Javascript 转置JSON数据
我知道这上面有线程,但我不明白,可能需要关于json文件的帮助。我想将json绑定到我的一个SAPUI5控件,但我没有转换它 问题是,我的数据已经在前端,所以我不想再进行第二次后端调用,我需要转换我的json数据 这是我得到的,专栏是Mon01。。等等Javascript 转置JSON数据,javascript,json,sapui5,transpose,Javascript,Json,Sapui5,Transpose,我知道这上面有线程,但我不明白,可能需要关于json文件的帮助。我想将json绑定到我的一个SAPUI5控件,但我没有转换它 问题是,我的数据已经在前端,所以我不想再进行第二次后端调用,我需要转换我的json数据 这是我得到的,专栏是Mon01。。等等 Mon01 Mon02 Mon03 Mon04 0 03/2015 04/2015 05/2015 06/2015 1 1 3 5 21 2 2 4 6
Mon01 Mon02 Mon03 Mon04
0 03/2015 04/2015 05/2015 06/2015
1 1 3 5 21
2 2 4 6 22
3 10 11 12 23
这就是我想要的:
Mon01 Mon02 Mon03 Mon04
0 03/2015 1 2 10
1 04/2015 3 4 11
2 05/2015 5 6 12
3 06/2015 21 22 23
d :
[
0: {
Mon01: "03/2015",
Mon02: "1,0",
Mon03: "2,0",
Mon04: "3,0",
Mon05: "",
Mon06: "",
},
1: {
Mon01: "04/2015",
Mon02: "3,0",
Mon03: "4,0",
Mon04: "11,0",
Mon05: "",
Mon06: "",
},
2: {
Mon01: "05/2015",
Mon02: "5,0",
Mon03: "6,0",
Mon04: "12,0",
Mon05: "",
Mon06: "",
},
length: 3
]
或者在JSON中,我得到了:
d :
[
0: {
Mon01: "03/2015",
Mon02: "04/2015",
Mon03: "05/2015",
},
1: {
Mon01: "1,0",
Mon02: "3,0",
Mon03: "5,0",
},
2: {
Mon01: "2,0",
Mon02: "4,0",
Mon03: "6,0",
Mon04: "",
Mon05: "",
Mon06: "",
},
3: {
Mon01: "10,0",
Mon02: "11,0",
Mon03: "12,0",
Mon04: "",
Mon05: "",
Mon06: "",
},
length: 3
]
在JSON中,我想要的是:
Mon01 Mon02 Mon03 Mon04
0 03/2015 1 2 10
1 04/2015 3 4 11
2 05/2015 5 6 12
3 06/2015 21 22 23
d :
[
0: {
Mon01: "03/2015",
Mon02: "1,0",
Mon03: "2,0",
Mon04: "3,0",
Mon05: "",
Mon06: "",
},
1: {
Mon01: "04/2015",
Mon02: "3,0",
Mon03: "4,0",
Mon04: "11,0",
Mon05: "",
Mon06: "",
},
2: {
Mon01: "05/2015",
Mon02: "5,0",
Mon03: "6,0",
Mon04: "12,0",
Mon05: "",
Mon06: "",
},
length: 3
]
我所做的不是最好的方法(但有效)移动每一行的单一方法:
transpose : function(oTreeAll) {
var oTreeNew = new Array();
var oTreeSingle = {};
oTreeSingle.Mon01 = oTreeAll[0].Mon01.replace(',', '.');
oTreeSingle.Mon02 = oTreeAll[1].Mon01.replace(',', '.');
oTreeSingle.Mon03 = oTreeAll[2].Mon01.replace(',', '.');
oTreeSingle.Mon04 = oTreeAll[3].Mon01.replace(',', '.');
oTreeNew.push(oTreeSingle);
var oTreeSingle1 = {};
oTreeSingle1.Mon01 = oTreeAll[0].Mon02.replace(',', '.');
oTreeSingle1.Mon02 = oTreeAll[1].Mon02.replace(',', '.');
oTreeSingle1.Mon03 = oTreeAll[2].Mon02.replace(',', '.');
oTreeSingle1.Mon04 = oTreeAll[3].Mon02.replace(',', '.');
oTreeNew.push(oTreeSingle1);
var oTreeSingle2 = {};
oTreeSingle2.Mon01 = oTreeAll[0].Mon03.replace(',', '.');
oTreeSingle2.Mon02 = oTreeAll[1].Mon03.replace(',', '.');
oTreeSingle2.Mon03 = oTreeAll[2].Mon03.replace(',', '.');
oTreeSingle2.Mon04 = oTreeAll[3].Mon03.replace(',', '.');
oTreeNew.push(oTreeSingle2);
var data = {
"d" : {
"results" : oTreeNew,
}
};
return data;
},
你会怎么做?我已经读了很多关于map函数的书,但是我不了解它的工作方式或者如何使它适应我的json,有人能帮我吗?非常感谢强>
感谢Shibaji Chakraborty,我得到了json的解决方案:
转置:函数(oTreeAll){
var键=[];
var i=0;
for(oTreeAll[i]中的var键){
按键。按(键);
}
控制台日志(键);
var newObj={
d:[]
};
newObj['length']=oTreeAll.length;
for(var k=0;k
请查找以下代码:
var data = {d :
[
{
Mon01: "03/2015",
Mon02: "04/2015",
Mon03: "05/2015",
},
{
Mon01: "1,0",
Mon02: "3,0",
Mon03: "5,0",
},
{
Mon01: "2,0",
Mon02: "4,0",
Mon03: "6,0",
Mon04: "",
Mon05: "",
Mon06: "",
},
{
Mon01: "10,0",
Mon02: "11,0",
Mon03: "12,0",
Mon04: "",
Mon05: "",
Mon06: "",
}
],
length: 3};
//console.log(data.d[0]);
var keys = [];
for(var key in data.d[data.length]){
//console.log(key);
keys.push(key);
}
var newObj = {d:[]};
newObj['length'] = data.length;
for(var k =0;k<data.length;k++){
var obj = {};
for(var cnt in keys){
obj[keys[cnt]] = "";
}
newObj.d.push(obj);
}
for(var k =0;k<data.length;k++){
//var obj = {};
//console.log(k);
for(var j=0;j<data.length;j++){
newObj.d[k][keys[j]] = data.d[j][keys[k]];
}
}
console.log(newObj);
var数据={d:
[
{
周一:“2015年3月3日”,
周一02:04/2015,
周一03:05/2015,
},
{
周一:“1,0”,
周一02:3,0,
Mon03:“5,0”,
},
{
周一:“2,0”,
周一02:4,0,
周一03:6,0,
星期一:,
星期一,
星期一,
},
{
周一:“10,0”,
周一02:11,0,
周一03:12,0,
星期一:,
星期一,
星期一,
}
],
长度:3};
//console.log(data.d[0]);
var键=[];
for(data.d[data.length]中的var键){
//控制台日志(键);
按键。按(键);
}
var newObj={d:[]};
newObj['length']=data.length;
对于(var k=0;khey Shibaji,非常接近,目前在键中有“0”,“1”,因为在我的json中有另一个级别-->d:[0:{Mon01:“03/2015”…..,您能帮我吗?