Javascript：在运行时生成函数 更新

解决方案在foreach循环中有效，但在for循环中无效

function x(number){
  return number - 10;
}
var i = 0
var runtimefunctions = {};
var allLevels = {"1":"State","2":"Educational_Services","3":"Principal_Networks","4":"Schools"}
 for (var key in allLevels) {
   runtimefunctions[i] = function() { return x(i); };
i++;
};

console.log(runtimefunctions[1]()); // -6
console.log(runtimefunctions[2]()); // -6
console.log(runtimefunctions[3]()); // -6

---

努力制作函数，但这是第一次创建这样的东西，所以无法理解正确的方法

我有一个功能

function x(number){
return number - 10;
}
runtimefunctions = {};
now I have a loop to run
[1,2,3].forEach(function(y){
   //here I want to create a function.. which will make a function x(y) -- like this
   runtimefunctions[x] = new Function("return function x_" + levelIterator + "(levelIterator){ console.log(levelIterator); x(" + y + ") }")();

});

基本上，我想做这样的函数

runtimefunctions= {
 "1": x(1),
 "2": x(2),
and so on
}

这是你需要的吗

function x(number){
  return number - 10;
}

var runtimefunctions = {};

[1,2,3].forEach(function(y){
   runtimefunctions[y] = function() { return x(y); };
});

console.log(runtimefunctions[1]()); // -9
console.log(runtimefunctions[2]()); // -8
console.log(runtimefunctions[3]()); // -7

---

为了满足下一个（for in）需求，您需要使用额外的函数调用来关闭索引变量：

var runtimefunctions = {}, i = 0;
var allLevels = {"1":"State","2":"Educational_Services","3":"Principal_Networks","4":"Schools"}
for (var key in allLevels) {
  runtimefunctions[i] = function(index){ return function() { return x(index); } }(i++);
};

这是你需要的吗

function x(number){
  return number - 10;
}

var runtimefunctions = {};

[1,2,3].forEach(function(y){
   runtimefunctions[y] = function() { return x(y); };
});

console.log(runtimefunctions[1]()); // -9
console.log(runtimefunctions[2]()); // -8
console.log(runtimefunctions[3]()); // -7

---

为了满足下一个（for in）需求，您需要使用额外的函数调用来关闭索引变量：

var runtimefunctions = {}, i = 0;
var allLevels = {"1":"State","2":"Educational_Services","3":"Principal_Networks","4":"Schools"}
for (var key in allLevels) {
  runtimefunctions[i] = function(index){ return function() { return x(index); } }(i++);
};

这要容易得多。 例如：

const createFunctionWith = (x) => {
    return (param) => console.log(x, param)
}
let a = [1,2,3].map(x => createFunctionWith(x));
console.log(a[1]("bebe")); // 2, "bebe"

这要容易得多。 例如：

const createFunctionWith = (x) => {
    return (param) => console.log(x, param)
}
let a = [1,2,3].map(x => createFunctionWith(x));
console.log(a[1]("bebe")); // 2, "bebe"

---

你可以这样做

// Found in your code
var x = (a) => {
    console.log(a)
};    

var runtimefunctions = {};

[1, 2, 3].forEach(function(y) {
    //Create a function with a parameter named "levelIterator"
    runtimefunctions[y] = Function("levelIterator", "{ console.log(levelIterator); x(" + y + ") }");

});

runtimefunctions[1]('test')

---

你可以这样做

// Found in your code
var x = (a) => {
    console.log(a)
};    

var runtimefunctions = {};

[1, 2, 3].forEach(function(y) {
    //Create a function with a parameter named "levelIterator"
    runtimefunctions[y] = Function("levelIterator", "{ console.log(levelIterator); x(" + y + ") }");

});

runtimefunctions[1]('test')

---

你是说你有一个数组，数组中的每一个值你都想调用这个函数，把这个值作为一个参数传递吗？是的，它可以有任意的数字，所以动态性太复杂了。避免在以后的求值中使用字符串，而是直接将函数分配给它们的键。关于更新：你是说你有一个数组，数组中的每个值都要调用函数，并将该值作为参数传递吗？是的，它可以有任何数字，所以动态性太复杂了。避免在以后的计算中使用字符串，而是将函数直接分配给它们的键。关于你的更新：它很有魅力，但我的错。我必须使用for循环for object而不是foreach循环..在forloop中请找到更新的问题…所有返回-6它工作起来很有魅力，但我的错。我必须使用for循环for object而不是foreach循环..在forloop中请查找更新的问题…所有返回-6