Javascript 使用JS从URL传递和操作参数

Javascript 使用JS从URL传递和操作参数,javascript,html,url,formatting,parameter-passing,Javascript,Html,Url,Formatting,Parameter Passing,问题:从url读取参数,并在必要的格式设置后以HTML显示 说明: URL:www.abc.com/test.html?name=Raj%20Sharma%20&%20Anjali%20Sharma 单击事件时,它应显示以下内容: 拉杰·夏尔马和安吉利·夏尔马 到目前为止,我拥有的是以下代码: <!DOCTYPE html> <html> <head> <script type="text/javascript"> function getPara

问题:从url读取参数,并在必要的格式设置后以HTML显示

说明: URL:www.abc.com/test.html?name=Raj%20Sharma%20&%20Anjali%20Sharma

单击事件时,它应显示以下内容:

拉杰·夏尔马和安吉利·夏尔马

到目前为止,我拥有的是以下代码:

<!DOCTYPE html>
<html>
<head>
<script type="text/javascript">
function getParameter(){
var param1var = getQueryVariable("name");
document.getElementById('demo').innerHTML = param1var;
function getQueryVariable(variable) {
var query = window.location.search.substring(1);
var vars = query.split("&");
for (var i=0;i<vars.length;i++) {
var pair = vars[i].split("=");
if (pair[0] == variable) {
return pair[1];
}
} 
alert('Query Variable ' + variable + ' not found');
}
} 
</script>
</head>
<body>
<h1>Testing</h1>
<a href="javascript:void(0)" onclick="getParameter()" id="continue">Click</a>

<p id="demo"></p>

</body>
</html> 

函数getParameter(){
var param1var=getQueryVariable(“名称”);
document.getElementById('demo').innerHTML=param1var;
函数getQueryVariable(变量){
var query=window.location.search.substring(1);
var vars=query.split(&);

对于(var i=0;i而言,这足以获得该输出:

 var query = decodeURIComponent(window.location.search.substring(1).split('=').pop());
查询:“Raj Sharma&Anjali Sharma”


我解决问题了吗?