Warning: file_get_contents(/data/phpspider/zhask/data//catemap/1/asp.net/33.json): failed to open stream: No such file or directory in /data/phpspider/zhask/libs/function.php on line 167

Warning: Invalid argument supplied for foreach() in /data/phpspider/zhask/libs/tag.function.php on line 1116

Notice: Undefined index: in /data/phpspider/zhask/libs/function.php on line 180

Warning: array_chunk() expects parameter 1 to be array, null given in /data/phpspider/zhask/libs/function.php on line 181
Javascript 如何使我的弹出页面成为子页面_Javascript_Asp.net_Vb.net - Fatal编程技术网

Javascript 如何使我的弹出页面成为子页面

Javascript 如何使我的弹出页面成为子页面,javascript,asp.net,vb.net,Javascript,Asp.net,Vb.net,如何使我的弹出页面作为子页面 说明: User can not do any operation in parent page till the popup page is not closed. It should only allow after popup page is closed. 您可以使用ajax模式弹出扩展程序 首先,您必须有一个脚本管理器作为 <asp:ScriptManager ID="ScriptManager1" runat="server" > <

如何使我的弹出页面作为子页面

说明:

User can not do any operation in parent page till the popup page is not closed.
It should only allow after popup page is closed.

您可以使用ajax模式弹出扩展程序

首先,您必须有一个脚本管理器作为

<asp:ScriptManager ID="ScriptManager1" runat="server" >
</asp:ScriptManager>

有关更多详细信息,请参阅…

您没有发布任何代码,甚至没有提出任何有意义的问题。您似乎发布了来自uni作业的内容。在发布问题之前,请先阅读规则。该描述是否是从某个需求文档中复制的?
<asp:Button ID="btnShowPopup" runat="server" CssClass="m-btn purple" style="display:none" />
<asp:ModalPopupExtender ID="ModalPopup1" runat="server" DynamicServicePath="" 
 Enabled="True" TargetControlID="btnShowPopup" CancelControlID="idclose" Drag="true" popupControlID="Name of your popup" >
 </asp:ModalPopupExtender>
ModalPopup1.show();