单击“JavaScript类型”按钮;例如;使用Selenium和Python
我试着按一下“喜欢”按钮。我尝试过“通过xpath()查找元素”,但它对我不起作用。 不知道怎么做 以下是检查完整的类别代码:单击“JavaScript类型”按钮;例如;使用Selenium和Python,javascript,python,selenium,webautomation,Javascript,Python,Selenium,Webautomation,我试着按一下“喜欢”按钮。我尝试过“通过xpath()查找元素”,但它对我不起作用。 不知道怎么做 以下是检查完整的类别代码: <div class="grid"> <div class="user_hover_panel" style="width:100%;"> <ul class="list--horizontal f
<div class="grid">
<div class="user_hover_panel" style="width:100%;">
<ul class="list--horizontal float--left post-icons-list ng-isolate-scope" wt-on-outside-click="$ctrl.emojiOutSideClick($ctrl.postData.id)" wt-on-outside-click-enabled="$ctrl.toggleEmoji">
<li ng-class="{'selected': $ctrl.postData.is_liked, 'liked-desk' : true ,
'like-border-right' : ($ctrl.postData.privacyType == 'Personal' || $ctrl.postData.privacyType == 'Pro' || $ctrl.postData.privacyType == 'All' || $ctrl.postData.privacyType == 'Public'),
'like-border-none' : ($ctrl.postData.privacyType == 'Groups' || $ctrl.postData.privacyType == 'Staff' || $ctrl.postData.privacyType == 'Private')}" class="liked-desk like-border-right">
<a ng-mouseover="$ctrl.userContext.id != undefined && !$ctrl.isMobile && $ctrl.showLikeEmoji($ctrl.postData.id)" ng-mouseleave="$ctrl.hideLikeEmoji()" ng-click="!$ctrl.isMobile ? $ctrl.likeMedia($ctrl.postData.id, $root.context.id, $ctrl.postData.mediaTypeTagging, $ctrl.postData, true):$ctrl.toggleReaction($ctrl.postData.id)" class="cursor--pointer " data-own-entry="false">
<!-- ngIf: !$ctrl.postData.is_liked -->
<i ng-if="!$ctrl.postData.is_liked" class="icon icon-post-like private-link ng-scope">Like</i>
<!-- end ngIf: !$ctrl.postData.is_liked -->
<!-- ngIf: $ctrl.postData.is_liked -->
</a>
</li>
<li class="comment-desk" ng-click="$ctrl.togglePostCommentBox()">
<a href="javascript:" data-own-entry="false">
<i class="icon icon-post-cmt private-link">Comment</i>
</a>
</li>
<!-- ngIf: !$ctrl.isModalView && !$ctrl.isPostAsComment --><li ng-if="!$ctrl.isModalView && !$ctrl.isPostAsComment" ng-class="{
'shared-desk' : true}" ng-hide="$ctrl.postData.privacyType != 'Public'" class="ng-scope shared-desk">
<!-- ngIf: $ctrl.postData.mediaTypeTagging != 'photos' && $ctrl.checkBannerOrProfile(false) --><a data-ng-if="$ctrl.postData.mediaTypeTagging != 'photos' && $ctrl.checkBannerOrProfile(false)" href="javascript:" ng-click="$ctrl.shareMedia('news', $ctrl.postData.post_share_id ? $ctrl.postData.post_share_id : $ctrl.postData.post_id, $ctrl.postData.privacyType)" class="" data-own-entry="false">
<i class="icon icon-post-share private-link">Share</i>
</a><!-- end ngIf: $ctrl.postData.mediaTypeTagging != 'photos' && $ctrl.checkBannerOrProfile(false) -->
<!-- ngIf: $ctrl.postData.mediaTypeTagging !='news' && $ctrl.postData.mediaTypeTagging == 'photos' && $ctrl.postData.id != undefined && $ctrl.checkBannerOrProfile(false) -->
</li><!-- end ngIf: !$ctrl.isModalView && !$ctrl.isPostAsComment -->
</ul>
<!-- ngIf: $ctrl.userContext.id != undefined && $ctrl.toggleEmoji && $ctrl.postEmojiId == $ctrl.postData.id -->
</div>
</div>
我犯了这个错误
selenium.common.exceptions.NoSuchElementException: Message: no such element: Unable to locate element: {"method":"xpath","selector":"//*[@id='30247788']/div[5]/div/div/ul/li[1]/a/i"}
(Session info: chrome=90.0.4430.212)
元素最可持续的XPath如下所示:
//i[contains(text(),'Like')]
此XPath选择包含单词的所有i
标记,如
。如果您不确定此XPath是否只返回一个元素,那么还可以将其复杂化一点(例如,添加类选择器)
提示:尝试首先使用浏览器选择网站上的元素,而不是直接通过selenium。请参见您的代码在哪里?刚刚添加的,如果您可以再次查看,将非常有帮助:现在它更清晰了。用这个奇怪的XPath
/*[@id=“30247788”]/div[5]/div/div/ul/li[1]/a/i
,你想定位什么元素?实际上路径“/*[@id=“30247788”]/div[5]/div/div/ul/li[1]/a/i”是在我单击检查并复制元素的“XPath”时出现的就像``这是元素一样,我点击它并复制了Xpathhttps://www.webtalk.co/“-我看不到与您提供的Xpath匹配的like按钮和元素
selenium.common.exceptions.NoSuchElementException: Message: no such element: Unable to locate element: {"method":"xpath","selector":"//*[@id='30247788']/div[5]/div/div/ul/li[1]/a/i"}
(Session info: chrome=90.0.4430.212)
//i[contains(text(),'Like')]