Javascript 从json obj中删除注意事项
这里我附加了json结果Javascript 从json obj中删除注意事项,javascript,string,Javascript,String,这里我附加了json结果 "properties": { "id": 99, "county": "Ashe", "cen_lat": 36.4343964583676, "cen_long": -81.5004915302458, "county_id": "5", "extent": "[-909946
"properties": {
"id": 99,
"county": "Ashe",
"cen_lat": 36.4343964583676,
"cen_long": -81.5004915302458,
"county_id": "5",
"extent": "[-9099469.85881319,4333729.96758589,-9044051.86962052,4381852.80674575]"
}
当我读取范围并得到结果时
“[-9099469.858813194333729.96758589,-9044051.869620524381852.80674575]”
但我需要
[-9099469.858813194333729.96758589,-9044051.869620524381852.80674575]
我怎样才能得到?如评论中所述
JSON.parse(“[-9099469.858813194333729.96758589,-9044051.869620524381852.80674575]”)代码>重新格式化问题。还有,这个大数字是什么?一个数字数组?它是一个数字数组吗?将代码放在两个反引号之间。它与1try JSON.parse旁边的tilde~键相同,然后用该键的结果重新发布问题。问题中可能重复没有提到jQuery。。。