Javascript 矩阵缩放/从点平移
我正在尝试缩放图像,并使其从原点正确平移(基本上是从收缩到缩放)。我试图找到一个不涉及更改Javascript 矩阵缩放/从点平移,javascript,css,math,matrix,Javascript,Css,Math,Matrix,我正在尝试缩放图像,并使其从原点正确平移(基本上是从收缩到缩放)。我试图找到一个不涉及更改变换原点的解决方案,因为它会使查找图片的左/上边缘变得复杂,我使用它不仅仅解决这个问题 这更像是一道数学题根据原点,我很难找到一个方程式来确定图像的平移量。我计算出的当前方程式不能从一个点正确缩放。关于演示,使用鼠标滚动时,图像应该从鼠标指针放大 var image_center = $("#image"); var base_image = $(".outer"); var dim = {}; func
变换原点的解决方案,因为它会使查找图片的左/上边缘变得复杂,我使用它不仅仅解决这个问题
这更像是一道数学题根据原点,我很难找到一个方程式来确定图像的平移量。我计算出的当前方程式不能从一个点正确缩放。关于演示,使用鼠标滚动时,图像应该从鼠标指针放大
var image_center = $("#image");
var base_image = $(".outer");
var dim = {};
function resetDim() {
// Initialize image.dim with values
dim.cont_width = base_image.width(); // Container width
dim.cont_height = base_image.height(); // Container height
dim.width = image_center.width(); // Element width
dim.height = image_center.height(); // Element height
dim.left_edge = 0;
dim.top_edge = 0; // Edge translation
dim.init_x = 0;
dim.new_x = 0; // Initial/new x position
dim.init_y = 0;
dim.new_y = 0; // Initial/new y position
dim.init_scale = 1;
dim.new_scale = 1; // Initial/new scale
dim.max_scale = 3; // Max image scale
};
function transform() {
var matrix = [dim.new_scale, 0, 0, dim.new_scale, dim.new_x, dim.new_y].join(",");
image_center.css({
"transform": "matrix(" + matrix + ") translate3d(0, 0, 0)",
"-webkit-transform": "matrix(" + matrix + ") translate3d(0, 0, 0)",
"-moz-transform": "matrix(" + matrix + ") translate3d(0, 0, 0)",
});
}
$(document).ready(function() {
resetDim();
transform();
$('.outer').bind('mousewheel', function(ev) {
// onScroll start
// Determine pointer origin in relation to picture
var offset = image_center.offset();
var originX = ev.originalEvent.pageX - offset.left;
var originY = ev.originalEvent.pageY - offset.top;
// Calculate current size of the image.
var width = dim.width * dim.new_scale;
var height = dim.height * dim.new_scale;
// Calculate the relative position of the mouse independent of current scale.
var mx = originX / width;
var my = originY / height;
// onScroll ev
dim.new_scale += (ev.originalEvent.deltaY > 0) ? -0.1 : 0.1;
if (dim.new_scale > dim.max_scale) dim.new_scale = dim.max_scale;
else if (dim.new_scale < 1) dim.new_scale = 1;
// Update new image position based upon new scale.
var new_width = dim.width * dim.new_scale;
var new_height = dim.height * dim.new_scale;
var new_mouse_x = new_width * mx;
var new_mouse_y = new_height * my;
dim.new_x += originX - new_mouse_x;
dim.new_y += originY - new_mouse_y;
transform();
});
});
我不是在寻找解决方法,也不是在寻找替代设计。如前所述,我无法修改“变换原点”属性
演示:
矩阵变换函数
function transform() {
var matrix = [dim.new_scale, 0, 0, dim.new_scale, dim.new_x, dim.new_y].join(",");
image_center.css({
"transform": "matrix(" + matrix + ") translate3d(0, 0, 0)",
"-webkit-transform": "matrix(" + matrix + ") translate3d(0, 0, 0)",
"-moz-transform": "matrix(" + matrix + ") translate3d(0, 0, 0)",
});
}
鼠标轮事件
// Determine mousewheel pointer in relation to picture origin
var offset = image_center.offset();
var originX = ev.originalEvent.pageX - offset.left;
var originY = ev.originalEvent.pageY - offset.top;
// truncated --- new_scale is modified
// Translate based on pointer origin -- This is where I need help
dim.new_x = originX + dim.height * (dim.new_scale - 1);
dim.new_y = originY + dim.height * (dim.new_scale - 1);
// truncated -- Keep image within constraints
transform(); // Applies everything in dim to CSS transform matrix
我得到了部分解决方案。我想它可以做你想做的,放大和缩小鼠标指定的点。不幸的是,如果您缩放,然后将鼠标移动到另一个点,然后再次缩放,它会跳转
var image_center = $("#image");
var base_image = $(".outer");
var dim = {};
var original_offset = image_center.offset();
function resetDim() {
// Initialize image.dim with values
dim.cont_width = base_image.width(); // Container width
dim.cont_height = base_image.height(); // Container height
dim.width = image_center.width(); // Element width
dim.height = image_center.height(); // Element height
dim.new_x = 0; // Initial/new x position
dim.new_y = 0; // Initial/new y position
dim.new_scale = 1; // Initial/new scale
dim.max_scale = 3; // Max image scale
};
function transform() {
var matrix = [dim.new_scale, 0, 0, dim.new_scale, dim.new_x, dim.new_y].join(",");
image_center.css({
"transform": "matrix(" + matrix + ") translate3d(0, 0, 0)",
"-webkit-transform": "matrix(" + matrix + ") translate3d(0, 0, 0)",
"-moz-transform": "matrix(" + matrix + ") translate3d(0, 0, 0)",
});
}
$(document).ready(function() {
resetDim();
$('.outer').bind('mousewheel', function(ev) {
// onScroll start
// Determine pointer origin in relation to picture
var originX = ev.originalEvent.pageX - original_offset.left;
var originY = ev.originalEvent.pageY - original_offset.top;
// onScroll ev
dim.new_scale += (ev.originalEvent.deltaY > 0) ? -0.1 : 0.1;
if (dim.new_scale > dim.max_scale) dim.new_scale = dim.max_scale;
else if (dim.new_scale < 1) dim.new_scale = 1;
// Translate based on origin
dim.new_x = -(originX * (dim.new_scale-1) );
dim.new_y = -(originY * (dim.new_scale-1) );
transform();
});
});
var image_center=$(“#image”);
var base_image=$(“.outer”);
var dim={};
var original_offset=图像_center.offset();
函数resetDim(){
//使用值初始化image.dim
dim.cont_width=base_image.width();//容器宽度
dim.cont_height=base_image.height();//容器高度
dim.width=image_center.width();//元素宽度
dim.height=image_center.height();//元素高度
dim.new_x=0;//初始/新x位置
dim.new_y=0;//初始/新y位置
dim.new_scale=1;//初始/新比例
dim.max_scale=3;//最大图像比例
};
函数变换(){
变量矩阵=[dim.new_scale,0,0,dim.new_scale,dim.new_x,dim.new_y]。连接(“,”;
image_center.css({
“变换”:“矩阵(“+matrix+”)translate3d(0,0,0)”,
“-webkit转换”:“矩阵(“+matrix+”)translate3d(0,0,0)”,
“-moz变换”:“矩阵(“+matrix+”)translate3d(0,0,0)”,
});
}
$(文档).ready(函数(){
resetDim();
$('.outer').bind('mousewheel',函数(ev){
//onScroll启动
//确定指针相对于图片的原点
var originX=ev.originalEvent.pageX-原始偏移量。左;
var originY=ev.originalEvent.pageY-原始偏移量.top;
//昂斯克罗尔电动汽车
dim.new_scale+=(ev.OriginaleEvent.deltaY>0)?-0.1:0.1;
如果(尺寸新刻度>尺寸最大刻度)尺寸新刻度=尺寸最大刻度;
否则,如果(尺寸新刻度<1)尺寸新刻度=1;
//基于原点的翻译
dim.new_x=-(originX*(dim.new_scale-1));
dim.new_y=-(原始*(dim.new_scale-1));
transform();
});
});
一种简单的方法是创建屏幕外对象并将其变换原点居中。将缩放应用于此对象
然后将矩阵变换从屏幕外的元素复制到屏幕上的元素,您应该具有正确的比例
以下是一些复制矩阵的图像原型:
HTMLImageElement.prototype.getMatrix = function() {
var st = window.getComputedStyle(this, null);
return st.getPropertyValue("-webkit-transform") ||
st.getPropertyValue("-moz-transform") ||
st.getPropertyValue("-ms-transform") ||
st.getPropertyValue("-o-transform") ||
st.getPropertyValue("transform") ||
'none';
};
HTMLImageElement.prototype.setMatrix = function(matrix) {
this.style.webkitTransform =
this.style.msTransform =
this.style.MozTransform =
this.style.OTransform =
this.style.transform =
matrix;
return this;
};
getMatrix
返回矩阵字符串。
setMatrix
获取矩阵字符串
targetImage.setMatrix(sourceImage.getMatrix())
WARE targetImage是显示的图像
而sourceImage是屏幕外图像请尝试以下操作:
当然,如果滚动太快,过渡将无法保持,但如果滚动太慢,图像将保持锁定在鼠标上
var image_center = $("#image");
var base_image = $(".outer");
var dim = {};
function resetDim() {
// Initialize image.dim with values
dim.cont_width = base_image.width(); // Container width
dim.cont_height = base_image.height(); // Container height
dim.width = image_center.width(); // Element width
dim.height = image_center.height(); // Element height
dim.left_edge = 0;
dim.top_edge = 0; // Edge translation
dim.init_x = 0;
dim.new_x = 0; // Initial/new x position
dim.init_y = 0;
dim.new_y = 0; // Initial/new y position
dim.init_scale = 1;
dim.new_scale = 1; // Initial/new scale
dim.max_scale = 3; // Max image scale
};
function transform() {
var matrix = [dim.new_scale, 0, 0, dim.new_scale, dim.new_x, dim.new_y].join(",");
image_center.css({
"transform": "matrix(" + matrix + ") translate3d(0, 0, 0)",
"-webkit-transform": "matrix(" + matrix + ") translate3d(0, 0, 0)",
"-moz-transform": "matrix(" + matrix + ") translate3d(0, 0, 0)",
});
}
$(document).ready(function() {
resetDim();
transform();
$('.outer').bind('mousewheel', function(ev) {
// onScroll start
// Determine pointer origin in relation to picture
var offset = image_center.offset();
var originX = ev.originalEvent.pageX - offset.left;
var originY = ev.originalEvent.pageY - offset.top;
// Calculate current size of the image.
var width = dim.width * dim.new_scale;
var height = dim.height * dim.new_scale;
// Calculate the relative position of the mouse independent of current scale.
var mx = originX / width;
var my = originY / height;
// onScroll ev
dim.new_scale += (ev.originalEvent.deltaY > 0) ? -0.1 : 0.1;
if (dim.new_scale > dim.max_scale) dim.new_scale = dim.max_scale;
else if (dim.new_scale < 1) dim.new_scale = 1;
// Update new image position based upon new scale.
var new_width = dim.width * dim.new_scale;
var new_height = dim.height * dim.new_scale;
var new_mouse_x = new_width * mx;
var new_mouse_y = new_height * my;
dim.new_x += originX - new_mouse_x;
dim.new_y += originY - new_mouse_y;
transform();
});
});
var image_center=$(“#image”);
var base_image=$(“.outer”);
var dim={};
函数resetDim(){
//使用值初始化image.dim
dim.cont_width=base_image.width();//容器宽度
dim.cont_height=base_image.height();//容器高度
dim.width=image_center.width();//元素宽度
dim.height=image_center.height();//元素高度
尺寸左边缘=0;
dim.top_edge=0;//边转换
dim.init_x=0;
dim.new_x=0;//初始/新x位置
dim.init_y=0;
dim.new_y=0;//初始/新y位置
dim.init_scale=1;
dim.new_scale=1;//初始/新比例
dim.max_scale=3;//最大图像比例
};
函数变换(){
变量矩阵=[dim.new_scale,0,0,dim.new_scale,dim.new_x,dim.new_y]。连接(“,”;
image_center.css({
“变换”:“矩阵(“+matrix+”)translate3d(0,0,0)”,
“-webkit转换”:“矩阵(“+matrix+”)translate3d(0,0,0)”,
“-moz变换”:“矩阵(“+matrix+”)translate3d(0,0,0)”,
});
}
$(文档).ready(函数(){
resetDim();
transform();
$('.outer').bind('mousewheel',函数(ev){
//onScroll启动
//确定指针相对于图片的原点
var offset=image_center.offset();
var originX=ev.originalEvent.pageX-offset.left;
var originY=ev.originalEvent.pageY-offset.top;
//计算图像的当前大小。
变量宽度=尺寸宽度*尺寸新_刻度;
变量高度=尺寸高度*尺寸新刻度;
//计算鼠标的相对位置,与当前比例无关。
var mx=初始值/宽度;
var my=原始/高度;
//昂斯克罗尔电动汽车
dim.new_scale+=(ev.OriginaleEvent.deltaY>0)?-0.1:0.1;
如果(尺寸新刻度>尺寸最大刻度)尺寸新刻度=尺寸最大刻度;
否则,如果(尺寸新刻度<1)尺寸新刻度=1;
//根据新比例更新新图像位置。
var new_width=dim.width*dim.new_比例;
var新高度=尺寸高度*尺寸新高度刻度;
var new_mouse_x=new_width*mx;
var new_mouse_y=新高度*我的;
dim.new_x+=originX-new_mouse_x;
dim.new_y+=原始-新建鼠标;
transform();
});
});
您想做什么?JSFIDLE似乎在某些方面起作用。我不明白到底是什么不起作用?我更新了这个问题(希望)使我的问题更清楚。