Javascript 使用JS解析Json中的嵌套对象
我有一个Json格式:Javascript 使用JS解析Json中的嵌套对象,javascript,jquery,json,parsing,loops,Javascript,Jquery,Json,Parsing,Loops,我有一个Json格式: {"year":{"month1":{"date1":{"device1":{"users":6}}}} 样本: {"2013":{"2":{"5":{"GT-N7000":{"users":1}},"6":{"GT-N7000":{"users":9},"HTC Sensation Z710a":{"users":1}},"7":{"GT-N7000":{"users":15},"HTC Sensation Z710a":{"users":2},"M903":{"us
{"year":{"month1":{"date1":{"device1":{"users":6}}}}
样本:
{"2013":{"2":{"5":{"GT-N7000":{"users":1}},"6":{"GT-N7000":{"users":9},"HTC Sensation Z710a":{"users":1}},"7":{"GT-N7000":{"users":15},"HTC Sensation Z710a":{"users":2},"M903":{"users":1}}}}}
如何从Json生成新的用户数组。例如:
GT-N7000 = [1, 9, 15]
M903 = [1]
我尝试了嵌套
for
循环,也尝试了for..in
循环。我肯定我犯了一个错误。您知道如何过滤/解析此类嵌套json对象所需的信息吗?大多数现代浏览器都支持原生json.parse方法。有关详细信息,请参见此问题大多数现代浏览器都支持本机JSON.parse方法。有关详细信息,请参见此问题我想您会这样做:
var json = {"2013":{"2":{"5":{"GT-N7000":{"users":1}},"6":{"GT-N7000":{"users":9},"HTC Sensation Z710a":{"users":1}},"7":{"GT-N7000":{"users":15},"HTC Sensation Z710a":{"users":2},"M903":{"users":1}}}}};
var result = {}, year, month, date, item;
for (year in json) {
for(month in json[year]) {
for(date in json[year][month]) {
for(item in json[year][month][date]) {
if(item in result) {
result[item].push(json[year][month][date][item].users) // this bit might need editing?
} else {
result[item] = [json[year][month][date][item].users] // this be also might need editing
}
}
}
}
}
我可以想象你会这样做:
var json = {"2013":{"2":{"5":{"GT-N7000":{"users":1}},"6":{"GT-N7000":{"users":9},"HTC Sensation Z710a":{"users":1}},"7":{"GT-N7000":{"users":15},"HTC Sensation Z710a":{"users":2},"M903":{"users":1}}}}};
var result = {}, year, month, date, item;
for (year in json) {
for(month in json[year]) {
for(date in json[year][month]) {
for(item in json[year][month][date]) {
if(item in result) {
result[item].push(json[year][month][date][item].users) // this bit might need editing?
} else {
result[item] = [json[year][month][date][item].users] // this be also might need editing
}
}
}
}
}
请发布您的代码,我们可能会帮助您。请发布您的代码,我们可能会帮助您。