Warning: file_get_contents(/data/phpspider/zhask/data//catemap/9/javascript/424.json): failed to open stream: No such file or directory in /data/phpspider/zhask/libs/function.php on line 167

Warning: Invalid argument supplied for foreach() in /data/phpspider/zhask/libs/tag.function.php on line 1116

Notice: Undefined index: in /data/phpspider/zhask/libs/function.php on line 180

Warning: array_chunk() expects parameter 1 to be array, null given in /data/phpspider/zhask/libs/function.php on line 181
Javascript 动态从外部站点加载js_Javascript - Fatal编程技术网

Javascript 动态从外部站点加载js

Javascript 动态从外部站点加载js,javascript,Javascript,当用户点击按钮时,我想从外部站点加载JS代码。例如: <button onclick="LoadJSFromURL('facebook.com/blablabla')" /> 当用户按下按钮时,我们会将新脚本附加到文档: <script> Share.WorkUrl="http://MySite.com"; Share.UserId=5 </script> <script src="http://Facebookcom/blabalbal" &g

当用户点击按钮时,我想从外部站点加载JS代码。例如:

 <button onclick="LoadJSFromURL('facebook.com/blablabla')" />

当用户按下按钮时,我们会将新脚本附加到文档:

<script> Share.WorkUrl="http://MySite.com"; Share.UserId=5 </script> <script src="http://Facebookcom/blabalbal" ></script>
Share.WorkUrl=”http://MySite.com"; Share.UserId=5
然后我们必须执行这个脚本。这是真的吗?

请检查:


这个解决方案是否依赖于原型?
var script = new Element("script", {src: "myBigCodeLibrary.js", type: "text/javascript"});

script.onload = script.onreadystatechange = function(){
    if (!this.readyState ||
        this.readyState == "loaded" || this.readyState == "complete") {
        //script is loaded
    }
};