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Javascript Cypher查询正则表达式以选择顶点和边

javascript regex

Javascript Cypher查询正则表达式以选择顶点和边,javascript,regex,cypher,lex,Javascript,Regex,Cypher,Lex,我试图用匹配条件解析密码查询，以提取其顶点、连接边和返回条件。它可以有两个以上的正则表达式来查找模式。什么可以是Regex1和Regex2： MATCH (A)-[E1]->(B), (A)-[E2]->(C), (B)-[E3]->(C) WHERE E1.TYPE = ''marriedTo'' AND C.NAME = ''Ares'' RETURN A.NAME AS PARENT1_NAME, B.NAME AS PARENT2_NAME Regex1输出=['（A

我试图用匹配条件解析密码查询，以提取其顶点、连接边和返回条件。它可以有两个以上的正则表达式来查找模式。什么可以是Regex1和Regex2：

MATCH (A)-[E1]->(B), (A)-[E2]->(C), (B)-[E3]->(C)
WHERE E1.TYPE = ''marriedTo'' AND C.NAME = ''Ares''
RETURN A.NAME AS PARENT1_NAME, B.NAME AS PARENT2_NAME
Regex1输出=
['（A）-[E1]->（B）'，（A）-[E2]->（C）'，（B）-[E3]->（C）]

Regex2输出=
[E1.TYPE=“marriedTo”，“C.NAME=“Ares”]

Regex1输出=
['（a）]

Regex2输出=
[]

MATCH (a), (A)
RETURN a.NAME AS name

MATCH (a)-[e]-(b)
RETURN e.TYPE AS type
ORDER BY e.TYPE ASC

MATCH (A)-[E1]->(B), (B)-[E2]->(C)
WHERE A.NAME = 'Zeus'
RETURN A.NAME as ANAME, B.NAME AS BNAME, C.NAME AS CNAME
ORDER BY B.NAME ASC, C.NAME ASC
Regex1输出=
['（a）'（a）']

Regex2输出=
[]

MATCH (a), (A)
RETURN a.NAME AS name

MATCH (a)-[e]-(b)
RETURN e.TYPE AS type
ORDER BY e.TYPE ASC

MATCH (A)-[E1]->(B), (B)-[E2]->(C)
WHERE A.NAME = 'Zeus'
RETURN A.NAME as ANAME, B.NAME AS BNAME, C.NAME AS CNAME
ORDER BY B.NAME ASC, C.NAME ASC
Regex1输出=
['（a）-[e]-（b）]

Regex2输出=
[]

MATCH (a), (A)
RETURN a.NAME AS name

MATCH (a)-[e]-(b)
RETURN e.TYPE AS type
ORDER BY e.TYPE ASC

MATCH (A)-[E1]->(B), (B)-[E2]->(C)
WHERE A.NAME = 'Zeus'
RETURN A.NAME as ANAME, B.NAME AS BNAME, C.NAME AS CNAME
ORDER BY B.NAME ASC, C.NAME ASC
Regex1输出=
['（A）-[E1]->（B）'（B）-[E2]->（C）]

Regex2 Output=
[A.NAME='Zeus']
对于javascript版本，请查看文章的结尾

（？MATCH p=（a）-[*1..2]->（b）其中a.NAME='Chaos'按b.NAME返回b.NAME作为名称顺序。在上述情况下，它也选择了p，如何避免我在使用JavaScript时遇到这种情况？积极看待匹配问题@bulbusLet us。