseFloat（）-

结果

[ 1493270171424,
  1493270171426,
  1493270171426,
  1493270171426,
  1493270171428,
  1493270171428,
  1493270171429,
  1493270171429,
  1493270171431 ]
使用
parseFloat（data.timestamp）
而不是
parseInt
，
timestamp
是数据json数组的内部对象值。您可以这样调用
data.timestamp
我创建了一些map函数来分离
时间戳
，并在数组中附加

var数据=[{
“温度传感器数据”：“28.489084691371996”，
“温度传感器单位”：“摄氏度”，
“时间戳”：“1493270171424”，
“时间戳2”：“1493270171454”，
“时间戳3”：“1493270171454”，
“val”：“0”
}, {
“温度传感器数据”：“28.48908469137112”，
“温度传感器单位”：“摄氏度”，
“时间戳”：“1493270171426”，
“时间戳2”：“1493270171522”，
“时间戳3”：“1493270171523”，
“val”：“1”
}, {
“温度传感器数据”：“28.489084691371186”，
“温度传感器单位”：“摄氏度”，
“时间戳”：“1493270171426”，
“时间戳2”：“1493270171523”，
“时间戳3”：“1493270171524”，
“val”：“2”
}, {
“温度传感器数据”：“28.489084691371595”，
“温度传感器单位”：“摄氏度”，
“时间戳”：“1493270171426”，
“时间戳2”：“1493270171524”，
“时间戳3”：“1493270171525”，
“val”：“3”
}, {
“温度传感器数据”：“28.48908469137168”，
“温度传感器单位”：“摄氏度”，
“时间戳”：“1493270171428”，
“时间戳2”：“1493270171529”，
“时间戳3”：“1493270171529”，
“val”：“4”
}, {
“温度传感器数据”：“28.489084691371684”，
“温度传感器单位”：“摄氏度”，
“时间戳”：“1493270171428”，
“时间戳2”：“1493270171529”，
“时间戳3”：“1493270171529”，
“val”：“5”
}, {
“温度传感器数据”：“28.489084691371357”，
“温度传感器单位”：“摄氏度”，
“时间戳”：“1493270171429”，
“时间戳2”：“1493270171530”，
“时间戳3”：“1493270171531”，
“val”：“6”
}, {
“温度传感器数据”：“28.489084691371144”，
“温度传感器单位”：“摄氏度”，
“时间戳”：“1493270171429”，
“时间戳2”：“1493270171531”，
“时间戳3”：“1493270171532”，
“val”：“7”
}, {
“温度传感器数据”：“28.48908469137181”，
“温度传感器单位”：“摄氏度”，
“时间戳”：“1493270171431”，
“时间戳2”：“1493270171546”，
“时间戳3”：“1493270171546”，
“val”：“25”
}]

console.log（data.map（a=>parseFloat（a.timestamp））
使用
parseFloat（data.timestamp）
而不是
parseInt
，
timestamp
是数据json数组的内部对象值。您可以这样调用
数据.timestamp
我创建了一些map函数来分离
时间戳
，并在数组中附加

var数据=[{
“温度传感器数据”：“28.489084691371996”，
“温度传感器单位”：“摄氏度”，
“时间戳”：“1493270171424”，
“时间戳2”：“1493270171454”，
“时间戳3”：“1493270171454”，
“val”：“0”
}, {
“温度传感器数据”：“28.48908469137112”，
“温度传感器单位”：“摄氏度”，
“时间戳”：“1493270171426”，
“时间戳2”：“1493270171522”，
“时间戳3”：“1493270171523”，
“val”：“1”
}, {
“温度传感器数据”：“28.489084691371186”，
“温度传感器单位”：“摄氏度”，
“时间戳”：“1493270171426”，
“时间戳2”：“1493270171523”，
“时间戳3”：“1493270171524”，
“val”：“2”
}, {
“温度传感器数据”：“28.489084691371595”，
“温度传感器单位”：“摄氏度”，
“时间戳”：“1493270171426”，
“时间戳2”：“1493270171524”，
“时间戳3”：“1493270171525”，
“val”：“3”
}, {
“温度传感器数据”：“28.48908469137168”，
“温度传感器单位”：“摄氏度”，
“时间戳”：“1493270171428”，
“时间戳2”：“1493270171529”，
“时间戳3”：“1493270171529”，
“val”：“4”
}, {
“温度传感器数据”：“28.489084691371684”，
“温度传感器单位”：“摄氏度”，
“时间戳”：“1493270171428”，
“时间戳2”：“1493270171529”，
“时间戳3”：“1493270171529”，
“val”：“5”
}, {
“温度传感器数据”：“28.489084691371357”，
“温度传感器单位”：“摄氏度”，
“时间戳”：“1493270171429”，
“时间戳2”：“1493270171530”，
“时间戳3”：“1493270171531”，
“val”：“6”
}, {
“温度传感器数据”：“28.489084691371144”，
“温度传感器单位”：“摄氏度”，
“时间戳”：“1493270171429”，
“时间戳2”：“1493270171531”，
“时间戳3”：“1493270171532”，
“val”：“7”
}, {
“温度传感器数据”：“28.48908469137181”，
“温度传感器单位”：“摄氏度”，
“时间戳”：“1493270171431”，
“时间戳2”：“1493270171546”，
“时间戳3”：“1493270171546”，
“val”：“25”
}]

log（data.map（a=>parseFloat（a.timestamp））
这是将JSON转换为对象的好方法

样本：

data_str=JSON.parse('[{"temperSensorData":"28.489084691371996","temperSensorUnit":"celsius","timestamp":"1493270171424","timestamp2":"1493270171454","timestamp3":"1493270171454","val":"0"},{"temperSensorData":"28.48908469137112","temperSensorUnit":"celsius","timestamp":"1493270171426","timestamp2":"1493270171522","timestamp3":"1493270171523","val":"1"},{"temperSensorData":"28.489084691371186","temperSensorUnit":"celsius","timestamp":"1493270171426","timestamp2":"1493270171523","timestamp3":"1493270171524","val":"2"},{"temperSensorData":"28.489084691371595","temperSensorUnit":"celsius","timestamp":"1493270171426","timestamp2":"1493270171524","timestamp3":"1493270171525","val":"3"},{"temperSensorData":"28.48908469137168","temperSensorUnit":"celsius","timestamp":"1493270171428","timestamp2":"1493270171529","timestamp3":"1493270171529","val":"4"},{"temperSensorData":"28.489084691371684","temperSensorUnit":"celsius","timestamp":"1493270171428","timestamp2":"1493270171529","timestamp3":"1493270171529","val":"5"},{"temperSensorData":"28.489084691371357","temperSensorUnit":"celsius","timestamp":"1493270171429","timestamp2":"1493270171530","timestamp3":"1493270171531","val":"6"},{"temperSensorData":"28.489084691371144","temperSensorUnit":"celsius","timestamp":"1493270171429","timestamp2":"1493270171531","timestamp3":"1493270171532","val":"7"},{"temperSensorData":"28.48908469137181","temperSensorUnit":"celsius","timestamp":"1493270171431","timestamp2":"1493270171546","timestamp3":"1493270171546","val":"25"}]');
console.log (data_str.length);

console.log (data_str[0].temperSensorData);
console.log(parseFloat(data_str[0].temperSensorData));

myTimeStamp = parseInt(data_str[0].timestamp);
console.log(myTimeStamp);


var theDate = new Date(myTimeStamp);
dateString = theDate.toString();
console.log(dateString);
这是将JSON转换为对象的好方法

样本：

data_str=JSON.parse('[{"temperSensorData":"28.489084691371996","temperSensorUnit":"celsius","timestamp":"1493270171424","timestamp2":"1493270171454","timestamp3":"1493270171454","val":"0"},{"temperSensorData":"28.48908469137112","temperSensorUnit":"celsius","timestamp":"1493270171426","timestamp2":"1493270171522","timestamp3":"1493270171523","val":"1"},{"temperSensorData":"28.489084691371186","temperSensorUnit":"celsius","timestamp":"1493270171426","timestamp2":"1493270171523","timestamp3":"1493270171524","val":"2"},{"temperSensorData":"28.489084691371595","temperSensorUnit":"celsius","timestamp":"1493270171426","timestamp2":"1493270171524","timestamp3":"1493270171525","val":"3"},{"temperSensorData":"28.48908469137168","temperSensorUnit":"celsius","timestamp":"1493270171428","timestamp2":"1493270171529","timestamp3":"1493270171529","val":"4"},{"temperSensorData":"28.489084691371684","temperSensorUnit":"celsius","timestamp":"1493270171428","timestamp2":"1493270171529","timestamp3":"1493270171529","val":"5"},{"temperSensorData":"28.489084691371357","temperSensorUnit":"celsius","timestamp":"1493270171429","timestamp2":"1493270171530","timestamp3":"1493270171531","val":"6"},{"temperSensorData":"28.489084691371144","temperSensorUnit":"celsius","timestamp":"1493270171429","timestamp2":"1493270171531","timestamp3":"1493270171532","val":"7"},{"temperSensorData":"28.48908469137181","temperSensorUnit":"celsius","timestamp":"1493270171431","timestamp2":"1493270171546","timestamp3":"1493270171546","val":"25"}]');
console.log (data_str.length);

console.log (data_str[0].temperSensorData);
console.log(parseFloat(data_str[0].temperSensorData));

myTimeStamp = parseInt(data_str[0].timestamp);
console.log(myTimeStamp);


var theDate = new Date(myTimeStamp);
dateString = theDate.toString();
console.log(dateString);
尝试parseFloat（“28.489084691371996”）函数。它会帮助你的

parseFloat("28.489084691371996")
如果需要进一步帮助，请告诉我。

尝试使用parseFloat（“28.489084691371996”）函数。它会帮助你的

parseFloat("28.489084691371996")
如果您需要进一步的帮助，请告诉我。

DEMO

var jsonObj=[{“温度传感器数据”：“28.489084691371996”，“温度传感器单元”：“摄氏度”，“时间戳”：“149370171424”，“时间戳2”：“149370171454”，“时间戳3”：“149370171454”，“val”：“0”}，{“温度传感器数据”：“28.48908469137112”，“温度传感器单元”：“摄氏度”，“时间戳”：“149370171426”，“时间戳2”：“149370171522”，“时间戳3”：“149370171523”，“val”：“149370523”，“val”：“1”}，{“温度传感器数据”：“28.489084691371186”，“温度传感器单元”：“摄氏度”，“时间戳”：“1493271426”，“时间戳2”：“1493271523”，“时间戳3”：“1493271524”，“val”：“2”}，{“温度传感器数据”：“28.489084691371595”，“温度传感器单元”：“摄氏度”，“时间戳”：“149327171426”，“时间戳2”：“149327171524”，“时间戳3”：“1493271525”，“val”：“3”{，”温度传感器数据“：”28.48908469137168“，”温度传感器单元“：”摄氏“，”tim