Javascript 如何正确生成这些嵌套HTML列表的数据结构
假设我有如下HTML:Javascript 如何正确生成这些嵌套HTML列表的数据结构,javascript,html,algorithm,css-selectors,Javascript,Html,Algorithm,Css Selectors,假设我有如下HTML: <body> <div> <div> <div> <p> <b>Title A</b> <p> <table> <tbody> <tr> <td>Item 1:<
<body>
<div>
<div>
<div>
<p>
<b>Title A</b>
<p>
<table>
<tbody>
<tr>
<td>Item 1:</td>
</tr>
<tr>
<td>
<p><b>Content title 1.1</b></p>
<p>Content 1.1</p>
<p>Content 1.1b</p>
<p>Content 1.1c</p>
<p>Content 1.1d (arbitrary paragraph number follows content title)</p>
<p>Content ...</p>
<p><b>Content title 1.2</b></p>
<p>Content 1.2</p>
<p>Content 1.2b</p>
<p>Content 1.2...</p>
...
</td>
</tr>
<tr>
<td>Item 2:</td>
</tr>
<tr>
<td>
<p><b>Content title 2.1</b></p>
<p>Content 2.1</p>
<p><b>Content title 2.2</b></p>
<p>Content 2.2</p>
...
</td>
</tr>
...
</tbody>
</table>
<p>
<b>Title B</b>
<p>
<table>
<tbody>
<tr>
<td>Item 1b:</td>
</tr>
<tr>
<td>
<p><b>Content title 1b.1</b></p>
<p>Content 1b.1</p>
<p><b>Content title 1b.2</b></p>
<p>Content 1b.2</p>
...
</td>
</tr>
<tr>
<td>Item 2b:</td>
</tr>
<tr>
<td>
<p><b>Content title 2b.1</b></p>
<p>Content 2b.1</p>
<p><b>Content title 2b.2</b></p>
<p>Content 2b.2</p>
...
</td>
</tr>
...
</tbody>
</table>
...
var titles = document.querySelector(
'body > div > div > div > p > b'
)
var items = document.querySelector(
'body > div > div > div > table tr:nth-child(odd) td'
)
var itemContentTitles = document.querySelector(
'body > div > div > div > table tr:nth-child(even) p b'
)
// somehow select all children after the content title,
// up until the next content title or til
// there are no more elements.
var itemContents = document.querySelector(
'body > div > div > div > table tr:nth-child(even) p'
)
[
{
text: 'Title A',
items: [
{
text: 'Item 1',
items: [
{
text: 'Content title 1.1',
items: [
{ text: 'Content 1.1' },
{ text: 'Content 1.1b' },
{ text: 'Content 1.1c' },
{ text: 'Content 1.1d' }
...
]
},
{
text: 'Content title 1.2',
items: [
{ text: 'Content 1.2' },
{ text: 'Content 1.2b' },
{ text: 'Content 1.2...' }
...
]
}
]
},
{
text: 'Item 2',
items: [
{
text: 'Content title 2.1',
items: [
{ text: 'Content 2.1' }
...
]
},
{
text: 'Content title 2.2',
items: [
{ text: 'Content 2.2' }
...
]
}
]
}
]
},
{
text: 'Title B',
items: [
...
]
}
]
一旦这些数组中有了数据,主要问题是如何正确地将它们编织在一起。您希望的最终结果如下所示:
<body>
<div>
<div>
<div>
<p>
<b>Title A</b>
<p>
<table>
<tbody>
<tr>
<td>Item 1:</td>
</tr>
<tr>
<td>
<p><b>Content title 1.1</b></p>
<p>Content 1.1</p>
<p>Content 1.1b</p>
<p>Content 1.1c</p>
<p>Content 1.1d (arbitrary paragraph number follows content title)</p>
<p>Content ...</p>
<p><b>Content title 1.2</b></p>
<p>Content 1.2</p>
<p>Content 1.2b</p>
<p>Content 1.2...</p>
...
</td>
</tr>
<tr>
<td>Item 2:</td>
</tr>
<tr>
<td>
<p><b>Content title 2.1</b></p>
<p>Content 2.1</p>
<p><b>Content title 2.2</b></p>
<p>Content 2.2</p>
...
</td>
</tr>
...
</tbody>
</table>
<p>
<b>Title B</b>
<p>
<table>
<tbody>
<tr>
<td>Item 1b:</td>
</tr>
<tr>
<td>
<p><b>Content title 1b.1</b></p>
<p>Content 1b.1</p>
<p><b>Content title 1b.2</b></p>
<p>Content 1b.2</p>
...
</td>
</tr>
<tr>
<td>Item 2b:</td>
</tr>
<tr>
<td>
<p><b>Content title 2b.1</b></p>
<p>Content 2b.1</p>
<p><b>Content title 2b.2</b></p>
<p>Content 2b.2</p>
...
</td>
</tr>
...
</tbody>
</table>
...
var titles = document.querySelector(
'body > div > div > div > p > b'
)
var items = document.querySelector(
'body > div > div > div > table tr:nth-child(odd) td'
)
var itemContentTitles = document.querySelector(
'body > div > div > div > table tr:nth-child(even) p b'
)
// somehow select all children after the content title,
// up until the next content title or til
// there are no more elements.
var itemContents = document.querySelector(
'body > div > div > div > table tr:nth-child(even) p'
)
[
{
text: 'Title A',
items: [
{
text: 'Item 1',
items: [
{
text: 'Content title 1.1',
items: [
{ text: 'Content 1.1' },
{ text: 'Content 1.1b' },
{ text: 'Content 1.1c' },
{ text: 'Content 1.1d' }
...
]
},
{
text: 'Content title 1.2',
items: [
{ text: 'Content 1.2' },
{ text: 'Content 1.2b' },
{ text: 'Content 1.2...' }
...
]
}
]
},
{
text: 'Item 2',
items: [
{
text: 'Content title 2.1',
items: [
{ text: 'Content 2.1' }
...
]
},
{
text: 'Content title 2.2',
items: [
{ text: 'Content 2.2' }
...
]
}
]
}
]
},
{
text: 'Title B',
items: [
...
]
}
]
问题是,如何从使用一些基本CSS选择器选择的项目数组(因此不需要大量定制编程)过渡到这个嵌套的JSON数据结构
似乎您应该能够遍历每个列表中的每个项,然后检查它与父项的关系。当然,我们会指定哪个列表应该作为子列表应用于其他列表。因此,我们可以这样做:
function assignChildren(parents, children) {
}
然后做:
assignChildren(titles, items)
但我们可能实际上必须从下至上开始,并做到:
assignChildren(itemContentTitles, itemContents)
这里的棘手问题是如何解决知道哪个itemContents
项目属于哪个itemContentTitle
的问题。我们从HTML中知道它们之间的关系。基本上是这样的:
itemContent
.parentNode
.parentNode
.previousElementSibling
.firstElementChild
.firstElementChild
但问题是,我们如何才能通用地解决这个问题,这样就不需要编写自定义代码了。也就是说,您只需这样做:
assignChildren(itemContentTitles, itemContents)
…并获取嵌套的JSON结构。它似乎可以像这样工作:
<body>
<div>
<div>
<div>
<p>
<b>Title A</b>
<p>
<table>
<tbody>
<tr>
<td>Item 1:</td>
</tr>
<tr>
<td>
<p><b>Content title 1.1</b></p>
<p>Content 1.1</p>
<p>Content 1.1b</p>
<p>Content 1.1c</p>
<p>Content 1.1d (arbitrary paragraph number follows content title)</p>
<p>Content ...</p>
<p><b>Content title 1.2</b></p>
<p>Content 1.2</p>
<p>Content 1.2b</p>
<p>Content 1.2...</p>
...
</td>
</tr>
<tr>
<td>Item 2:</td>
</tr>
<tr>
<td>
<p><b>Content title 2.1</b></p>
<p>Content 2.1</p>
<p><b>Content title 2.2</b></p>
<p>Content 2.2</p>
...
</td>
</tr>
...
</tbody>
</table>
<p>
<b>Title B</b>
<p>
<table>
<tbody>
<tr>
<td>Item 1b:</td>
</tr>
<tr>
<td>
<p><b>Content title 1b.1</b></p>
<p>Content 1b.1</p>
<p><b>Content title 1b.2</b></p>
<p>Content 1b.2</p>
...
</td>
</tr>
<tr>
<td>Item 2b:</td>
</tr>
<tr>
<td>
<p><b>Content title 2b.1</b></p>
<p>Content 2b.1</p>
<p><b>Content title 2b.2</b></p>
<p>Content 2b.2</p>
...
</td>
</tr>
...
</tbody>
</table>
...
var titles = document.querySelector(
'body > div > div > div > p > b'
)
var items = document.querySelector(
'body > div > div > div > table tr:nth-child(odd) td'
)
var itemContentTitles = document.querySelector(
'body > div > div > div > table tr:nth-child(even) p b'
)
// somehow select all children after the content title,
// up until the next content title or til
// there are no more elements.
var itemContents = document.querySelector(
'body > div > div > div > table tr:nth-child(even) p'
)
[
{
text: 'Title A',
items: [
{
text: 'Item 1',
items: [
{
text: 'Content title 1.1',
items: [
{ text: 'Content 1.1' },
{ text: 'Content 1.1b' },
{ text: 'Content 1.1c' },
{ text: 'Content 1.1d' }
...
]
},
{
text: 'Content title 1.2',
items: [
{ text: 'Content 1.2' },
{ text: 'Content 1.2b' },
{ text: 'Content 1.2...' }
...
]
}
]
},
{
text: 'Item 2',
items: [
{
text: 'Content title 2.1',
items: [
{ text: 'Content 2.1' }
...
]
},
{
text: 'Content title 2.2',
items: [
{ text: 'Content 2.2' }
...
]
}
]
}
]
},
{
text: 'Title B',
items: [
...
]
}
]
从itemContents
元素(子列表项之一)开始。然后我们知道找到父项的父选择器。因此,以某种方式向上、向后和向下导航,以匹配该项的父选择器。这就是它开始变得棘手的地方,我很难看到如何在基本上不扫描整个DOM和检查每个项的完整生成的选择器路径的情况下完成它(诸如此类的事情)。想知道如何做到这一点。不一定要有超高的性能,但良好的性能总是一个加号
这样做的原因是,这样做只需要指定嵌套JSON结构不同部分的选择器,以及每个选择器与其父级的关系。在DOM中导航时,不必为每个选择器编写自定义代码
主要问题是在上述场景中,如何将孩子编织到父母身上