Javascript 日历未显示正确的成员事件

我有一个有多个成员的网站，我希望每个成员都有自己的日历。 我找到了一个构建和事件日历witch的教程，它工作得很好，但是我在尝试将事件显示在正确的日历上时遇到了困难，要么每个人都可以看到数据库中的所有事件，要么没有人可以看到任何事件

我的代码如下

calendar_start.php

<?php 

$showmonth = $_POST['showmonth'];
$showyear = $_POST['showyear'];
$showmonth = preg_replace('#[^0-9]#i', '', $showmonth);
$showyear = preg_replace('#[^0-9]#i', '', $showyear);


$day_count = cal_days_in_month(CAL_GREGORIAN, $showmonth, $showyear);
$pre_days = date('w', mktime(0,0,0, $showmonth, 1, $showyear));
$post_days = (6 - (date('w', mktime(0,0,0, $showmonth, $day_count, $showyear))));

echo '<div id="calender_wrap">';

echo '<div class="title_bar">';
echo '<div class="previouse_month"><input name="myBtn" type="submit" value="Previouse Month" onclick="javascript:last_month();"></div';
echo '<div class="show_month">' . $showmonth . '/' . $showyear . '</div>';
echo '<div class="next_month"><input name="myBtn" type="submit" value="Next Month" onclick="javascript:next_month();"></div>';
echo '</div>';

echo '<div class="week_days">';
echo '<div class="days_of_week">Sunday</div>';
echo '<div class="days_of_week">Monday</div>';
echo '<div class="days_of_week">Tuesday</div>';
echo '<div class="days_of_week">Wednesday</div>';
echo '<div class="days_of_week">Thursday</div>';
echo '<div class="days_of_week">Friday</div>';
echo '<div class="days_of_week">saturday</div>';
echo '<div class="clear"></div>';
echo '</div>';

/* Previouse Month filler Days */
if ($pre_days != 0) {
    for($i = 1; $i<=$pre_days; $i++) {
        echo '<div class="non_cal_day"></div>';
    }
}

/*Current Month filler Days */
include("scripts/connect_to_mysql.php");
for($i = 1; $i<= $day_count; $i++) {
    // get event logic

    $date = $i . '/' . $showmonth . '/' . $showyear;
    $query = "SELECT * FROM occurrences WHERE cid ='$squadid' AND start_date ='$date' ";
    $cal = mysqli_query($db_conx, $query);
    $num_rows = mysqli_num_rows($cal);
        if($num_rows > 0) {
            $event= '<a href="view_events.php"><h3 class="event_here">Events Here</h3></a>';
            }
        //end get event logic

    echo '<div class="cal_day">';
    echo '<div class="day_heading">' . $i . ' <a href="add_event.php"><div class="add_event"></div></a></div><br/>';
    if($num_rows != 0) { echo $event;}
    echo '</div>';
}

/* Next month filler days */
if ($post_days != 0) {
    for($i = 1; $i<=$post_days; $i++) {
        echo '<div class="non_cal_day"></div>';
    }
}

echo '</div>';

?>

---

在您的calendar\u start.php（即由ajax请求触发的文件）中，var$squadid是空的。您需要将$squadid从show_calendar.php发送到calendar_start.php以抛出ajax请求

以下是一个例子：

  //Ajax request example from show_calendar.php
    var hr = new XMLHttpRequest();
    var url = "calender_start.php";
    var currentTime = new Date();
    var month = currentTime.getMonth() + 1;
    var year = currentTime.getFullYear();
    showmonth = month;
    showyear = year;
    var vars = "showmonth="+showmonth+"&showyear="+showyear+"&squadid=<?= $squadid; ?>";
    hr.open("POST", url, true);
    hr.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
    hr.onreadystatechange = function() {
        if(hr.readyState == 4 && hr.status == 200) {
            var return_data = hr.responseText;
            document.getElementById("showCalendar") .innerHTML = return_data;
        }
    }
    hr.send(vars);
    document.getElementById("showCalendar") .innerHTML = "processing...";


    //Get the var in calendar_start.php add this line
    $squadid = $_POST['squadid'];

//show_calendar.php中的Ajax请求示例
var hr=新的XMLHttpRequest（）；
var url=“calender\u start.php”；
var currentTime=新日期（）；
var month=currentTime.getMonth（）+1；
var year=currentTime.getFullYear（）；
showmonth=月份；
showyear=year；
var vars=“showmonth=“+showmonth+”&showyear=“+showyear+”&squadid=“；
hr.open（“POST”，url，true）；
hr.setRequestHeader（“内容类型”、“应用程序/x-www-form-urlencoded”）；
hr.onreadystatechange=函数（）{
如果（hr.readyState==4&&hr.status==200）{
var return_data=hr.responseText；
document.getElementById（“showCalendar”）.innerHTML=返回\u数据；
}
}
人力资源发送（vars）；
document.getElementById（“showCalendar”）.innerHTML=“处理…”；
//在calendar_start.php中获取var添加此行
$squadid=$_POST['squadid']；

希望这对你有帮助。
干杯
 嗨，格鲁吉亚人，我已经尝试过你的建议，但不幸的是，仍然无法使其发挥作用。我把$squadid=$_POST['squadid']放在这里对吗；在calendar_start.php中？首先，从ajax发送它，然后发送它；what’你的意思是通过ajax发送吗？你是说这行：var vars=“showmonth=“+showmonth+”&showyear=“+showyear+”&squadid=“；如果是这样，我已经添加了这个，但仍然无法看到事件。我还缺什么吗？当我遇到这些小麻烦的时候，这通常是很明显的。谢谢你的帮助
  //Ajax request example from show_calendar.php
    var hr = new XMLHttpRequest();
    var url = "calender_start.php";
    var currentTime = new Date();
    var month = currentTime.getMonth() + 1;
    var year = currentTime.getFullYear();
    showmonth = month;
    showyear = year;
    var vars = "showmonth="+showmonth+"&showyear="+showyear+"&squadid=<?= $squadid; ?>";
    hr.open("POST", url, true);
    hr.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
    hr.onreadystatechange = function() {
        if(hr.readyState == 4 && hr.status == 200) {
            var return_data = hr.responseText;
            document.getElementById("showCalendar") .innerHTML = return_data;
        }
    }
    hr.send(vars);
    document.getElementById("showCalendar") .innerHTML = "processing...";


    //Get the var in calendar_start.php add this line
    $squadid = $_POST['squadid'];