Javascript JS-将JSON的嵌套数组转换为单个对象

我想将嵌套的JSON结构转换为单个对象，使用下面代码中使用的动态键，但它只适用于一个级别，我需要编写一些递归函数，我正在努力为n个级别的嵌套JSON编写代码。请告知

   data.map((e) => {
   for (let key in e) {
     if (typeof e[key] === "object") {
       for (let onLevel in e[key]) {
         e[key + "." + onLevel] = e[key][onLevel];
       }
     }
   }
 });

示例

输入JSON

[{
  "Id": "0hb3L00000000jkQAA",
  "Name": "P-2797",
  "ContactEncounterId": "0ha3L000000001qQAA",
  "StartTime": "2020-06-27T11:00:00.000Z",
  "EncounterDuration": 25,
  "ContactEncounter": {
    "Name": "Grocery Shopping 17",
    "LocationId": "1313L0000004ENlQAM",
    "Id": "0ha3L000000001qQAA",
    "Location": {
      "Name": "Waitrose",
      "LocationType": "Site",
      "Id": "1313L0000004ENlQAM"
    }
  }
}]

[{
  "Id": "0hb3L00000000jkQAA",
  "Name": "P-2797",
  "ContactEncounterId": "0ha3L000000001qQAA",
  "StartTime": "2020-06-27T11:00:00.000Z",
  "EncounterDuration": 25,
  "ContactEncounter.Name": "Grocery Shopping 17",
  "ContactEncounter.LocationId": "1313L0000004ENlQAM",
  "ContactEncounter.Id": "0ha3L000000001qQAA",
  "ContactEncounter.Location.Name": "Waitrose",
  "ContactEncounter.Location.LocationType": "Site",
  "ContactEncounter.Location.Id": "1313L0000004ENlQAM"
}]

输出JSON

[{
  "Id": "0hb3L00000000jkQAA",
  "Name": "P-2797",
  "ContactEncounterId": "0ha3L000000001qQAA",
  "StartTime": "2020-06-27T11:00:00.000Z",
  "EncounterDuration": 25,
  "ContactEncounter": {
    "Name": "Grocery Shopping 17",
    "LocationId": "1313L0000004ENlQAM",
    "Id": "0ha3L000000001qQAA",
    "Location": {
      "Name": "Waitrose",
      "LocationType": "Site",
      "Id": "1313L0000004ENlQAM"
    }
  }
}]

[{
  "Id": "0hb3L00000000jkQAA",
  "Name": "P-2797",
  "ContactEncounterId": "0ha3L000000001qQAA",
  "StartTime": "2020-06-27T11:00:00.000Z",
  "EncounterDuration": 25,
  "ContactEncounter.Name": "Grocery Shopping 17",
  "ContactEncounter.LocationId": "1313L0000004ENlQAM",
  "ContactEncounter.Id": "0ha3L000000001qQAA",
  "ContactEncounter.Location.Name": "Waitrose",
  "ContactEncounter.Location.LocationType": "Site",
  "ContactEncounter.Location.Id": "1313L0000004ENlQAM"
}]

---

正如您所说，您需要创建一个递归来深入对象。也就是说，你必须跟踪你所在的路径

你可以用下面的方法解决它

const输入=[{
“Id”：“0hb3L00000000jkQAA”，
“名称”：“P-2797”，
“ContactEncounterId”：“0HA3L000000001QQQAA”，
“开始时间”：“2020-06-27T11:00:00.000Z”，
“遭遇”：25，
“接触接触”：{
“名称”：“杂货店购物17”，
“位置ID”：“1313L0000004ENlQAM”，
“Id”：“0HA3L000000001QQQAA”，
“地点”：{
“姓名”：“Waitrose”，
“地点类型”：“地点”，
“Id”：“1313L0000004ENlQAM”
}
}
}
];
函数合并（源，目标={}，…父）{
for（让Object.entries的[key，value]（源））{
常量路径=（父项| |[]）.concat（键）；
如果（值的类型==='object'）{
合并（值、目标、路径）；
继续；
}
目标[path.join（'.'）]=value；
}
回报目标；
}
console.log（合并（输入[0]）这里是另一种方法，在查找第n级对象时使用第二个参数并传递键


const obj={
“Id”：“0hb3L00000000jkQAA”，
“名称”：“P-2797”，
“ContactEncounterId”：“0HA3L000000001QQQAA”，
“开始时间”：“2020-06-27T11:00:00.000Z”，
“遭遇”：25，
“接触接触”：{
“名称”：“杂货店购物17”，
“位置ID”：“1313L0000004ENlQAM”，
“Id”：“0HA3L000000001QQQAA”，
“地点”：{
“姓名”：“Waitrose”，
“地点类型”：“地点”，
“Id”：“1313L0000004ENlQAM”
}
}
}
函数展平obj（obj，参数）{
设newObj={}；
用于（输入obj）{
如果（对象的类型[键]=“对象”）{
newObj={……newObj，
…展平obj（obj[key]，key+'。）
}
}否则{
newObj[param+key]=obj[key]
}
}
返回newObj；
}
log（flattobj（obj，，）
那不是。输入和输出都是带有一个对象的数组->