JavaScript localeCompare排序不好[“aaa-1.0”、“aaa-1.1”、“aaa-1.01”、“aaa-11”、“aaa-2.01”]

我想按十进制数值和字母顺序对字符串进行排序。保持它的自然秩序

var strArray = ["aaa-0", "aaa-0.01", "aaa-1.0", "aaa-1.1", "aaa-1.01", "aaa-2.01", "bbb-2.01", "aaa-11", "aaa-2.01"]

strArray.sort(function (a, b) {
    return a.localeCompare(b,undefined, {numeric: true, sensitivity: 'base'});
});

返回：

["aaa-0", "aaa-0.01", "aaa-1.0", "aaa-1.1", "aaa-1.01", "aaa-2.01", "aaa-2.01", "aaa-11", "bbb-2.01"]

虽然我想要：

["aaa-0", "aaa-0.01", "aaa-1.0", "aaa-1.01", "aaa-1.1", "aaa-2.01", "aaa-2.01", "aaa-11", "bbb-2.01"]

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如何才能做到这一点？即使我用，而不是。排序是相同的。

您需要分别对数字和字母进行排序

演示

var strArray=[aaa-0，aaa-0.01，aaa-1.0，aaa-1.1，aaa-1.01，aaa-2.01，bbb-2.01，aaa-11，aaa-2.01] strArray.sortfunctiona，b{ var splitA=a.split-； var splitB=b.split-； 如果splitA[0]==splitB[0]{ 返回NumbersplitA[1]-NumbersplitB[1]； }否则{ 返回splitA[0].localecompareplitb[0]，未定义{ 数字：对， 敏感度：“基本” }; } }; 控制台。日志阵列 您可以将中的标志IgnorePerception设置为true

变量数组=[aaa-0，aaa-0.01，aaa-1.0，aaa-1.1，aaa-1.01，aaa-2.01，bbb-2.01，aaa-11，aaa-2.01] array.sort函数a，b{ 返回a.localeCompareb，未定义，{IgnorePerception:true，numeric:true，sensitivity:'base'}； }; console.logarray；

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.作为控制台包装器{max height:100%！important；top:0；}@GabrielBleu，而不是在边缘。@GabrielBleu，它似乎依赖于用户代理实现。在我的情况下，它是有效的，不幸的是，它不是通用解决方案。谢谢