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Javascript 从Ajax调用控制器获取参数_Javascript_Jquery_Ajax_Grails - Fatal编程技术网

Javascript 从Ajax调用控制器获取参数

Javascript 从Ajax调用控制器获取参数,javascript,jquery,ajax,grails,Javascript,Jquery,Ajax,Grails,我的ajax调用正在传递以下数据: var quoteParams ={check:true,startDate:date} $.ajax({ type: "POST", url: "check/save", data: {orderForm : gatherOrderDetails(), quoteForm : quoteParams } , // GatherORderDetails will get all the form in

我的ajax调用正在传递以下数据:

var quoteParams ={check:true,startDate:date}
 $.ajax({
        type: "POST",
        url: "check/save",
        data: {orderForm : gatherOrderDetails(), quoteForm : quoteParams } ,      // GatherORderDetails will get all the form input values from a form


        success: function(msg) {
            alert(msg.d);
        },
        error: function(msg) {
        alert('error');
        }

    });
因此,在我的控制器中,我希望将“orderform”和“quoteForm”作为类的对象。类是类ordersForm和类quotesForm

def save(ordersForm orderForm,quotesForm quoteForm){
//now i need to save all the details obtained from 'orderform' and 'quoteform' after procerssing them in database.

}

但我得到一个错误,即参数无效。

只需定义如下保存操作:

def save() {
    // do stuff with orderForm
    params.orderForm

    // do stuff with quoteForm
    params.quoteForm 
}
另外,看看哪种方法可以大大简化事物的持久性方面

不确定javascript gatherOrderDetails()函数在做什么,但如果只需要提交所有表单元素,则可以使用


我想说的是,您应该通过
request.JSON
访问它:

def save() {
    def json = request.JSON
    doSomething json.orderForm
    doSomethingElse json.quoteForm 
}

刚改了,值是多少​​您通过ajax传递的数据是多少?我只是使用了param,然后将其设置为类new object的instace
def save() {
    def json = request.JSON
    doSomething json.orderForm
    doSomethingElse json.quoteForm 
}